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Diethyl ether on heating with excess of conc. $HI$ gives two moles of
A. Ethanol
B. 1-bromo-2-butene
C. Ethyl iodide
D. Methyl iodide

Answer
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Hint:The nature of Diethyl ether is a flammable substance that has the potential to explode. In addition to an open flame, heat sources and even static electricity can ignite diethyl ether vapour. In addition, when exposed to light and air, it can generate explosive peroxides. Ether (ROR) can break into RO- and R'groups.

Complete step-by-step answer:As we know that, Diethyl ether reacts with excess of conc. $HI$ to give two moles of Ethyl iodide.
The reactions take place as follows:
${C_2}{H_5}O{C_2}{H_5} + HI \to {C_2}{H_5}OH + {C_2}{H_5}I$

Here, diethyl ether reacts with $HI$ to give ethanol and other by-product.
In the second reaction, ethanol formed above reacts with excess of conc. $HI$ to give ethyl iodide.
${C_2}{H_5}OH + HI \to {C_2}{H_5}I+ {H_2}O$

The total reaction taking place can be written as:
${C_2}{H_5}O{C_2}{H_5} + 2HI \to 2{C_2}{H_5}I + {H_2}O$

Therefore, the correct answer is Ethyl iodide.

Option ‘C’ is correct

Additional Information: First of all, let’s talk about the compound diethyl ether.
Diethyl ether or ether, is an organic compound of the ether class which is used as a solvent in the manufacture of synthetic dyes and plastics.
Diethyl ether was also widely used by many countries as an anesthetic agent.

Note: The ethanol gets converted into ethyl iodide by the nucleophilic substitution reaction in this process hydroxyl group gets replaced with I- group. Similarly, in the first step it can be considered that ethoxy group of Diethyl ether is replaced by I- group.