Ethylene may be obtained by dehydration of which of the following is concentrated \[{H_2}S{O_4}\] at \[160 - 170^\circ C\]?
(a) \[{C_2}{H_5}OH\]
(b) \[C{H_3}OH\]
(c) \[C{H_3}C{H_2}C{H_2}OH\]
(d) \[{(C{H_3})_2}CHC{H_2}OH\]
Answer
261k+ views
Hint: Dehydration reactions are the reaction that involves the removal of water (\[{H_2}O\]) molecules upon heating the molecular compounds. The best example of dehydration reaction is the elimination reaction where the formation of a more stable alkene occurs by the abstraction of a beta-proton via base.
Complete Step by Step Answer:
As we know the dehydration reaction involves the removal of water \[{H_2}O\] molecules.
In a dehydration reaction, a water molecule is generated by the removal of a beta-hydrogen atom and hydroxyl group (\[ - OH\]).

Image: Ethanol
The dehydration of alcohol can be done by the following two methods.
1. By allowing the vapours of alcohols over heated alumina (\[A{l_2}{O_3}\]).
2. By heating alcohols with conc. Sulfuric acid (\[{H_2}S{O_4}\]) and phosphoric acid (\[{H_3}P{O_4}\]).

Image: Dehydration of alcohol
Sometimes anhydrous zinc chloride (\[ZnC{l_2}\]) is also used for the dehydration of alcohols.
The dehydration trends of alcohols can be represented as tertiary alcohols > secondary alcohols> primary alcohols.
The tertiary alcohols and secondary alcohols can also be dehydrated by diluting sulfuric acid (\[{H_2}S{O_4}\]).
In the question, option (b), (c), and (d) will be the incorrect option because the dehydration of \[C{H_3}OH\] , \[C{H_3}C{H_2}C{H_2}OH\]and \[{(C{H_3})_2}CHC{H_2}OH\]do not produce ethylene. For the formation of ethylene, the alcohol must have two carbon atoms.
Therefore, from the above discussion, it is quite clear that option (a) will be the correct answer.
Note: During the dehydration of alcohols in the presence of acids the number of carbon atoms remains the same. Sulfuric acid (\[{H_2}S{O_4}\]) is a colourless and corrosive liquid. It is highly miscible with water.
Complete Step by Step Answer:
As we know the dehydration reaction involves the removal of water \[{H_2}O\] molecules.
In a dehydration reaction, a water molecule is generated by the removal of a beta-hydrogen atom and hydroxyl group (\[ - OH\]).

Image: Ethanol
The dehydration of alcohol can be done by the following two methods.
1. By allowing the vapours of alcohols over heated alumina (\[A{l_2}{O_3}\]).
2. By heating alcohols with conc. Sulfuric acid (\[{H_2}S{O_4}\]) and phosphoric acid (\[{H_3}P{O_4}\]).

Image: Dehydration of alcohol
Sometimes anhydrous zinc chloride (\[ZnC{l_2}\]) is also used for the dehydration of alcohols.
The dehydration trends of alcohols can be represented as tertiary alcohols > secondary alcohols> primary alcohols.
The tertiary alcohols and secondary alcohols can also be dehydrated by diluting sulfuric acid (\[{H_2}S{O_4}\]).
In the question, option (b), (c), and (d) will be the incorrect option because the dehydration of \[C{H_3}OH\] , \[C{H_3}C{H_2}C{H_2}OH\]and \[{(C{H_3})_2}CHC{H_2}OH\]do not produce ethylene. For the formation of ethylene, the alcohol must have two carbon atoms.
Therefore, from the above discussion, it is quite clear that option (a) will be the correct answer.
Note: During the dehydration of alcohols in the presence of acids the number of carbon atoms remains the same. Sulfuric acid (\[{H_2}S{O_4}\]) is a colourless and corrosive liquid. It is highly miscible with water.
Recently Updated Pages
Algebra Made Easy: Step-by-Step Guide for Students

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

JEE Energetics Important Concepts and Tips for Exam Preparation

Chemical Properties of Hydrogen - Important Concepts for JEE Exam Preparation

JEE General Topics in Chemistry Important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

JEE Main Participating Colleges 2026 - A Complete List of Top Colleges

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Electric Field of a Uniformly Charged Ring

Understanding the Different Types of Solutions in Chemistry

Derivation of Equation of Trajectory Explained for Students

Other Pages
JEE Advanced 2026 Notification Out with Exam Date, Registration (Extended), Syllabus and More

CBSE Class 12 Chemistry Question Paper 2026 PDF Download (All Sets) with Answer Key

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions For Class 12 Chemistry Chapter 2 Electrochemistry - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 1 Solutions - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 3 Chemical Kinetics - 2025-26

