
When current flows through a conductor, then the order of drift velocity of electrons will be?
A. ${10^{10}}cm/s$
B. ${10^{ - 2}}cm/s$
C. ${10^4}cm/s$
D. ${10^{ - 1}}cm/s$
Answer
232.8k+ views
Hint: In this case, we will assume the ideal conditions to find the order of drift velocity of electrons. Also, we know that all the parameters in current electricity vary with each other (directly or indirectly) i.e., current, voltage, resistance, etc. Hence, analyze every aspect of the solution needed and then present it with a proper explanation in a scientific approach.
Formula used:
Drift Velocity of electrons can be calculated by using formula,
$v = \dfrac{I}{{nAQ}}$
Where, v = drift velocity of electrons in $m/s$
I = current flowing through the conductor
n = number of electrons
A = area of cross section of the conductor
Q = charge of an electron
Complete step by step solution:
As we all know, electrons move with different velocities in an arbitrary direction in absence of an electric field inside a conductor. But, whenever an electric current flows through a conductor, the electrons start moving towards positive potential with a certain velocity. The average velocity acquired by a charged particle in a conductor due to an electric field is called drift velocity.
Drift Velocity of electrons (or any charged particle) can be calculated by using formula
$v = \dfrac{I}{{nAQ}}$
By assuming ideal conditions such as $I = 1A$or $A = 1m/{s^2}$, the order of drift velocity of electrons can be calculated as ${10^{ - 4}}m/s$. This means, when current flows through a conductor, then the order of drift velocity of electrons will be ${10^{ - 4}}m/s$ i.e., ${10^{ - 2}}cm/s$.$(\therefore 1m = 100cm)$
Hence, the correct option is B.
Note: Since this is a partial-numerical-based problem hence, it is essential that the given question is to be analyzed very carefully to give an accurate solution. Also, as we assumed the ideal conditions to solve this question, we should know that the value of the drift velocity of electrons changes with the other values of current, cross-sectional area, etc., but the order will always remain the same.
Formula used:
Drift Velocity of electrons can be calculated by using formula,
$v = \dfrac{I}{{nAQ}}$
Where, v = drift velocity of electrons in $m/s$
I = current flowing through the conductor
n = number of electrons
A = area of cross section of the conductor
Q = charge of an electron
Complete step by step solution:
As we all know, electrons move with different velocities in an arbitrary direction in absence of an electric field inside a conductor. But, whenever an electric current flows through a conductor, the electrons start moving towards positive potential with a certain velocity. The average velocity acquired by a charged particle in a conductor due to an electric field is called drift velocity.
Drift Velocity of electrons (or any charged particle) can be calculated by using formula
$v = \dfrac{I}{{nAQ}}$
By assuming ideal conditions such as $I = 1A$or $A = 1m/{s^2}$, the order of drift velocity of electrons can be calculated as ${10^{ - 4}}m/s$. This means, when current flows through a conductor, then the order of drift velocity of electrons will be ${10^{ - 4}}m/s$ i.e., ${10^{ - 2}}cm/s$.$(\therefore 1m = 100cm)$
Hence, the correct option is B.
Note: Since this is a partial-numerical-based problem hence, it is essential that the given question is to be analyzed very carefully to give an accurate solution. Also, as we assumed the ideal conditions to solve this question, we should know that the value of the drift velocity of electrons changes with the other values of current, cross-sectional area, etc., but the order will always remain the same.
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Dual Nature of Radiation and Matter Class 12 Physics Chapter 11 CBSE Notes - 2025-26

Understanding Uniform Acceleration in Physics

Understanding the Electric Field of a Uniformly Charged Ring

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Derivation of Equation of Trajectory Explained for Students

