
The general formula ${{(RCO)}_{2}}O$ represents
A.An ester [CPMT $1974$; DPMT $1982$; MP PMT 1996]
B.A ketone
C.An aldehyde
D.An acid anhydride
Answer
225.6k+ views
Hint: In organic compounds the most reactive part is its functional group. There are lots of functional groups in organic chemistry. Here in this question, the given compound contains two $-CO$groups and they are connected through an oxygen atom. Therefore to recognize the function group of this compound we must have to draw the compound.
Complete answer:Generally, a functional group represents the general grouping of atoms within the molecules and that has a unique set of chemical properties. The most common examples of the functional groups are alkenes, alkynes, alcohols, ethers, amines, aldehydes, ketones, carboxylic acids, esters, anhydrides, etc
We can draw the structure of the compound ${{(RCO)}_{2}}O$ in the following way:

Let us check all the options to find a similar to the functional group present ${{(RCO)}_{2}}O$.
Esters are the carboxylic acid derivative compound and can be derived from an acid in which at least one hydroxyl group, $-OH$group is replaced by an alkyl alkoxy group, $-0R$. A common structure of ester is shown below which $-R$denotes the alkyl or aryl group.

So, the given compound is not an ester.
Aldehyde and ketones are carbonyl compounds containing carbonyl functional groups, $C=O$ . In aldehyde, at least one hydrogen atom is connected to the $C=O$group but in ketone carbonyl groups are attached to two alkyl or aryl groups. Acetaldehyde and acetone are examples of aldehyde and ketone.

Thus, the compound ${{(RCO)}_{2}}O$ is not an aldehyde or ketone.
Finally, acid anhydride falls under the carboxylic derivative category. When two carboxylic acid groups react, acid anhydride forms by the loss of one water molecule. For example, if we combine two common carboxylic acids of chemical formula $RCOOH$where $R-$denotes an alkyl or aryl group we get an acid anhydride having the formula,${{(RCO)}_{2}}O$.

Therefore the formula ${{(RCO)}_{2}}O$ represents an acid anhydride.
Thus, option (D) is correct.
Note: To deal with any problem in chemistry, especially in organic chemistry we need to learn how to recognize certain patterns in molecular structures and reactions. One of the most important of those basic patterns is the recognition of functional groups. By learning this we will reach one step closer to identifying possible reactions.
Complete answer:Generally, a functional group represents the general grouping of atoms within the molecules and that has a unique set of chemical properties. The most common examples of the functional groups are alkenes, alkynes, alcohols, ethers, amines, aldehydes, ketones, carboxylic acids, esters, anhydrides, etc
We can draw the structure of the compound ${{(RCO)}_{2}}O$ in the following way:

Let us check all the options to find a similar to the functional group present ${{(RCO)}_{2}}O$.
Esters are the carboxylic acid derivative compound and can be derived from an acid in which at least one hydroxyl group, $-OH$group is replaced by an alkyl alkoxy group, $-0R$. A common structure of ester is shown below which $-R$denotes the alkyl or aryl group.

So, the given compound is not an ester.
Aldehyde and ketones are carbonyl compounds containing carbonyl functional groups, $C=O$ . In aldehyde, at least one hydrogen atom is connected to the $C=O$group but in ketone carbonyl groups are attached to two alkyl or aryl groups. Acetaldehyde and acetone are examples of aldehyde and ketone.

Thus, the compound ${{(RCO)}_{2}}O$ is not an aldehyde or ketone.
Finally, acid anhydride falls under the carboxylic derivative category. When two carboxylic acid groups react, acid anhydride forms by the loss of one water molecule. For example, if we combine two common carboxylic acids of chemical formula $RCOOH$where $R-$denotes an alkyl or aryl group we get an acid anhydride having the formula,${{(RCO)}_{2}}O$.

Therefore the formula ${{(RCO)}_{2}}O$ represents an acid anhydride.
Thus, option (D) is correct.
Note: To deal with any problem in chemistry, especially in organic chemistry we need to learn how to recognize certain patterns in molecular structures and reactions. One of the most important of those basic patterns is the recognition of functional groups. By learning this we will reach one step closer to identifying possible reactions.
Recently Updated Pages
JEE Main 2025-26 Mock Test: Organic Compounds Containing Nitrogen

JEE Main 2025-26 Organic Compounds Containing Nitrogen Mock Test

JEE Main Chemical Kinetics Mock Test 2025-26: Free Practice Online

JEE Main 2025-26 Organic Compounds Containing Oxygen Mock Test

JEE Main 2025-26 Organic Compounds Containing Halogens Mock Test

Sodium acetate on heating with soda lime produce A class 12 chemistry JEE_Main

Trending doubts
JEE Main 2026: City Intimation Slip and Exam Dates Released, Application Form Closed, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

Other Pages
NCERT Solutions For Class 12 Chemistry Chapter 1 Solutions - 2025-26

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Solutions Class 12 Chemistry Chapter 1 CBSE Notes - 2025-26

NCERT Solutions ForClass 12 Chemistry Chapter Chapter 4 The D and F Block Elements

Biomolecules Class 12 Chemistry Chapter 10 CBSE Notes - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 10 Biomolecules - 2025-26

