
In Millikan’s oil drop experiment, we make use of:
(A) Ohm’s law
(B) Ampere’s law
(C) Stokes law
(D) Faraday’s law
Answer
151.8k+ views
Hint: Robert Millikan in 1909 performed an experiment to determine the charge on an electron. For his work he received a Nobel Prize. The name of the experiment is Oil drop experiment. In the oil drop experiment Robert Millikan used charged oil droplets to determine the charge on the electron.
Complete step by step answer:
* To find the weight of the oil drop, Millikan allowed the oil drop to fall through the air in the oil drop experiment.
* Oil drop quickly reaches its terminal velocity and at this point, the weight of the drop is being balanced by the viscous effort of the air.
* The effort of the air can be calculated by using Stokes' Law, which endorsed Millikan to determine the weight of the drop.
Therefore Millikan used Stokes law in the oil drop experiment.
So, the correct option is C.
Additional information:
* Stokes law: The force that hinders a sphere while it moving via a viscous fluid is directly proportional to the velocity, the radius of the sphere and the viscosity of the particular fluid is called stokes law.
* Stokes law is used to calculate the viscosity of the given fluid.
Stokes law explains the following:
a) Floating of clouds
b) Bigger raindrops hurt us more than the smaller rain drops.
c) A man moving towards the earth with the parachute gains constant terminal velocity.
Note: Don’t be confused with the relation between viscosity and velocity. As the viscosity of the fluid increases the velocity to travel through the air decreases. Viscosity and velocity are inversely proportional to each other.
Complete step by step answer:
* To find the weight of the oil drop, Millikan allowed the oil drop to fall through the air in the oil drop experiment.
* Oil drop quickly reaches its terminal velocity and at this point, the weight of the drop is being balanced by the viscous effort of the air.
* The effort of the air can be calculated by using Stokes' Law, which endorsed Millikan to determine the weight of the drop.
Therefore Millikan used Stokes law in the oil drop experiment.
So, the correct option is C.
Additional information:
* Stokes law: The force that hinders a sphere while it moving via a viscous fluid is directly proportional to the velocity, the radius of the sphere and the viscosity of the particular fluid is called stokes law.
* Stokes law is used to calculate the viscosity of the given fluid.
Stokes law explains the following:
a) Floating of clouds
b) Bigger raindrops hurt us more than the smaller rain drops.
c) A man moving towards the earth with the parachute gains constant terminal velocity.
Note: Don’t be confused with the relation between viscosity and velocity. As the viscosity of the fluid increases the velocity to travel through the air decreases. Viscosity and velocity are inversely proportional to each other.
Recently Updated Pages
JEE Main 2022 (June 29th Shift 2) Maths Question Paper with Answer Key

JEE Main 2023 (January 25th Shift 1) Maths Question Paper with Answer Key

JEE Main 2022 (July 29th Shift 1) Maths Question Paper with Answer Key

JEE Main 2022 (July 26th Shift 2) Chemistry Question Paper with Answer Key

JEE Main 2022 (June 26th Shift 2) Maths Question Paper with Answer Key

JEE Main 2022 (June 29th Shift 1) Physics Question Paper with Answer Key

Trending doubts
JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics

Electrical Field of Charged Spherical Shell - JEE

Learn About Angle Of Deviation In Prism: JEE Main Physics 2025

Displacement-Time Graph and Velocity-Time Graph for JEE

Number of sigma and pi bonds in C2 molecule isare A class 11 chemistry JEE_Main

Collision - Important Concepts and Tips for JEE

Other Pages
JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

Thermodynamics Class 11 Notes: CBSE Chapter 5

Brief Information on Alpha, Beta and Gamma Decay - JEE Important Topic

Compressibility Factor Z | Plot of Compressibility Factor Z Vs Pressure for JEE

The reaction of P4 with X leads selectively to P4O6 class 11 chemistry JEE_Main

NCERT Solutions for Class 11 Chemistry Chapter 7 Redox Reaction
