
In order to prepare a buffer solution of pH 5.74, sodium acetate is added to acetic acid. If the concentration of acetic acid in the buffer is 1.0 M, the concentration of sodium acetate in the buffer is? (Round off to the nearest integer). [Given: \[p{k_a}\] (acetic acid) = 4.74]
Answer
219k+ views
Hint: Here, we have to apply the formula of pH in terms of logarithm after putting the values given to us in the question. Then, we will make the appropriate substitution and then take the antilog of it. Finally we will calculate the ratio of the salt and the concentration of both the acid and salt will be calculated.
Complete Step by Step Solution:
pH, or potential of hydrogen, is a metric for determining the acidity or basicity of aqueous or other liquid solutions. The term which is widely used in chemistry, refers to the values of the concentration of the hydrogen ion which ordinarily ranges between about 1 and 10−14 gram equivalents per litre in amounts ranging from 0 to 14. In pure water, it is neutral which is neither acidic nor basic. The concentration of the hydrogen ion is 10 −7 gram equivalents per litre, which is equal to a pH of 7. A solution with pH less than 7 is regarded as acidic. A solution with a pH greater than 7 is considered to be alkaline.
Formula for calculating the pH;
pH = − log \[{k_a}\] + log \[([\dfrac{{salt}}{{acid}}])\]
As the value of pH and \[{k_a}\] are already given in question, so putting these values in the given formula:
5.74 = − 4.74 + log \[([\dfrac{{salt}}{{acid}}])\]
From the logarithmic property [a log b = log \[{b^a}\] ]
5.74 = 4.74 + log \[([\dfrac{{salt}}{{acid}}])\]
Further solving,
1 = log \[([\dfrac{{salt}}{{acid}}])\]
Taking antilog on both sides, we get:
10/1 = [salt][acid]101= \[([\dfrac{{salt}}{{acid}}])\]
Hence, The ratio of salt to the acid will be 10:1.
Note: A pH metre is used to determine the pH, which transforms the difference in electromotive force into pH measurements. It is also called electrical potential or voltage between electrodes placed in the solution to be tested. Fundamentally, a pH metre consists of a voltmeter attached to a pH responsive electrode and a reference constant electrode and the readings are reflected in a digital screen.
Complete Step by Step Solution:
pH, or potential of hydrogen, is a metric for determining the acidity or basicity of aqueous or other liquid solutions. The term which is widely used in chemistry, refers to the values of the concentration of the hydrogen ion which ordinarily ranges between about 1 and 10−14 gram equivalents per litre in amounts ranging from 0 to 14. In pure water, it is neutral which is neither acidic nor basic. The concentration of the hydrogen ion is 10 −7 gram equivalents per litre, which is equal to a pH of 7. A solution with pH less than 7 is regarded as acidic. A solution with a pH greater than 7 is considered to be alkaline.
Formula for calculating the pH;
pH = − log \[{k_a}\] + log \[([\dfrac{{salt}}{{acid}}])\]
As the value of pH and \[{k_a}\] are already given in question, so putting these values in the given formula:
5.74 = − 4.74 + log \[([\dfrac{{salt}}{{acid}}])\]
From the logarithmic property [a log b = log \[{b^a}\] ]
5.74 = 4.74 + log \[([\dfrac{{salt}}{{acid}}])\]
Further solving,
1 = log \[([\dfrac{{salt}}{{acid}}])\]
Taking antilog on both sides, we get:
10/1 = [salt][acid]101= \[([\dfrac{{salt}}{{acid}}])\]
Hence, The ratio of salt to the acid will be 10:1.
Note: A pH metre is used to determine the pH, which transforms the difference in electromotive force into pH measurements. It is also called electrical potential or voltage between electrodes placed in the solution to be tested. Fundamentally, a pH metre consists of a voltmeter attached to a pH responsive electrode and a reference constant electrode and the readings are reflected in a digital screen.
Recently Updated Pages
The hybridization and shape of NH2 ion are a sp2 and class 11 chemistry JEE_Main

What is the pH of 001 M solution of HCl a 1 b 10 c class 11 chemistry JEE_Main

Aromatization of nhexane gives A Benzene B Toluene class 11 chemistry JEE_Main

Show how you will synthesise i 1Phenylethanol from class 11 chemistry JEE_Main

The enolic form of acetone contains a 10sigma bonds class 11 chemistry JEE_Main

Which of the following Compounds does not exhibit tautomerism class 11 chemistry JEE_Main

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

Understanding Atomic Structure for Beginners

Other Pages
NCERT Solutions For Class 11 Chemistry Chapter 7 Redox Reaction

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Thermodynamics Class 11 Chemistry Chapter 5 CBSE Notes - 2025-26

NCERT Solutions ForClass 11 Chemistry Chapter Chapter 5 Thermodynamics

Equilibrium Class 11 Chemistry Chapter 6 CBSE Notes - 2025-26

How to Convert a Galvanometer into an Ammeter or Voltmeter

