
If a velocity has both perpendicular and parallel components when moving through a magnetic field, the path followed by a charged particle is:
(A) Circular
(B) Elliptical
(C) Linear
(D) Helical
Answer
234.9k+ views
Hint A particle moving in a magnetic field will experience force only if the magnetic field is perpendicular to it. This is because the force on a particle in a magnetic field is the cross product of velocity and direction of the magnetic field.
Complete step by step solution
When a particle is moving in a magnetic field, it experiences force according to the given formula
\[F\, = \,q(v\, \times B)\]
\[F\, = \,qvB\sin \theta \]
Where \[\theta \] is the angle between the velocity and the magnetic field.
This force will act perpendicular to the direction of motion of the particle. This centripetal force will be equal to
\[
\dfrac{{m{v^2}}}{r}\, = \,qvB \\
v\, = \,\dfrac{{qrB}}{m} \\
\]
Thus this force will make the particle move in a circular path. Whereas there will be no external force acting on the particle in the direction of the magnetic field. The resultant of these 2 forces will make the particle move in a helical path.
Therefore the correct answer is option D.
Note This concept is used in a particle accelerator, where the magnetic field rotates the particle in a circular motion and the electric field speeds up the particle.
Complete step by step solution
When a particle is moving in a magnetic field, it experiences force according to the given formula
\[F\, = \,q(v\, \times B)\]
\[F\, = \,qvB\sin \theta \]
Where \[\theta \] is the angle between the velocity and the magnetic field.
This force will act perpendicular to the direction of motion of the particle. This centripetal force will be equal to
\[
\dfrac{{m{v^2}}}{r}\, = \,qvB \\
v\, = \,\dfrac{{qrB}}{m} \\
\]
Thus this force will make the particle move in a circular path. Whereas there will be no external force acting on the particle in the direction of the magnetic field. The resultant of these 2 forces will make the particle move in a helical path.
Therefore the correct answer is option D.
Note This concept is used in a particle accelerator, where the magnetic field rotates the particle in a circular motion and the electric field speeds up the particle.
Recently Updated Pages
States of Matter Chapter For JEE Main Chemistry

Young’s Double Slit Experiment Derivation Explained

Wheatstone Bridge – Principle, Formula, Diagram & Applications

Circuit Switching vs Packet Switching: Key Differences Explained

Mass vs Weight: Key Differences Explained for Students

JEE Main Participating Colleges 2026 - A Complete List of Top Colleges

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Essential Derivations for CBSE Class 12 Physics: Stepwise & PDF Solutions

Dual Nature of Radiation and Matter Class 12 Physics Chapter 11 CBSE Notes - 2025-26

Understanding Uniform Acceleration in Physics

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

Understanding Electromagnetic Waves and Their Importance

