
Hemiacetals are usually unstable whereas acetals are stable. Which has the most stable hemiacetal?
A.

B.

C.

D. \[{{C}_{6}}{{H}_{5}}-CHO\]
Answer
163.8k+ views
Hint: When two ether groups are joined to the same carbon, an acetal is created. Additionally, it is made from a hemiacetal, which is an aldehyde with two groups: an ether group and an alcohol group.
Complete Step by Step Answer:
Acetals are created when alcohols and aldehydes combine in an acidic environment. These are tetrahedral-shaped functional groups having two alkoxy (\[-OR\]) groups linked to the centre carbon atom. The action begins with the protonation of carbonyl oxygen, which makes the C=O bond highly electrophilic. Alcohol then attacks the C=O bond and creates an intermediate called oxonium as a result. Upon deprotonation, this intermediate transforms into a hemiacetal. In contrast to acetals, which have two alkoxy groups, hemiacetals only have one.
Hemiacetal's OH group is further protonated and converted into a suitable leaving group. The SN2 reaction cannot take place here because carbon is sterically inhibited. As a result, the SN2 process is used in this instance, in which the leaving group is first removed by oxygen lone pairs and then followed by deprotonation of the intermediate oxonium to produce acetal. By creating an ether bond and an OH bond on the same carbon, hemiacetals are created from an aldehyde or ketone and an alcohol. It serves as a tetrahedral intermediary in the acetal synthesis. It moves more quickly when an acid is used as a catalyst, but acid can also cause it to decompose and return to the original substance.
The hemiacetals are generally unstable in nature but they form acetals that are stable in nature. The stability of the acetal depends on the number of carbon chains in the ring. Usually, rings with 5 or 6 members are more stable than the others. So if we look at the given options the only compound that can form a 5 or 6 membered ring structure is option B that is 4-hydroxy butanal. The cyclic form is given as:

Hence, the correct option is B.
Note: Because it functions as a reducing sugar, a hemiacetal structure is unstable in nature. Acetals, on the other hand, are non-reducing sugars and are stable because they cannot be changed back into hemiacetals or aldehydes.
Complete Step by Step Answer:
Acetals are created when alcohols and aldehydes combine in an acidic environment. These are tetrahedral-shaped functional groups having two alkoxy (\[-OR\]) groups linked to the centre carbon atom. The action begins with the protonation of carbonyl oxygen, which makes the C=O bond highly electrophilic. Alcohol then attacks the C=O bond and creates an intermediate called oxonium as a result. Upon deprotonation, this intermediate transforms into a hemiacetal. In contrast to acetals, which have two alkoxy groups, hemiacetals only have one.
Hemiacetal's OH group is further protonated and converted into a suitable leaving group. The SN2 reaction cannot take place here because carbon is sterically inhibited. As a result, the SN2 process is used in this instance, in which the leaving group is first removed by oxygen lone pairs and then followed by deprotonation of the intermediate oxonium to produce acetal. By creating an ether bond and an OH bond on the same carbon, hemiacetals are created from an aldehyde or ketone and an alcohol. It serves as a tetrahedral intermediary in the acetal synthesis. It moves more quickly when an acid is used as a catalyst, but acid can also cause it to decompose and return to the original substance.
The hemiacetals are generally unstable in nature but they form acetals that are stable in nature. The stability of the acetal depends on the number of carbon chains in the ring. Usually, rings with 5 or 6 members are more stable than the others. So if we look at the given options the only compound that can form a 5 or 6 membered ring structure is option B that is 4-hydroxy butanal. The cyclic form is given as:

Hence, the correct option is B.
Note: Because it functions as a reducing sugar, a hemiacetal structure is unstable in nature. Acetals, on the other hand, are non-reducing sugars and are stable because they cannot be changed back into hemiacetals or aldehydes.
Recently Updated Pages
JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

JEE Main 2025 Session 2: Exam Date, Admit Card, Syllabus, & More

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

Trending doubts
Types of Solutions

Degree of Dissociation and Its Formula With Solved Example for JEE

Classification of Drugs

Instantaneous Velocity - Formula based Examples for JEE

JEE Main Chemistry Question Paper with Answer Keys and Solutions

JEE Main Chemistry Online Mock Test for Class 12

Other Pages
Haloalkanes and Haloarenes

Alcohol Phenol and Ether Class 12 Notes: CBSE Chemistry Chapter 7

Coordination Compounds Class 12 Notes: CBSE Chemistry Chapter 5

NCERT Solutions for Class 12 Chemistry In Hindi Chapter 10 Haloalkanes and Haloarenes In Hindi Mediem

Total MBBS Seats in India 2025: Government College Seat Matrix

NEET Total Marks 2025: Important Information and Key Updates
