
Magnification of a concave lens is-
(A) $ > 0$ and $ < 1$
(B) $ > 1$ or $ < - 1$
(C) $ > - 1$ and $ < 1$
(D) Insufficient information
Answer
137.1k+ views
Hint Magnification is defined as the ratio between the size of an image compared with the original size of the object. Magnification is also determined by the ratio of the distance of the image from the pole to the distance of the object to the pole.
Complete Step by step solution
Magnification of an object consists of two parts which tell about the nature of an image-
The sign of the magnification tells if the image formed is inverted or upright. A real image is inverted in nature, so a negative sign is used to represent a real and inverted image. A virtual image on the other hand is upright, thus it is represented by a positive sign of magnification.
The magnitude of the magnification represents the ratio of the size of the image with respect to the size of the actual object. If this value is less than one, it signifies that the image is smaller in size than the actual object or diminished, it also tells that the distance of the image formed from the pole of the lens is less than the distance between the lens and the object. If this value is more than one, it represents a larger image than the original object or enlarged image. If the magnitude is equal to one, it represents the same sized image and object.
A concave lens is also known as a diverging lens. It diverges a beam of rays directed towards it. The rays never meet in reality but the diverged rays can be traced backward to create a virtual image.
The virtual images are upright, thus the sign of the magnification caused by a concave lens would be positive.
A concave lens always forms a diminished image of the object, thus the value of magnification produced by it ranges from $0$ to $1$.
Therefore the magnification produced by a concave mirror is, $ > 0$ and $ < 1$.
Option (A) is correct.
Note A concave lens always produces diminished, virtual and upright images. A convex lens on the other hand can produce a variety of images based on the distance between the object and the optical center of the lens.
Complete Step by step solution
Magnification of an object consists of two parts which tell about the nature of an image-
The sign of the magnification tells if the image formed is inverted or upright. A real image is inverted in nature, so a negative sign is used to represent a real and inverted image. A virtual image on the other hand is upright, thus it is represented by a positive sign of magnification.
The magnitude of the magnification represents the ratio of the size of the image with respect to the size of the actual object. If this value is less than one, it signifies that the image is smaller in size than the actual object or diminished, it also tells that the distance of the image formed from the pole of the lens is less than the distance between the lens and the object. If this value is more than one, it represents a larger image than the original object or enlarged image. If the magnitude is equal to one, it represents the same sized image and object.
A concave lens is also known as a diverging lens. It diverges a beam of rays directed towards it. The rays never meet in reality but the diverged rays can be traced backward to create a virtual image.
The virtual images are upright, thus the sign of the magnification caused by a concave lens would be positive.
A concave lens always forms a diminished image of the object, thus the value of magnification produced by it ranges from $0$ to $1$.
Therefore the magnification produced by a concave mirror is, $ > 0$ and $ < 1$.
Option (A) is correct.
Note A concave lens always produces diminished, virtual and upright images. A convex lens on the other hand can produce a variety of images based on the distance between the object and the optical center of the lens.
Recently Updated Pages
COM of Semicircular Ring Important Concepts and Tips for JEE

Geostationary Satellites and Geosynchronous Satellites for JEE

Current Loop as Magnetic Dipole Important Concepts for JEE

Electromagnetic Waves Chapter for JEE Main Physics

Structure of Atom: Key Models, Subatomic Particles, and Quantum Numbers

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Learn About Angle Of Deviation In Prism: JEE Main Physics 2025

Degree of Dissociation and Its Formula With Solved Example for JEE

Physics Average Value and RMS Value JEE Main 2025

Formula for number of images formed by two plane mirrors class 12 physics JEE_Main

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Dual Nature of Radiation and Matter Class 12 Notes: CBSE Physics Chapter 11

Electric field due to uniformly charged sphere class 12 physics JEE_Main

Collision - Important Concepts and Tips for JEE

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Charging and Discharging of Capacitor
