
Shape of \[B{F_3}\] molecule is.
(a) Linear
(b) Planar
(c) Tetrahedral
(d) Square pyramidal
Answer
163.5k+ views
Hint: Sulfur trioxide (\[S{O_3}\] ) has trigonal planar geometry, i.e., one sulfur atom is surrounded by three oxygen atoms. The three oxygen atoms occupy the equatorial position and possess \[120^\circ \] bond angle.
Complete step by step solution:For the determination of molecular geometry, the concept of hybridization can be used.
The process of hybridization involves the mixing of atomic orbitals to generate new orbitals, i.e., hybrid orbitals.
Based on the type of mixing of atomic orbitals, hybridization can be \[sp,s{p^2},s{p^3},s{p^3}d,s{p^3}{d^2}\] and \[s{p^3}{d^3}\] .
The \[B{F_3}\]is called boron difluoride.
The \[B{F_3}\] has \[s{p^2}\]type of hybridization.
In \[B{F_3}\]molecules, three \[s{p^2}\]hybrid orbitals of boron overlap with the p-orbital of three fluorine atoms, and as a result, three sigma bonds are formed.
Due to \[s{p^2}\]hybridization, the \[B{F_3}\]molecule has trigonal planar geometry and shape with \[120^\circ \] bond angle.
Due to electron-deficient nature, the \[B{F_3}\]molecule is considered as an electrophile i.e., electron loving species.
Therefore from the above explanation we can say option (b) will be the correct option
Note: he \[B{F_3}\]molecule exists in colourless gaseous form at room temperature.
The \[B{F_3}\]has a toxic nature, and in the presence of moisture it forms white fumes.
Because the \[B{F_3}\] has symmetric structure (trigonal planar geometry) therefore it is considered as non-polar in nature.
The \[B{F_3}\]has various applications, in different fields, such as in the reaction of epoxy resins, polymerization, isomerization, alkylation esterification, and in condensation reaction.
The \[B{F_3}\] can also be used in soldering, brazing and production of other boron derivatives.
Complete step by step solution:For the determination of molecular geometry, the concept of hybridization can be used.
The process of hybridization involves the mixing of atomic orbitals to generate new orbitals, i.e., hybrid orbitals.
Based on the type of mixing of atomic orbitals, hybridization can be \[sp,s{p^2},s{p^3},s{p^3}d,s{p^3}{d^2}\] and \[s{p^3}{d^3}\] .
The \[B{F_3}\]is called boron difluoride.
The \[B{F_3}\] has \[s{p^2}\]type of hybridization.
In \[B{F_3}\]molecules, three \[s{p^2}\]hybrid orbitals of boron overlap with the p-orbital of three fluorine atoms, and as a result, three sigma bonds are formed.
Due to \[s{p^2}\]hybridization, the \[B{F_3}\]molecule has trigonal planar geometry and shape with \[120^\circ \] bond angle.
Due to electron-deficient nature, the \[B{F_3}\]molecule is considered as an electrophile i.e., electron loving species.
Therefore from the above explanation we can say option (b) will be the correct option
Note: he \[B{F_3}\]molecule exists in colourless gaseous form at room temperature.
The \[B{F_3}\]has a toxic nature, and in the presence of moisture it forms white fumes.
Because the \[B{F_3}\] has symmetric structure (trigonal planar geometry) therefore it is considered as non-polar in nature.
The \[B{F_3}\]has various applications, in different fields, such as in the reaction of epoxy resins, polymerization, isomerization, alkylation esterification, and in condensation reaction.
The \[B{F_3}\] can also be used in soldering, brazing and production of other boron derivatives.
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