
Laws of electrolysis are given by:
A) Faraday
B) Maxwell
C) Lenz
D) Bohr
Answer
232.8k+ views
Hint: In these kinds of situations the first thing important is to notice the given problem statement. Specially this is a straight away question. It is simply easy to interpret that Faraday would be the answer as he is known as the ‘Father of Electricity’.
Complete step by step solution:
Faraday's laws of electrolysis, in chemistry, quantitative laws used to express magnitudes of electrolytic effects, first described by the English scientist Michael Faraday in 1833.
There are two laws of electrolysis:
First Law: The first law given by Faraday is regarding the proportionality of the mass and charge. The law reports that the mass of any element which is deposited at an electrode g is directly proportional to the charge on the Coulombs.
$
m \propto Q \\
Q = Ampere \times seconds \\
$
Therefore,
$
\dfrac{m}{Q} = Z \\
\\
$
Here $Z$ is called the Electro-Chemical Equivalent.
Second Law: The Second law given by Faraday is regarding the proportionality of elements deposited at the electrode when connected in series. The law reports that the mass of any element which is deposited at an electrode g is directly proportional to their Chemical Equivalent Weight.
$
m \propto E \\
E = \dfrac{{molar{\text{ }}mass}}{{Valence}} \\
$
Note:Most important thing here is to notice the given options and then we can easily emulate the right answer even if we are unaware of it. Apart from that it is clear that this is a question of fact and is clearly based on the memory.
Complete step by step solution:
Faraday's laws of electrolysis, in chemistry, quantitative laws used to express magnitudes of electrolytic effects, first described by the English scientist Michael Faraday in 1833.
There are two laws of electrolysis:
First Law: The first law given by Faraday is regarding the proportionality of the mass and charge. The law reports that the mass of any element which is deposited at an electrode g is directly proportional to the charge on the Coulombs.
$
m \propto Q \\
Q = Ampere \times seconds \\
$
Therefore,
$
\dfrac{m}{Q} = Z \\
\\
$
Here $Z$ is called the Electro-Chemical Equivalent.
Second Law: The Second law given by Faraday is regarding the proportionality of elements deposited at the electrode when connected in series. The law reports that the mass of any element which is deposited at an electrode g is directly proportional to their Chemical Equivalent Weight.
$
m \propto E \\
E = \dfrac{{molar{\text{ }}mass}}{{Valence}} \\
$
Note:Most important thing here is to notice the given options and then we can easily emulate the right answer even if we are unaware of it. Apart from that it is clear that this is a question of fact and is clearly based on the memory.
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