
The magnetic induction in air at a distance d from an isolated point pole of strength $m$ unit will be
A. $\dfrac{m}{d}$
B. $\dfrac{m}{{{d}^{2}}}$
C. $md$
D. $md^2$
Answer
220.5k+ views
Hint: In this question we will use the concept magnetic induction of a bar magnet to get the magnetic induction in at a distance d from an isolated point pole of strength m unit.
Complete step by step solution:
In a bar magnet with N=north pole, S=south pole and O=centre. If a point is perpendicular to the bar magnet, in line with O, then that is the broad-side-on position for magnetic induction. If a point is on the extended axis of the bar magnet, in line with N and S, then that is the end-on position for magnetic induction.
For a single point having strength m, all the positions are end-on. At end-on position,
$B=K\times \dfrac{m}{{{r}^{2}}}$
where, K=constant, B=magnetic induction, m = pole strength and r=distance
Therefore, the magnetic induction in air at a distance d from an isolated point pole of strength m unit will be $\dfrac{m}{{{d}^{2}}}$.
Hence, the correct answer is B.
Additional Information: Magnetic induction is the process through which a regular piece of iron briefly gains magnetic properties as a result of the presence of another magnet nearby. A current is created by voltage production (also known as electromotive force) as a result of a shifting magnetic field. This can occur when a conductor is put in a magnetic field that is moving (when utilising an AC power source) or when a conductor is continuously moving in a magnetic field that is stationary.
Note: For a single point, there can never be a broad-side-on position since there is no perpendicular of a point. All the points at a distance of the point with strength m will always be an end-on position because we can assume that the point taken is on the x/y/z axis.
Complete step by step solution:
In a bar magnet with N=north pole, S=south pole and O=centre. If a point is perpendicular to the bar magnet, in line with O, then that is the broad-side-on position for magnetic induction. If a point is on the extended axis of the bar magnet, in line with N and S, then that is the end-on position for magnetic induction.
For a single point having strength m, all the positions are end-on. At end-on position,
$B=K\times \dfrac{m}{{{r}^{2}}}$
where, K=constant, B=magnetic induction, m = pole strength and r=distance
Therefore, the magnetic induction in air at a distance d from an isolated point pole of strength m unit will be $\dfrac{m}{{{d}^{2}}}$.
Hence, the correct answer is B.
Additional Information: Magnetic induction is the process through which a regular piece of iron briefly gains magnetic properties as a result of the presence of another magnet nearby. A current is created by voltage production (also known as electromotive force) as a result of a shifting magnetic field. This can occur when a conductor is put in a magnetic field that is moving (when utilising an AC power source) or when a conductor is continuously moving in a magnetic field that is stationary.
Note: For a single point, there can never be a broad-side-on position since there is no perpendicular of a point. All the points at a distance of the point with strength m will always be an end-on position because we can assume that the point taken is on the x/y/z axis.
Recently Updated Pages
[Awaiting input: Please provide the content from "Ask AI Response," "Competitor 1," and "Competitor 2," so I can perform the analysis and synthesize the requested metadata and headings.]

Young’s Double Slit Experiment Derivation Explained

A square frame of side 10 cm and a long straight wire class 12 physics JEE_Main

The work done in slowly moving an electron of charge class 12 physics JEE_Main

Two identical charged spheres suspended from a common class 12 physics JEE_Main

According to Bohrs theory the timeaveraged magnetic class 12 physics JEE_Main

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Understanding Uniform Acceleration in Physics

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Dual Nature of Radiation and Matter Class 12 Physics Chapter 11 CBSE Notes - 2025-26

Degree of Dissociation: Meaning, Formula, Calculation & Uses

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

Understanding the Electric Field of a Uniformly Charged Ring

Understanding Electromagnetic Waves and Their Importance

