Current through $100\Omega $ resistor is
(Given forward resistance of diode = $50\Omega $, reverse bias resistance = $\infty $ )

Answer
300.9k+ views
Hint Diode connected in forward bias conducts and that connected in reverse biased does not. We will use this concept to approach the solution. Further we will find total equivalent resistance of the circuit and find the required current.
Complete Step by step answer
Let ${D_1}$ be the diode in series with $50\Omega $ resistance and ${D_2}$ be the diode in series with $150\Omega $ resistance.
Diode ${D_1}$ is reverse biased and ${D_2}$ is forward biased.
Since diodes in reverse bias offer infinite resistance therefore no current flows through it. Hence all current pass-through diodes ${D_2}$ .

Now we will find equivalent resistance of circuit,
${R_{eq}} = 150\Omega + 100\Omega + {R_{{D_2}}}$
$
\because {R_{{D_{_2}}}} = 50\Omega \\
\therefore {R_{eq}} = 200\Omega \\
$
Thus, total current in the circuit is,
$
I = \dfrac{V}{{{R_{eq}}}} \\
\\
$
On putting value, we get
$
I = \dfrac{6}{{200}} \\
I = 0.03A \\
$
As all the resistances are in series, thus we get the current passing through the $100\Omega $ resistor as $0.03A$ .
Note In forward biasing width of depletion layer decreases hence diode offers zero resistance and acts as a short circuit and in reverse biasing width of depletion layer increases hence it offers infinite resistance and acts as an open circuit. In open circuit no current flows in the circuit.
Complete Step by step answer
Let ${D_1}$ be the diode in series with $50\Omega $ resistance and ${D_2}$ be the diode in series with $150\Omega $ resistance.
Diode ${D_1}$ is reverse biased and ${D_2}$ is forward biased.
Since diodes in reverse bias offer infinite resistance therefore no current flows through it. Hence all current pass-through diodes ${D_2}$ .

Now we will find equivalent resistance of circuit,
${R_{eq}} = 150\Omega + 100\Omega + {R_{{D_2}}}$
$
\because {R_{{D_{_2}}}} = 50\Omega \\
\therefore {R_{eq}} = 200\Omega \\
$
Thus, total current in the circuit is,
$
I = \dfrac{V}{{{R_{eq}}}} \\
\\
$
On putting value, we get
$
I = \dfrac{6}{{200}} \\
I = 0.03A \\
$
As all the resistances are in series, thus we get the current passing through the $100\Omega $ resistor as $0.03A$ .
Note In forward biasing width of depletion layer decreases hence diode offers zero resistance and acts as a short circuit and in reverse biasing width of depletion layer increases hence it offers infinite resistance and acts as an open circuit. In open circuit no current flows in the circuit.
Recently Updated Pages
If the magnetizing field on a ferromagnetic material class 12 physics JEE_Main

A point charge is placed at the corner of a cube The class 12 physics JEE_Main

What changes occur if the monochromatic light used class 12 physics JEE_Main

The unit of specific conductance is A Ohm B Ohmmetre class 12 physics JEE_Main

Which lens is used in magnifying glass A Concave lens class 12 physics JEE_Main

Sir C V Raman won the Nobel Prize in which year A 1928 class 12 physics JEE_Main

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Understanding the Electric Field of a Uniformly Charged Ring

Electron Gain Enthalpy and Electron Affinity Explained

Derivation of Equation of Trajectory Explained for Students

Understanding Atomic Structure for Beginners

Understanding Uniform Acceleration in Physics

Other Pages
CBSE Class 12 Physics Question Paper 2026: Download SET-wise PDF with Answer Key & Analysis

JEE Advanced Percentile vs Marks 2026: JEE Main Cutoff, AIR & IIT Admission Guide

How to Convert a Galvanometer into an Ammeter or Voltmeter

Hybridisation in Chemistry – Concept, Types & Applications

What Are Elastic Collisions in One Dimension?

Effective Nuclear Charge for JEE

