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\[R - CH = CH - CHO + N{H_2} - CO - NH - N{H_2}\xrightarrow{{{H^ + }}}\]
(X) is the above reaction is:

Answer
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Hint: As we see in the above reaction that there are a group of reactants are given and the reaction is going to be done in the presence of hydrogen atom from which we know that this is going to be reduction reaction and we have to find the product of the reaction by using above reactants.

Complete Step by Step Solution:
We know that this question is a part of the chemical reaction made between aldehydes and ketones. Here in the above equation we have to find the product which is going to be done as we see the whole reaction below:
\[R - CH = CH - CHO + N{H_2} - CO - NH - N{H_2}\xrightarrow{{{H^ + }}}R - CH = CH - CH = N - CO - NH - N{H_2}\]

As we get the result in the above reaction, When we react the given whole reaction as in the presence of Hydrogen atom we get the above product as after the whole reaction takes place.

Although, ${H_2}O$ make a bond as per the above reaction, get out from the solution made as in the product.
As from taking the whole conclusion we get that, after completing the whole reaction we get the X as a result which is given in the product form of the reaction.
Hence, the correct answer of X is \[R - CH = CH - CH = N - CO - NH - N{H_2}\] .

Note: Now we are going to know what Aldehyde and Ketone are and what is the difference between them. As per talking about aldehyde it is present in the form of $R - CHO$ and occurs at the end of the carbon chain. Whereas, Ketone is present in the form of $R - CO - R'$ and occurs at the middle position of the carbon chain.