
If P, Q and R are subsets of A , then find the value of \[R \times {({P^c} \cup {Q^c})^c}\] .
A.\[\left( {R \times P} \right) \cap \left( {R \times Q} \right)\]
B. \[\left( {R \times Q} \right) \cap \left( {R \times P} \right)\]
C. \[\left( {R \times P} \right) \cup \left( {R \times Q} \right)\]
D. None of these.
Answer
216.6k+ views
Hint: Apply De-Morgan’s law of sets in the expression \[{P^c} \cup {Q^c}\], then calculate to obtain the required result.
Formula Used:
De-Morgan’s law of sets is,
\[{(P \cup Q)^c} = {P^c} \cap {Q^c}\]
Complete step by step solution:
The given expression is,
\[R \times {({P^c} \cup {Q^c})^c}\]
Apply De-Morgan’s law in the given expression.
\[R \times {\left[ {{{(P \cap Q)}^c}} \right]^c}\]
Now, apply that \[{\left( {{A^c}} \right)^c} = A\] .
\[R \times \left[ {(P \cap Q)} \right]\]
=\[\left( {R \times P} \right) \cap \left( {R \times Q} \right)\]\[\]
Hence the correct option is A.
Additional Information: A set that contains the elements present in the universal set but excluded from set A is referred to as the complement of set A. The definition of a union is the set created by combining components from two sets. The set of elements in A, B, or both is the result of adding sets A and B together. With the help of De Morgan’s law, we learn how mathematical expressions and concepts are related to their opposites. In set theory, De Morgan’s law deals with the union intersection of a set and its complements. It is simply an observation of the relation between the sets and their complements. With the help of De Morgan’s law, we can solve a problem easily.
Note: Students sometimes want to solve this type of problem by Venn diagram, but as the nature of P and Q are not given as the sets are disjoint or not it’s complicated to draw a Venn diagram with this information, rather than that student should use the De- Morgan’s law and solve it easily.
Formula Used:
De-Morgan’s law of sets is,
\[{(P \cup Q)^c} = {P^c} \cap {Q^c}\]
Complete step by step solution:
The given expression is,
\[R \times {({P^c} \cup {Q^c})^c}\]
Apply De-Morgan’s law in the given expression.
\[R \times {\left[ {{{(P \cap Q)}^c}} \right]^c}\]
Now, apply that \[{\left( {{A^c}} \right)^c} = A\] .
\[R \times \left[ {(P \cap Q)} \right]\]
=\[\left( {R \times P} \right) \cap \left( {R \times Q} \right)\]\[\]
Hence the correct option is A.
Additional Information: A set that contains the elements present in the universal set but excluded from set A is referred to as the complement of set A. The definition of a union is the set created by combining components from two sets. The set of elements in A, B, or both is the result of adding sets A and B together. With the help of De Morgan’s law, we learn how mathematical expressions and concepts are related to their opposites. In set theory, De Morgan’s law deals with the union intersection of a set and its complements. It is simply an observation of the relation between the sets and their complements. With the help of De Morgan’s law, we can solve a problem easily.
Note: Students sometimes want to solve this type of problem by Venn diagram, but as the nature of P and Q are not given as the sets are disjoint or not it’s complicated to draw a Venn diagram with this information, rather than that student should use the De- Morgan’s law and solve it easily.
Recently Updated Pages
JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

Electricity and Magnetism Explained: Key Concepts & Applications

Chemical Properties of Hydrogen - Important Concepts for JEE Exam Preparation

JEE Energetics Important Concepts and Tips for Exam Preparation

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 11 Maths Chapter 10 Conic Sections

NCERT Solutions for Class 11 Maths Chapter 9 Straight Lines

NCERT Solutions For Class 11 Maths Chapter 8 Sequences And Series

Understanding Atomic Structure for Beginners

NCERT Solutions For Class 11 Maths Chapter 12 Limits And Derivatives

