When ethyl iodide is heated with silver nitrate, the product obtained is
A. \[{{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{5}}}{\rm{Ag}}\]
B.\[{\rm{Ag}} - {\rm{O}} - {\rm{N}}{{\rm{O}}_{\rm{2}}}\]
C.\[{{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{5}}}{\rm{O}} - {\rm{N}}{{\rm{O}}_{\rm{2}}}\]
D. \[{{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{5}}}{\rm{I}} - {\rm{N}}{{\rm{O}}_{\rm{2}}}\]
Answer
250.2k+ views
Hint: Silver nitrate is an important organic compound used as an antiseptic and in many chemical reactions. The chemical symbol of silver nitrate is \[{\rm{AgN}}{{\rm{O}}_{\rm{3}}}\] . It is also used in the industrial preparation of many salts of silver.
Complete Step by Step Solution:
Let’s understand the reaction of ethyl iodide and silver nitrate. In the first step, dissociation of bonds of C-I and Ag-N occurs.

Image: Reaction of ethyl iodide and silver nitrate
In the second step, the nitrate ion attacks the carbocation and the product forms.

Image: Nucleophilic attack of nitrate ion
Therefore, the product formed in the reaction of ethyl iodide and silver nitrate is ethyl nitrate, \[{{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{5}}}{\rm{O}} - {\rm{N}}{{\rm{O}}_{\rm{2}}}\].
Hence, the option C is right
Additional Information: Let’s discuss ethyl iodide in detail. Ethyl iodide is also chemically known as iodoethane. It is a chemical compound of no colour and flammable properties. The chemical symbol of ethyl iodide is \[{{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{5}}}{\rm{I}}\]. The preparation of ethyl iodide is done by heating ethanol with phosphorus and iodine. The decomposition of iodoethane or ethyl iodide occurs when it comes in contact with air or light.
Note: There are many uses for silver nitrate in our everyday life. Silver nitrate is useful in treating wounds. It is used to treat bone ulcers, burns, and acute wounds. In the laboratory, Silver nitrate is a useful reagent because of its role in the identification of halogens, such as bromine, chlorine etc.
Complete Step by Step Solution:
Let’s understand the reaction of ethyl iodide and silver nitrate. In the first step, dissociation of bonds of C-I and Ag-N occurs.

Image: Reaction of ethyl iodide and silver nitrate
In the second step, the nitrate ion attacks the carbocation and the product forms.

Image: Nucleophilic attack of nitrate ion
Therefore, the product formed in the reaction of ethyl iodide and silver nitrate is ethyl nitrate, \[{{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{5}}}{\rm{O}} - {\rm{N}}{{\rm{O}}_{\rm{2}}}\].
Hence, the option C is right
Additional Information: Let’s discuss ethyl iodide in detail. Ethyl iodide is also chemically known as iodoethane. It is a chemical compound of no colour and flammable properties. The chemical symbol of ethyl iodide is \[{{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{5}}}{\rm{I}}\]. The preparation of ethyl iodide is done by heating ethanol with phosphorus and iodine. The decomposition of iodoethane or ethyl iodide occurs when it comes in contact with air or light.
Note: There are many uses for silver nitrate in our everyday life. Silver nitrate is useful in treating wounds. It is used to treat bone ulcers, burns, and acute wounds. In the laboratory, Silver nitrate is a useful reagent because of its role in the identification of halogens, such as bromine, chlorine etc.
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