Question

Boojho stands at a just on the side of a plane mirror as shown in figure (1). Can he see himself in the mirror? Also can he see the image of objects situated at \[P\], \[Q\], \[R\]?

                                                         Figure (1)

Answer 1

Hint: In this question use the concept of the plane mirror. We can see the image of the object in between the mirror. The image formed behind the mirror is at the same distance at which the object is placed in front of the mirror.

Complete step by step answer
In the given figure (1), we are given three particles that are situated at points \[P\], \[Q\], \[R\]. We can say that Boojho can see an image of an object if the reflected ray can reach the eyes of the Boojho. Then, rays of point \[P\], and point \[Q\] can reach the eyes of the Boojho.
We know that the mirror forms a virtual image of the object behind the mirror at the same distance. At which the body or object is placed in front of the mirror.
Thus, the point \[A\] will form a virtual image \[A'\].
\[P'\] is the virtual image of the point \[P\] and \[Q'\] is the virtual image of the point \[Q\].
So, \[R'\] is the virtual image of the point \[R\].
Consider figure (2), virtual images of the objects are given below,

                                                                    Figure (2)
Since the mirror is not placed between point \[A\] and point \[A'\].
Boojho cannot see the image of his reflection. Now, the mirror is not placed between point \[R\] and point\[R'\]. So, Boojho cannot see the image of the reflection of the point \[R\]. The points \[P\], and the point \[Q\]. are in between the mirror. So, Boojho can see the images of \[P\], and \[Q\].

Therefore, Boojho cannot see the image that is behind the mirror and Boojho also cannot see the image of point \[R\].

Note
As we know that the image of an object is formed when the rays of light from the object falls on the mirror and reflects and then intersect. There are two types of images formed that are real and virtual. Plane mirrors always form virtual images.