
For a biased die the probabilities for different faces to turn up are given below. The die is tossed and you are told that either face 1 or 2 has turned up. What is the probability of getting face 1?
Face 1 2 3 4 5 6 Probability 0.1 0.32 0.21 0.15 0.05 0.17
A. \[\dfrac{5}{{21}}\]
B. \[\dfrac{5}{{22}}\]
C. \[\dfrac{4}{{21}}\]
D. None of these
| Face | 1 | 2 | 3 | 4 | 5 | 6 |
| Probability | 0.1 | 0.32 | 0.21 | 0.15 | 0.05 | 0.17 |
Answer
232.8k+ views
Hint:First we will calculate the probability of getting face 1 or 2 by using the formula \[P\left( {A \cup B} \right) = P\left( A \right) + P\left( B \right)\]. Then we will apply the formula \[{\rm{Probability = }}\dfrac{{{\rm{The}}\,{\rm{number}}\,{\rm{of}}\,{\rm{favorable}}\,{\rm{outcomes}}}}{{{\rm{The}}\,{\rm{number}}\,{\rm{of}}\,{\rm{total}}\,{\rm{outcomes}}}}\].
Formula Used:
\[P\left( {A \cup B} \right) = P\left( A \right) + P\left( B \right)\]
\[{\rm{Probability = }}\dfrac{{{\rm{The}}\,{\rm{number}}\,{\rm{of}}\,{\rm{favorable}}\,{\rm{outcomes}}}}{{{\rm{The}}\,{\rm{number}}\,{\rm{of}}\,{\rm{total}}\,{\rm{outcomes}}}}\]
Complete step by step solution:
The probability of getting face 1 is 0.1.
The probability of getting face 2 is 0.32.
Since face 1 and face 2 are independent events.
Apply the formula \[P\left( {A \cup B} \right) = P\left( A \right) + P\left( B \right)\] to get face 1 or face 2
The probability of getting face 1 or face 2 is \[0.1 + 0.32 = 0.42\].
Apply the formula \[{\rm{Probability = }}\dfrac{{{\rm{The}}\,{\rm{number}}\,{\rm{of}}\,{\rm{favorable}}\,{\rm{outcomes}}}}{{{\rm{The}}\,{\rm{number}}\,{\rm{of}}\,{\rm{total}}\,{\rm{outcomes}}}}\] to calculate the probability of getting face 1.
A bise die rolled. After rolling the die, we will get either face 1 or face 2. So, the total probability is the probability of getting either face 1 or face 2.
The number of total outcomes is 0.42.
The number of favorable outcomes is 0.1.
The required probability is \[{\rm{ = }}\dfrac{{0.1}}{{0.42}}\]
Multiply 100 with numerator and denominator
\[{\rm{ = }}\dfrac{{0.1 \times 100}}{{0.42 \times 100}}\]
\[{\rm{ = }}\dfrac{{10}}{{42}}\]
Divide the numerator and denominator by 2
\[{\rm{ = }}\dfrac{5}{{21}}\]
Hence option A is the correct.
Note:Student often do a common mistake to calculate total probability. They calculate the probability by adding the probability of getting face 1, face 2, face 3, face 4, face 5, and face 6. Since the die is biased, so it shows only face 1 and face 2 when it rolled. Therefore, the total probability is the sum of the probability of getting face 1 and face 2.
Formula Used:
\[P\left( {A \cup B} \right) = P\left( A \right) + P\left( B \right)\]
\[{\rm{Probability = }}\dfrac{{{\rm{The}}\,{\rm{number}}\,{\rm{of}}\,{\rm{favorable}}\,{\rm{outcomes}}}}{{{\rm{The}}\,{\rm{number}}\,{\rm{of}}\,{\rm{total}}\,{\rm{outcomes}}}}\]
Complete step by step solution:
The probability of getting face 1 is 0.1.
The probability of getting face 2 is 0.32.
Since face 1 and face 2 are independent events.
Apply the formula \[P\left( {A \cup B} \right) = P\left( A \right) + P\left( B \right)\] to get face 1 or face 2
The probability of getting face 1 or face 2 is \[0.1 + 0.32 = 0.42\].
Apply the formula \[{\rm{Probability = }}\dfrac{{{\rm{The}}\,{\rm{number}}\,{\rm{of}}\,{\rm{favorable}}\,{\rm{outcomes}}}}{{{\rm{The}}\,{\rm{number}}\,{\rm{of}}\,{\rm{total}}\,{\rm{outcomes}}}}\] to calculate the probability of getting face 1.
A bise die rolled. After rolling the die, we will get either face 1 or face 2. So, the total probability is the probability of getting either face 1 or face 2.
The number of total outcomes is 0.42.
The number of favorable outcomes is 0.1.
The required probability is \[{\rm{ = }}\dfrac{{0.1}}{{0.42}}\]
Multiply 100 with numerator and denominator
\[{\rm{ = }}\dfrac{{0.1 \times 100}}{{0.42 \times 100}}\]
\[{\rm{ = }}\dfrac{{10}}{{42}}\]
Divide the numerator and denominator by 2
\[{\rm{ = }}\dfrac{5}{{21}}\]
Hence option A is the correct.
Note:Student often do a common mistake to calculate total probability. They calculate the probability by adding the probability of getting face 1, face 2, face 3, face 4, face 5, and face 6. Since the die is biased, so it shows only face 1 and face 2 when it rolled. Therefore, the total probability is the sum of the probability of getting face 1 and face 2.
Recently Updated Pages
Geometry of Complex Numbers Explained

JEE General Topics in Chemistry Important Concepts and Tips

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

Electricity and Magnetism Explained: Key Concepts & Applications

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions For Class 11 Maths Chapter 12 Limits and Derivatives (2025-26)

NCERT Solutions For Class 11 Maths Chapter 10 Conic Sections (2025-26)

Understanding the Electric Field of a Uniformly Charged Ring

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Derivation of Equation of Trajectory Explained for Students

