Calculate the area of cross section of a wire of length 2m, resistance $46{\text{ }}\Omega $ and resistivity $1.84 \times {10^{ - 6}}\Omega {\text{m}}$.
Answer
244.8k+ views
Hint: In this question we have to find the area of cross section of wire having length equal to 2m, resistance $46{\text{ }}\Omega $ and resistivity $1.84 \times {10^{ - 6}}\Omega {\text{m}}$. To find the cross section we are going to use the formula of resistivity.
Complete step by step solution:
Given,
Length L = 2m
Resistance R =$46{\text{ }}\Omega $
Resistivity $\rho $=$1.84 \times {10^{ - 6}}\Omega {\text{m}}$
Formula of resistivity is given below,
$R = \dfrac{{\rho L}}{A}$
To find the value of A, putting the values of R, L and $\rho $
$\Rightarrow A = \dfrac{{\rho L}}{R}$
$\Rightarrow A = \dfrac{{1.84 \times {{10}^{ - 6}} \times 2}}{{46}}$
$\Rightarrow A = \dfrac{{3.68 \times {{10}^{ - 6}}}}{{46}}$
$\Rightarrow A = 0.08 \times {10^{ - 6}}{\text{ }}{{\text{m}}^2}$
Hence from above calculation we can see that the value of cross section of the wire is $A = 0.08 \times {10^{ - 6}}{\text{ }}{{\text{m}}^2}$.
Note: In this question, we have used the formula of resistivity $\rho $. Now we are going to understand more about resistivity. Resistivity of a wire is electrical resistance of that wire per unit cross sectional area and per unit length.
Resistivity is a property of the material of that wire. Resistivity has various applications in electronics. Resistivity is useful to compare metals, on the basis of their ability to conduct electric currents through them. High resistivity shows poor conductivity of that metal and low resistivity shows high conductivity of that metal. The unit of resistivity is $\Omega m$. The opposite of resistivity is conductivity. It shows how easily the current can and heat flow through that metal. The unit of conductivity is $\Omega {m^{ - 1}}$. It is also a measure to compare properties of different metals. There are some other types of conductivity also –
(a) The electrical conductivity of an electrolyte in solution is called Electrolytic conductivity.
(b) The conductivity due to ions moving in a crystal lattice is called Ionic conductivity.
(c) It is a property of a porous material’s ability to transmit water is called Hydraulic conductivity.
(d) The thermal conductivity of a material is its ability to conduct heat.
Complete step by step solution:
Given,
Length L = 2m
Resistance R =$46{\text{ }}\Omega $
Resistivity $\rho $=$1.84 \times {10^{ - 6}}\Omega {\text{m}}$
Formula of resistivity is given below,
$R = \dfrac{{\rho L}}{A}$
To find the value of A, putting the values of R, L and $\rho $
$\Rightarrow A = \dfrac{{\rho L}}{R}$
$\Rightarrow A = \dfrac{{1.84 \times {{10}^{ - 6}} \times 2}}{{46}}$
$\Rightarrow A = \dfrac{{3.68 \times {{10}^{ - 6}}}}{{46}}$
$\Rightarrow A = 0.08 \times {10^{ - 6}}{\text{ }}{{\text{m}}^2}$
Hence from above calculation we can see that the value of cross section of the wire is $A = 0.08 \times {10^{ - 6}}{\text{ }}{{\text{m}}^2}$.
Note: In this question, we have used the formula of resistivity $\rho $. Now we are going to understand more about resistivity. Resistivity of a wire is electrical resistance of that wire per unit cross sectional area and per unit length.
Resistivity is a property of the material of that wire. Resistivity has various applications in electronics. Resistivity is useful to compare metals, on the basis of their ability to conduct electric currents through them. High resistivity shows poor conductivity of that metal and low resistivity shows high conductivity of that metal. The unit of resistivity is $\Omega m$. The opposite of resistivity is conductivity. It shows how easily the current can and heat flow through that metal. The unit of conductivity is $\Omega {m^{ - 1}}$. It is also a measure to compare properties of different metals. There are some other types of conductivity also –
(a) The electrical conductivity of an electrolyte in solution is called Electrolytic conductivity.
(b) The conductivity due to ions moving in a crystal lattice is called Ionic conductivity.
(c) It is a property of a porous material’s ability to transmit water is called Hydraulic conductivity.
(d) The thermal conductivity of a material is its ability to conduct heat.
Recently Updated Pages
JEE Main 2026 Exam Date, Session 2 Updates, City Slip & Admit Card

NEET UG Exam Countdown 2026 – Days Left, Tracker & Tips

JEE Main 2026 Admit Card OUT LIVE Soon| Session 2 Direct Download Link

JEE Main 2026 Session 2 City Intimation Slip Expected Soon: Check How to Download

JEE Main 2026 Session 2 Application Form: Reopened Registration, Dates & Fees

JEE Main 2026 Session 2 Registration (Reopened): Last Date, Fees, Link & Process

Trending doubts
Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

Understanding the Angle of Deviation in a Prism

Understanding Differential Equations: A Complete Guide

Understanding the Block and Tackle System

Understanding Average and RMS Value in Electrical Circuits

Understanding Excess Pressure Inside a Liquid Drop

Other Pages
Dual Nature of Radiation and Matter Class 12 Physics Chapter 11 CBSE Notes - 2025-26

JEE Main Participating Colleges 2026 - A Complete List of Top Colleges

Formula for number of images formed by two plane mirrors class 12 physics JEE_Main

How to Convert a Galvanometer into an Ammeter or Voltmeter

Four Stroke Engine Explained: Working, Diagram, and Exam Insights

JEE Main 2022 June 27 Shift 1 Question Paper with Answer Keys & Solutions

