
If A is the A.M of the roots of the equation \[{x^2} - 2ax +{b^2} = 0\] and G is the G.M. of the roots of the equation \[{x^2} - 2bx + {a^2} = 0\], then
A. \[A > G\]
B. \[A \ne G\]
C. \[A = G\]
D. None of these
Answer
233.4k+ views
Hint
The values of the variable that satisfy a quadratic equation are known as its roots. The "solutions" or "zeroes" of the quadratic equation are other names for them. The x-coordinates of the x-intercepts of a quadratic function are the roots of the function. It is a quadratic equation in its general form, where "a" stands for the leading coefficient and "c" for the absolute term of f. (x).
The roots of a quadratic equation are the values of the variables that fulfil the equation. The constant term (the third term), divided by the leading coefficient, is equivalent to the product of the roots of a quadratic equation. Future courses will teach you that these relationships also apply to equations of higher degrees.
Formula use:
To find the ratio of two numbers,
G.M of a and b \[ = \sqrt {(ab)} \]
A.M of a and b \[ =\frac{{a + b }}{2} \]
If \[{x^2} - 2ax + b = 0\] is \[\alpha \] and \[\beta \]
then sum of root, \[\alpha + \beta = 2a\]
Product of roots, \[\alpha \beta = {b^2}\]
Complete step-by-step solution
Assume that the roots of the equation \[{x^2} - 2ax + b = 0\] is \[\alpha \] and \[\beta \]
Then, the equation becomes
\[\alpha + \beta = 2a\] and
The product of roots becomes
\[\alpha \beta = {b^2}\]
Assume that \[\alpha ',\beta '\]be the roots of the equation\[{x^2} - 2bx + {a^2} = 0\]
\[ = > \alpha ' + \beta ' = 2b\] and
The product of roots becomes
\[ = > \alpha '\beta ' = {a^2}\]
Then, by equating both the equation, it becomes
\[ = > \frac{{\alpha + \beta }}{2} = \sqrt {\alpha '\beta '} \]
Hence, it is proved that \[A = G\]
Therefore, the correct option is C.
Note
The product of two binomials can be used to represent a quadratic equation. The roots of the given quadratic equation in this case are a and b. The "solutions" or numerical values that are equal to the given equation's variable are known as the roots of the equation. The x-intercepts of a function are its roots. The y-coordinate of a point on the x-axis is always zero.
The values of the variable that satisfy a quadratic equation are known as its roots. The "solutions" or "zeroes" of the quadratic equation are other names for them. The x-coordinates of the x-intercepts of a quadratic function are the roots of the function. It is a quadratic equation in its general form, where "a" stands for the leading coefficient and "c" for the absolute term of f. (x).
The roots of a quadratic equation are the values of the variables that fulfil the equation. The constant term (the third term), divided by the leading coefficient, is equivalent to the product of the roots of a quadratic equation. Future courses will teach you that these relationships also apply to equations of higher degrees.
Formula use:
To find the ratio of two numbers,
G.M of a and b \[ = \sqrt {(ab)} \]
A.M of a and b \[ =\frac{{a + b }}{2} \]
If \[{x^2} - 2ax + b = 0\] is \[\alpha \] and \[\beta \]
then sum of root, \[\alpha + \beta = 2a\]
Product of roots, \[\alpha \beta = {b^2}\]
Complete step-by-step solution
Assume that the roots of the equation \[{x^2} - 2ax + b = 0\] is \[\alpha \] and \[\beta \]
Then, the equation becomes
\[\alpha + \beta = 2a\] and
The product of roots becomes
\[\alpha \beta = {b^2}\]
Assume that \[\alpha ',\beta '\]be the roots of the equation\[{x^2} - 2bx + {a^2} = 0\]
\[ = > \alpha ' + \beta ' = 2b\] and
The product of roots becomes
\[ = > \alpha '\beta ' = {a^2}\]
Then, by equating both the equation, it becomes
\[ = > \frac{{\alpha + \beta }}{2} = \sqrt {\alpha '\beta '} \]
Hence, it is proved that \[A = G\]
Therefore, the correct option is C.
Note
The product of two binomials can be used to represent a quadratic equation. The roots of the given quadratic equation in this case are a and b. The "solutions" or numerical values that are equal to the given equation's variable are known as the roots of the equation. The x-intercepts of a function are its roots. The y-coordinate of a point on the x-axis is always zero.
Recently Updated Pages
Geometry of Complex Numbers Explained

JEE General Topics in Chemistry Important Concepts and Tips

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

Electricity and Magnetism Explained: Key Concepts & Applications

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions For Class 11 Maths Chapter 12 Limits and Derivatives (2025-26)

NCERT Solutions For Class 11 Maths Chapter 10 Conic Sections (2025-26)

Understanding the Electric Field of a Uniformly Charged Ring

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Derivation of Equation of Trajectory Explained for Students

