Question

How many of the following compounds has $X-X$ bonds i.e. single covalent bond between two same elements in their molecule?
$\begin{align}
  & A.{{H}_{4}}{{P}_{2}}{{O}_{6}} \\
 & B.{{H}_{4}}{{P}_{2}}{{O}_{5}} \\
 & C.{{H}_{4}}{{P}_{2}}{{O}_{7}} \\
 & D.{{N}_{2}}O \\
 & E.{{N}_{2}}{{O}_{3}} \\
 & F.{{N}_{2}}{{O}_{4}} \\
 & G.{{N}_{2}}{{O}_{5}} \\
 & H.{{(HP{{O}_{3}})}_{3}} \\
\end{align}$

Answer 1

Hint: Draw the structure of all the molecules given in the options and then count the number of single covalent bonds in there respective structures and then that will be the correct answers

Complete Step by Step Answer:
The hypophosphoric acids of the phosphorus element has many times peroxo linkage in their structures. The method of drawing the structures is to attach all the hydrogen as hydroxo ion i.e OH bonds and rest oxygen is connected as per the covalency of the central atom like phosphorus in the phospohoric acids and nitrogen in the nitrous compounds given . So , first we need to draw the diagrams of all the compounds given above.



${{(HP{{O}_{3}})}_{3}}$ ${{(HP{{O}_{3}})}_{3}}$
From these structures we can infer that the compounds in which the single covalent bond is present in the same element are 3 compounds .
Thus , the correct option is A,E,F.

Note: Solubility product is a type of equilibrium constant whose value depends on the temperature. It is denoted by ${{K}_{sp}}$. It usually increases with the increase in temperature because of the increased solubility. Remember that solubility and the solubility product are different from each other. Solubility of a substance in a solvent is the highest amount of solute that can be dissolved in a solvent whereas the solubility product is an equilibrium constant that gives the equilibrium between the solid solute and its ions that are dissolved in the solution