
Find the value of $[\tan A /(1+\sec A)]+[(1+\sec A) / \tan A]$
1) $2 \sin A$
2) $2 \cos \mathrm{A}$
3) $2 \operatorname{cosec} \mathrm{A}$
4) $2 \sec A$
Answer
218.4k+ views
Hint: We have to find the value of the given expression for that we need to know some basic trigonometric theorems. All trigonometric identities are built upon the foundation of the six trigonometric ratios. Sine, cosine, tangent, cosecant, secant, and cotangent are a few of their names. These trigonometric ratios are each defined in terms of the right triangle's adjacent side, opposite side, and hyperbolic tangent side. All basic trigonometric identities are derived from the six trigonometric ratios.
Formula Used:
The trignometric identity ${{\sec }^{2}}x-{{\tan }^{2}}x=1$
Complete step by step Solution:
Given that
${[\tan A /(1+\sec A)]+[(1+\sec A) / \tan A] }$
Cross-multiply the terms
We get
$=\left[\left(\tan ^{2} A+(1+\sec A)^{2}\right] /(1+\sec A) \tan A\right.$
There are two primary tangent function formulations. As we already know, $\tan x$ in a right-angled triangle is defined as the ratio of the angle's opposite and adjacent sides. The ratio of the sine function to the cosine function, which can be calculated using a unit circle, is another way to define the tangent function. So, the $\tan x$ formulae are as follows:.
- $\tan x=\sin x / \cos x$
- $\tan x=$ Opposite Side/Adjacent Side
using the identity ${{\sec }^{2}}x-{{\tan }^{2}}x=1$
$=\left[ \left( {{\sec }^{2}}A-1 \right)+{{(1+\sec A)}^{2}} \right]/(1+\sec A)\tan A$
$=[(\sec A+1)(\sec A-1+1+\sec A)] /(1+\sec A) \tan A$
$=2 \sec A / \tan A$
$=(2 / \cos A) /(\sin A / \cos A)$
$=2 / \sin A$
$=2 \operatorname{cosec} A$
Hence, the correct option is 3.
Additional Information:There are two primary tangent function formulations. Since we already know, in a right-angled triangle is defined as the ratio of the angle's opposite and adjacent sides. The ratio of the sine function to the cosine function, which can be calculated using a unit circle, is another way to define the tangent function.
Note: It's important to keep in mind that the cosecant is the relationship between two sides of a right-angled triangle and an acute angle. Any angle that is less than or greater than 90 degrees can have a cosecant since both acute and obtuse angles can have a cosecant.
Formula Used:
The trignometric identity ${{\sec }^{2}}x-{{\tan }^{2}}x=1$
Complete step by step Solution:
Given that
${[\tan A /(1+\sec A)]+[(1+\sec A) / \tan A] }$
Cross-multiply the terms
We get
$=\left[\left(\tan ^{2} A+(1+\sec A)^{2}\right] /(1+\sec A) \tan A\right.$
There are two primary tangent function formulations. As we already know, $\tan x$ in a right-angled triangle is defined as the ratio of the angle's opposite and adjacent sides. The ratio of the sine function to the cosine function, which can be calculated using a unit circle, is another way to define the tangent function. So, the $\tan x$ formulae are as follows:.
- $\tan x=\sin x / \cos x$
- $\tan x=$ Opposite Side/Adjacent Side
using the identity ${{\sec }^{2}}x-{{\tan }^{2}}x=1$
$=\left[ \left( {{\sec }^{2}}A-1 \right)+{{(1+\sec A)}^{2}} \right]/(1+\sec A)\tan A$
$=[(\sec A+1)(\sec A-1+1+\sec A)] /(1+\sec A) \tan A$
$=2 \sec A / \tan A$
$=(2 / \cos A) /(\sin A / \cos A)$
$=2 / \sin A$
$=2 \operatorname{cosec} A$
Hence, the correct option is 3.
Additional Information:There are two primary tangent function formulations. Since we already know, in a right-angled triangle is defined as the ratio of the angle's opposite and adjacent sides. The ratio of the sine function to the cosine function, which can be calculated using a unit circle, is another way to define the tangent function.
Note: It's important to keep in mind that the cosecant is the relationship between two sides of a right-angled triangle and an acute angle. Any angle that is less than or greater than 90 degrees can have a cosecant since both acute and obtuse angles can have a cosecant.
Recently Updated Pages
The maximum number of equivalence relations on the-class-11-maths-JEE_Main

A train is going from London to Cambridge stops at class 11 maths JEE_Main

Find the reminder when 798 is divided by 5 class 11 maths JEE_Main

An aeroplane left 50 minutes later than its schedu-class-11-maths-JEE_Main

A man on the top of a vertical observation tower o-class-11-maths-JEE_Main

In an election there are 8 candidates out of which class 11 maths JEE_Main

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

Understanding Atomic Structure for Beginners

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 11 Maths Chapter 10 Conic Sections

NCERT Solutions for Class 11 Maths Chapter 9 Straight Lines

NCERT Solutions For Class 11 Maths Chapter 8 Sequences And Series

How to Convert a Galvanometer into an Ammeter or Voltmeter

NCERT Solutions For Class 11 Maths Chapter 12 Limits And Derivatives

