
What happens when current is passed through a metallic loop placed in magnetic field?
A. The ring will feel a force of attraction.
B. The ring will feel a force of repulsion.
C. It will move to and fro about its centre of gravity.
D. None of these
Answer
161.1k+ views
Hint:When a current carrying coil or loop is placed in a magnetic field, it experiences some torque and starts to rotate. Use this concept of torque experienced on a current carrying loop placed in a uniform magnetic field to get the solution of the above question.
Complete answer:
When current starts to flow through a metallic loop, it starts behaving like a bar magnet.
When this current carrying metallic loop is placed in a magnetic field, it starts to experience a torque.
This makes the loop rotate in the magnetic field.
Torque in a current carrying loop placed in a uniform magnetic field is given by:
$\tau = iAB\sin \theta $ … (1)
Where $i$ is the current flowing through the loop,
$A$ is the area of the loop,
$B$ is the intensity of the magnetic field and
$\theta $ is the angle between the magnetic field and the axis of the loop.
From the given options,
The loop does not move to and fro about its centre of gravity.
It also neither feels a force of attraction or repulsion.
It experiences a torque, making it rotate. The direction of this torque is determined by the cross product of $\vec A$ and $\vec B$ .
Thus, the correct option is D.
Note: A current carrying loop is similar to a bar magnet. This loop, when placed in a magnetic field, experiences a torque. As torque makes a body rotate, thus, the current carrying loop starts to rotate in the magnetic field, depending on the direction of the area vector and the direction of the magnetic field. It does not experience forces of attraction and repulsion.
Complete answer:
When current starts to flow through a metallic loop, it starts behaving like a bar magnet.
When this current carrying metallic loop is placed in a magnetic field, it starts to experience a torque.
This makes the loop rotate in the magnetic field.
Torque in a current carrying loop placed in a uniform magnetic field is given by:
$\tau = iAB\sin \theta $ … (1)
Where $i$ is the current flowing through the loop,
$A$ is the area of the loop,
$B$ is the intensity of the magnetic field and
$\theta $ is the angle between the magnetic field and the axis of the loop.
From the given options,
The loop does not move to and fro about its centre of gravity.
It also neither feels a force of attraction or repulsion.
It experiences a torque, making it rotate. The direction of this torque is determined by the cross product of $\vec A$ and $\vec B$ .
Thus, the correct option is D.
Note: A current carrying loop is similar to a bar magnet. This loop, when placed in a magnetic field, experiences a torque. As torque makes a body rotate, thus, the current carrying loop starts to rotate in the magnetic field, depending on the direction of the area vector and the direction of the magnetic field. It does not experience forces of attraction and repulsion.
Recently Updated Pages
JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

Young's Double Slit Experiment Step by Step Derivation

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

JEE Energetics Important Concepts and Tips for Exam Preparation

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Electric field due to uniformly charged sphere class 12 physics JEE_Main

Displacement-Time Graph and Velocity-Time Graph for JEE

If a wire of resistance R is stretched to double of class 12 physics JEE_Main

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Formula for number of images formed by two plane mirrors class 12 physics JEE_Main

Uniform Acceleration

Degree of Dissociation and Its Formula With Solved Example for JEE
