
During negative beta decay
A. Neutron converts into proton
B. Proton converts into neutron
C. Neutron proton ratio increases
D. None of these
Answer
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Hint: A negative beta decay is a radioactive disintegration in which a neutron is converted into a proton or an electron, it happened because of the emission of a beta particle such as an electron or a positron. If an emitted beta particle is changed as an electron, then it is called as negative beta (β) decay. Use the concept to solve the question
Complete answer:
Radioactive disintegration of a nucleus is the process of which the nucleus loses their energy in the radiation form. Beta decay allows the nucleus to the ratio of optimal proton or neutron. Where there are too many neutrons related to the protons negative beta decay occurred. And if there are many protons related to the neutrons, a positive beta decay is taking place.
During positive beta decay; it releases a positively charged beta particle called a positron, and neutrino. In negative beta decay, it releases a negatively charged beta particle called an electron and antineutrino.
The process of beta decay in electron emission is called negative beta decay. An unstable nucleus emitted an energetic electron. In negative beta decay, a neutron in the nucleus is converted into a proton or an electron. This process may occur due to the emission of a beta particle. It can be an electron or a positron.
When a proton of the nucleus is converted into a neutron, the beta particle released is a positron(positive electron). Along with this type of positron a neutrino is released. This type of disintegration is called positive beta decay. It is denoted as + .
The positive equation is written as below:
\(p \to n + {e^ + }\)
If the neutron of the nucleus is converted into a proton, the beta particle released is an electron. Along with this type of electron, an anti-neutrino is released. This type of beta disintegration process is called negative beta decay. It is denoted as -.
The negative equation is written as below:
\(n = p + {e^ - }\)
Therefore we know that negative beta disintegration involves disintegration of a neutron by the emission of an electron.
Hence, the correct answer is option A.
Note: In this type of phenomenon of beta disintegration, the reaction should follow the law of conservation. According to this law, there is a constant mass during the reaction. Neutrons or protons only transform into others. We should include the proton number at the bottom of an atom, so that only it was easier to see the difference from the new atom. During the negative beta disintegration there is no loss of mass. And the total mass stayed constant before and after the reaction of negative beta decay.
Complete answer:
Radioactive disintegration of a nucleus is the process of which the nucleus loses their energy in the radiation form. Beta decay allows the nucleus to the ratio of optimal proton or neutron. Where there are too many neutrons related to the protons negative beta decay occurred. And if there are many protons related to the neutrons, a positive beta decay is taking place.
During positive beta decay; it releases a positively charged beta particle called a positron, and neutrino. In negative beta decay, it releases a negatively charged beta particle called an electron and antineutrino.
The process of beta decay in electron emission is called negative beta decay. An unstable nucleus emitted an energetic electron. In negative beta decay, a neutron in the nucleus is converted into a proton or an electron. This process may occur due to the emission of a beta particle. It can be an electron or a positron.
When a proton of the nucleus is converted into a neutron, the beta particle released is a positron(positive electron). Along with this type of positron a neutrino is released. This type of disintegration is called positive beta decay. It is denoted as + .
The positive equation is written as below:
\(p \to n + {e^ + }\)
If the neutron of the nucleus is converted into a proton, the beta particle released is an electron. Along with this type of electron, an anti-neutrino is released. This type of beta disintegration process is called negative beta decay. It is denoted as -.
The negative equation is written as below:
\(n = p + {e^ - }\)
Therefore we know that negative beta disintegration involves disintegration of a neutron by the emission of an electron.
Hence, the correct answer is option A.
Note: In this type of phenomenon of beta disintegration, the reaction should follow the law of conservation. According to this law, there is a constant mass during the reaction. Neutrons or protons only transform into others. We should include the proton number at the bottom of an atom, so that only it was easier to see the difference from the new atom. During the negative beta disintegration there is no loss of mass. And the total mass stayed constant before and after the reaction of negative beta decay.
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