Question

The amine formed from an amide by means of bromine and alkali has
(A) Same number of C atoms as that of amide
(B) One less C atom that of amide
(C) One more C atom than that of amide
(D) Two more C atom than that of amide

Answer 1

Hint: In this question we have to solve that when amide is reacted in presence of bromine and alkali then as in product as comparison to amide how many carbon atom is present in the amine form as many options are there as from which we can easily find by writing a reaction on the basis of amine and amide we get the solution.

Complete Step by Step Solution:
By getting reaction of Amide in the presence of bromine and alkali we get the following reaction as:
$C{H_3} - CO - N{H_2}\xrightarrow[{NaOH}]{{B{r_2}}}C{H_3} - N{H_2}$
As we get all the details from the above reaction we get to know that when $C{H_3} - CO - N{H_2}$ an Amide is reaction in the presence of Bromine and sodium hydroxide which is a alkali we get the result in the reactant side in amide there are two carbon atom in that side but after completion of reaction in the product state there are only one carbon atom is present in amine form.
Now in the above conclusion we get that when amide is reacted by the means of bromine and alkali one less C atom is found as compared to the amide.
Therefore, the answer is as in amine one less C atom than that of amide.
Hence, the correct option is (B).

Note: There are many methods are there from which Amines are prepared in which the major ones are from Reduction of Amides which is also used in this question whereas, by using ammonolysis of Alkyl Halides method amine is prepared. These are the some major methods from which we can prepare amines easily.