
If \[x = \sqrt {\dfrac{{2 + \sqrt 3 }}{{2 - \sqrt 3 }}} \] then calculate the value of \[{x^2}{(x - 4)^2} \] .
A. 7
B. 4
C. 2
D. 1
Answer
218.4k+ views
Hint: We will rationalize the given term. The conjugate surd of \[2 - \sqrt 3 \] is \[2 + \sqrt 3 \]. After that we will put the value of in the given expression.
Formula used: If we have a surd \[a + \sqrt b \] then its conjugate surd is \[a - \sqrt b \] and also vice-versa. I we have a fraction \[\dfrac{{c + \sqrt d }}{{a - \sqrt b }}\] then we always do rationalize and to rationalize this type of fraction we use the technique \[\dfrac{{(c + \sqrt d )(a + \sqrt {b)} }}{{(a - \sqrt b )(a + \sqrt {b)} }} = \dfrac{{(c + \sqrt d )(a + \sqrt {b)} }}{{{a^2} - b}}\] multiplying denominator and numerator by the conjugate surd of the denominator part to denominator as rational free term.
\[(a + b)(a - b) = {a^2} - {b^2}\].
Complete step-by-step solution:
We will rationalize the given term. The conjugate surd of \[2 - \sqrt 3 \] is \[2 + \sqrt 3 \].
We have
\[x = \sqrt {\dfrac{{2 + \sqrt 3 }}{{2 - \sqrt 3 }}} \]
or, \[x = \sqrt {\dfrac{{(2 + \sqrt 3 )(2 + \sqrt 3 )}}{{(2 - \sqrt 3 )(2 + \sqrt 3 )}}} \] [Rationalizing by multiplication of \[2 + \sqrt 3 \] with numerator and denominator]
or, \[x = \sqrt {\dfrac{{{{(2 + \sqrt 3 )}^2}}}{{{2^2} - {{(\sqrt 3 )}^2}}}} \] [Using \[(a + b)(a - b) = {a^2} - {b^2}\] ]
or, \[x = \sqrt {\dfrac{{{{(2 + \sqrt 3 )}^2}}}{{4 - 3}}} \]
or, \[x = \sqrt {{{(2 + \sqrt 3 )}^2}} \]
or, \[x = 2 + \sqrt 3 \] [Taking positive square root]
Now, subtracting 4 from x we have
\[x - 4 = 2 + \sqrt 3 - 4 = - 2 + \sqrt 3 \]
So, \[{x^2}{(x - 4)^2} = {(2 + \sqrt 3 )^2}{( - 2 + \sqrt 3 )^2}\]
\[ = {(2 + \sqrt 3 )^2}{(2 - \sqrt 3 )^2}\]
\[ = {({2^2} - {(\sqrt 3 )^2})^2}\] [Using\[(a + b)(a - b) = {a^2} - {b^2}\]]
\[ = {(4 - 3)^2}\]
\[ = 1\]
Hence the option D. is correct.
Note: If we directly place the value of x in the desired term then the process will be very lengthy to find the answer. If we take a square of x directly then we have a very tough situation to handle this problem. Most of the students do this and have to face this difficult situation. Then they become puzzled to solve. So, first notice the question that you have to find, then following that you have to precede the solution to get an answer quickly. In this type of problem, first, we have to get rational free denominator terms using some techniques. The numerator term may be any term. But there should not be any surd term in the denominator.
Formula used: If we have a surd \[a + \sqrt b \] then its conjugate surd is \[a - \sqrt b \] and also vice-versa. I we have a fraction \[\dfrac{{c + \sqrt d }}{{a - \sqrt b }}\] then we always do rationalize and to rationalize this type of fraction we use the technique \[\dfrac{{(c + \sqrt d )(a + \sqrt {b)} }}{{(a - \sqrt b )(a + \sqrt {b)} }} = \dfrac{{(c + \sqrt d )(a + \sqrt {b)} }}{{{a^2} - b}}\] multiplying denominator and numerator by the conjugate surd of the denominator part to denominator as rational free term.
\[(a + b)(a - b) = {a^2} - {b^2}\].
Complete step-by-step solution:
We will rationalize the given term. The conjugate surd of \[2 - \sqrt 3 \] is \[2 + \sqrt 3 \].
We have
\[x = \sqrt {\dfrac{{2 + \sqrt 3 }}{{2 - \sqrt 3 }}} \]
or, \[x = \sqrt {\dfrac{{(2 + \sqrt 3 )(2 + \sqrt 3 )}}{{(2 - \sqrt 3 )(2 + \sqrt 3 )}}} \] [Rationalizing by multiplication of \[2 + \sqrt 3 \] with numerator and denominator]
or, \[x = \sqrt {\dfrac{{{{(2 + \sqrt 3 )}^2}}}{{{2^2} - {{(\sqrt 3 )}^2}}}} \] [Using \[(a + b)(a - b) = {a^2} - {b^2}\] ]
or, \[x = \sqrt {\dfrac{{{{(2 + \sqrt 3 )}^2}}}{{4 - 3}}} \]
or, \[x = \sqrt {{{(2 + \sqrt 3 )}^2}} \]
or, \[x = 2 + \sqrt 3 \] [Taking positive square root]
Now, subtracting 4 from x we have
\[x - 4 = 2 + \sqrt 3 - 4 = - 2 + \sqrt 3 \]
So, \[{x^2}{(x - 4)^2} = {(2 + \sqrt 3 )^2}{( - 2 + \sqrt 3 )^2}\]
\[ = {(2 + \sqrt 3 )^2}{(2 - \sqrt 3 )^2}\]
\[ = {({2^2} - {(\sqrt 3 )^2})^2}\] [Using\[(a + b)(a - b) = {a^2} - {b^2}\]]
\[ = {(4 - 3)^2}\]
\[ = 1\]
Hence the option D. is correct.
Note: If we directly place the value of x in the desired term then the process will be very lengthy to find the answer. If we take a square of x directly then we have a very tough situation to handle this problem. Most of the students do this and have to face this difficult situation. Then they become puzzled to solve. So, first notice the question that you have to find, then following that you have to precede the solution to get an answer quickly. In this type of problem, first, we have to get rational free denominator terms using some techniques. The numerator term may be any term. But there should not be any surd term in the denominator.
Recently Updated Pages
The maximum number of equivalence relations on the-class-11-maths-JEE_Main

A train is going from London to Cambridge stops at class 11 maths JEE_Main

Find the reminder when 798 is divided by 5 class 11 maths JEE_Main

An aeroplane left 50 minutes later than its schedu-class-11-maths-JEE_Main

A man on the top of a vertical observation tower o-class-11-maths-JEE_Main

In an election there are 8 candidates out of which class 11 maths JEE_Main

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

Understanding Atomic Structure for Beginners

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 11 Maths Chapter 10 Conic Sections

NCERT Solutions for Class 11 Maths Chapter 9 Straight Lines

NCERT Solutions For Class 11 Maths Chapter 8 Sequences And Series

How to Convert a Galvanometer into an Ammeter or Voltmeter

NCERT Solutions For Class 11 Maths Chapter 12 Limits And Derivatives

