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Gravitational attraction on Earth on the stone of mass M is ${F_S}$. If the force on the hydrogen balloon of mass M located at the same space is ${F_B}$, then
1) ${F_S} > {F_B}$
2) ${F_S} < {F_B}$
3) ${F_S} = {F_B}$
4) ${F_S} = -{F_B}$

Answer
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Hint: Before starting a question, we should know about the concept of gravitational attraction force. The gravitational force, which is exerted by each body in the universe and which is the subject of the science of gravitation, draws other bodies toward it. The heavier of the two masses is known as the source mass, while the lighter one is known as the test mass.

Complete answer:
The gravitational pull between two objects is proportional to their masses and becomes weaker as their distance from one another grows. A falling item attracts the Earth with a force equal to that with which the Earth attracts it. Both objects exert an equal attractive attraction on one another.

The Earth has an atmosphere because of its gravitational pull, which causes air molecules to significantly slow down and divert falling items like paper, tissues, and balloons off their intended route. Since hydrogen gas is lighter than air, a hydrogen gas-filled balloon floats high in the atmosphere on Earth.
The moon does not have enough gravity to hold down an atmosphere because its gravity is only one sixth that of the Earth's. Therefore, if a hydrogen gas balloon is launched from Earth and lands on the moon, the balloon will fall with an acceleration smaller than g.

Mass M of the bodies is the same on earth, so the gravitational force is also the same. Hence, option (3) is correct.

Note: The least powerful of the four fundamental forces is gravity. One drop of water's hydrogen bonding, one of the electromagnetic force's weakest manifestations, may overcome the gravitational pull of a whole planet since gravity is so weak.