
The amount of NaOH in gms in 250cm3 of a 0.100M NaOH solution would be
A . 4 gm
B . 2 gm
C . 1 gm
D . 2.5 gm
Answer
164.7k+ views
Hint: In this question we have to use the concept of molarity and find out the grams of solute present in the given volume of 0.1M concentration. We must first calculate the amount of moles by dividing the weight of compound NaOH by its molecular weight. With this knowledge, the molarity of the solution in moles per litre volume can subsequently be calculated.
Complete answer:Moles per litre of a solution, also known as moles per litre of a solution, is a measure of a solution's molar concentration or molarity. It is one of the concentration units that are most frequently used, and the letter M stands in for it.
The formula for it is:
$Molarity=\dfrac{moles\text{ }of\text{ }solute}{volume\text{ }of\text{ }solution\text{ }in\text{ }litres}$
The SI unit for molarity is mol/L.
In the given question, the solute is NaOH.
Molar mass of NaOH = molar mass of Na + molar mass of O + molar mass of H = 23+16+1 = 40g/mol
$Molarity=\dfrac{moles\text{ }of\text{ }solute}{volume\text{ }of\text{ }solution\text{ }in\text{ }litres}$
$0.1=\dfrac{{{w}_{NaOH}}\times 4}{40\times 1}=1gm$
Therefore, the weight of NaOH is 1gm
The correct answer is C.
Note: Molality, normality, and molarity may all be used interchangeably. Molality is denoted by the letter "m," as opposed to molarity, which is symbolized by the letter "M." The number of moles of solute per kilogram of solvent is used to determine the molality of any solution. It may be stated as follows:
$Molality=\dfrac{moles\text{ }per\text{ }solute\left( mol \right)}{weight\text{ }of\text{ }solvent\text{ }in\text{ }kg}$
It has the SI unit mol/kg.
The term "normality" refers to the quantity of solute in a solution measured in grams or moles per litre. It is commonly referred to as a solution's equivalent concentration and is denoted by the letter "N". N or equivalents/Litre serve as the units of normality.
Complete answer:Moles per litre of a solution, also known as moles per litre of a solution, is a measure of a solution's molar concentration or molarity. It is one of the concentration units that are most frequently used, and the letter M stands in for it.
The formula for it is:
$Molarity=\dfrac{moles\text{ }of\text{ }solute}{volume\text{ }of\text{ }solution\text{ }in\text{ }litres}$
The SI unit for molarity is mol/L.
In the given question, the solute is NaOH.
Molar mass of NaOH = molar mass of Na + molar mass of O + molar mass of H = 23+16+1 = 40g/mol
$Molarity=\dfrac{moles\text{ }of\text{ }solute}{volume\text{ }of\text{ }solution\text{ }in\text{ }litres}$
$0.1=\dfrac{{{w}_{NaOH}}\times 4}{40\times 1}=1gm$
Therefore, the weight of NaOH is 1gm
The correct answer is C.
Note: Molality, normality, and molarity may all be used interchangeably. Molality is denoted by the letter "m," as opposed to molarity, which is symbolized by the letter "M." The number of moles of solute per kilogram of solvent is used to determine the molality of any solution. It may be stated as follows:
$Molality=\dfrac{moles\text{ }per\text{ }solute\left( mol \right)}{weight\text{ }of\text{ }solvent\text{ }in\text{ }kg}$
It has the SI unit mol/kg.
The term "normality" refers to the quantity of solute in a solution measured in grams or moles per litre. It is commonly referred to as a solution's equivalent concentration and is denoted by the letter "N". N or equivalents/Litre serve as the units of normality.
Recently Updated Pages
Hess Law of Constant Heat Summation: Definition, Formula & Applications

Disproportionation Reaction: Definition, Example & JEE Guide

Environmental Chemistry Chapter for JEE Main Chemistry

JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

Get P Block Elements for JEE Main 2025 with clear Explanations

Trending doubts
Atomic Structure - Electrons, Protons, Neutrons and Atomic Models

Types of Solutions

Instantaneous Velocity - Formula based Examples for JEE

JEE Main Chemistry Question Paper with Answer Keys and Solutions

NIT Raipur Cut-off of Previous Years and Expected for 2025

JEE Main Cut-Off for NIT Kurukshetra: All Important Details

Other Pages
JEE Advanced 2025 Notes

Redox reaction Class 11 Notes: CBSE Chapter 7

Total MBBS Seats in India 2025: Government College Seat Matrix

NEET Total Marks 2025: Important Information and Key Updates

Neet Cut Off 2025 for MBBS in Tamilnadu: AIQ & State Quota Analysis

Karnataka NEET Cut off 2025 - Category Wise Cut Off Marks
