
What is the basic cause of quantisation of charge?
Answer
232.8k+ views
Hint: If protons and electrons are the most fundamental particles and only charge carriers in the universe, then all the observable charges must be integral multiples of multiple electrons and protons.
Step by Step Answer
Charge quantization is the principle that the charge of an object is an integral multiple of the elementary charge.
Now, since protons and electrons are the only charge carriers in the universe, therefore all the observable charges must be integral multiple of electron. If an object contains $n$, electrons and ${n_2}$ protons, then the net charge on object is:
$ - {n_1}\left( e \right) + {n_2}\left( e \right) = \left( {{n_1} - {n_2}} \right)e$
Indeed, there are elementary particles other than protons and electrons, which carry charge. But all the elementary particles have charges which are integral multiple of $e$.. Thus charge on any object is always an integral multiple of $e$ and can be changed in steps of$e$, i.e. charge is quantized.
Note:
The step size $e$ is usually so small that we can easily neglect the quantization. If $l\,\mu \,C$ contains $n$ units of basic charge $e$ where,
$n = \dfrac{{l\,\mu \,C}}{{1.6 \times {{10}^{ - 19C}}}} = 6 \times {10^{12}}$
The step size is thus very small as compared to the charges usually found. Hence in many cases, we assume a continuous charge variation.
Step by Step Answer
Charge quantization is the principle that the charge of an object is an integral multiple of the elementary charge.
Now, since protons and electrons are the only charge carriers in the universe, therefore all the observable charges must be integral multiple of electron. If an object contains $n$, electrons and ${n_2}$ protons, then the net charge on object is:
$ - {n_1}\left( e \right) + {n_2}\left( e \right) = \left( {{n_1} - {n_2}} \right)e$
Indeed, there are elementary particles other than protons and electrons, which carry charge. But all the elementary particles have charges which are integral multiple of $e$.. Thus charge on any object is always an integral multiple of $e$ and can be changed in steps of$e$, i.e. charge is quantized.
Note:
The step size $e$ is usually so small that we can easily neglect the quantization. If $l\,\mu \,C$ contains $n$ units of basic charge $e$ where,
$n = \dfrac{{l\,\mu \,C}}{{1.6 \times {{10}^{ - 19C}}}} = 6 \times {10^{12}}$
The step size is thus very small as compared to the charges usually found. Hence in many cases, we assume a continuous charge variation.
Recently Updated Pages
JEE Main 2026 Session 2 Registration Open, Exam Dates, Syllabus & Eligibility

JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

Trending doubts
JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Why does capacitor block DC and allow AC class 12 physics JEE_Main

Understanding Average and RMS Value in Electrical Circuits

Understanding Collisions: Types and Examples for Students

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

Understanding Atomic Structure for Beginners

Other Pages
JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

CBSE Class 12 Physics Set 2 (55/2/2) 2025 Question Paper & Solutions

Inductive Effect and Its Role in Acidic Strength

Degree of Dissociation: Meaning, Formula, Calculation & Uses

Units and Measurements Mock Test for JEE Main 2025-26 Preparation

Chemistry Question Papers for JEE Main, NEET & Boards (PDFs)

