Atomic wt. of P is 31 and Sb is 120. What will be the atomic wt. of As, as per Dobernier triad rule?
A. 151
B. 75.5
C. 89.5
D. Unpredictable
Answer
261k+ views
Hint: If we are provided the atomic weight of the first and third elements of a triad, we can find the atomic wt. of the second one using Dobereiner’s triad rule i.e., by taking average of the two given atomic weights.
Complete step-by-step answer:
Dobereiner’s triads were groups of elements that have similar properties which were identified by the German chemist Johann Wolfgang Dobereiner. He observed that groups of three elements known as triads, could be formed in which all the elements will have similar physical and chemical properties.
He stated in his law of triads that the atomic mass of the second element in that triad is approximately equal to the arithmetic mean of the atomic masses of the first and third element in a triad. He further give a suggestion that this law could be extended to explain the other quantifiable properties of elements, like density.
Dobereiner’sfirst triad was identified in 1817 and was constituted by the three alkaline earth metals -calcium, strontium, and barium. He identified three more triads by the year 1829. These triads are shown below.
Using his triad rule, we can determine the atomic weight of arsenic (As) when the atomic weight of phosphorus(P) and antimony (Sb) is given, 31 and 120 respectively. Their average will result in the atomic weight of arsenic as per Dobereiner’s triad rule.
Atomic weight of As = \[\dfrac{{31 + 120}}{2} = \dfrac{{151}}{2} = 75.5\]
Hence, the correct option is (B).
Note: This triad rule has some limitations though. The identification of new elements made this model obsolete. Newly discovered elements and even several known elements did not fit into the triads. So, only a total of 5 Dobereiner’s triads were identified.
Complete step-by-step answer:
Dobereiner’s triads were groups of elements that have similar properties which were identified by the German chemist Johann Wolfgang Dobereiner. He observed that groups of three elements known as triads, could be formed in which all the elements will have similar physical and chemical properties.
He stated in his law of triads that the atomic mass of the second element in that triad is approximately equal to the arithmetic mean of the atomic masses of the first and third element in a triad. He further give a suggestion that this law could be extended to explain the other quantifiable properties of elements, like density.
Dobereiner’sfirst triad was identified in 1817 and was constituted by the three alkaline earth metals -calcium, strontium, and barium. He identified three more triads by the year 1829. These triads are shown below.
| Triad 1 | Atomicmasses | Triad 2 | Atomic masses | Triad 3 | Atomic masses | Triad 4 | Atomic masses | Triad 5 | Atomic masses |
| Lithium | 6.94 | calcium | 40.1 | chlorine | 35.4 | sulphur | 32.1 | iron | 55.8 |
| Sodium | 22.99 | strontium | 87.6 | bromine | 79.9 | selenium | 78.9 | cobalt | 58.9 |
| Potassium | 39.1 | barium | 137.3 | iodine | 126.9 | tellurium | 127.6 | nickel | 58.7 |
Using his triad rule, we can determine the atomic weight of arsenic (As) when the atomic weight of phosphorus(P) and antimony (Sb) is given, 31 and 120 respectively. Their average will result in the atomic weight of arsenic as per Dobereiner’s triad rule.
Atomic weight of As = \[\dfrac{{31 + 120}}{2} = \dfrac{{151}}{2} = 75.5\]
Hence, the correct option is (B).
Note: This triad rule has some limitations though. The identification of new elements made this model obsolete. Newly discovered elements and even several known elements did not fit into the triads. So, only a total of 5 Dobereiner’s triads were identified.
Recently Updated Pages
JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

Electricity and Magnetism Explained: Key Concepts & Applications

JEE Energetics Important Concepts and Tips for Exam Preparation

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

JEE Main Participating Colleges 2026 - A Complete List of Top Colleges

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Electric Field of a Uniformly Charged Ring

Understanding the Different Types of Solutions in Chemistry

Derivation of Equation of Trajectory Explained for Students

Other Pages
JEE Advanced 2026 Notification Out with Exam Date, Registration (Extended), Syllabus and More

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

CBSE Notes Class 11 Chemistry Chapter 5 - Thermodynamics - 2025-26

JEE Advanced Weightage Chapter Wise 2026 for Physics, Chemistry, and Mathematics

Understanding Atomic Structure for Beginners

How to Convert a Galvanometer into an Ammeter or Voltmeter

