Answer
Verified
88.8k+ views
Hint: In order to answer this question, you should know that in alkali metals the ionization energy decreases down the group with increasing atomic size, which leads to addition of new atomic shells.
Complete step by step answer:
As we know alkali metals are very good reducing agents because of their great tendency to lose electrons. An element which acts as a reducing agent must have low ionization energy. Alkali metals act as strong reducing agents as their ionization energy values are low. As we already know ionization decreases on moving down from Li to Cs, the reducing property increases in the same order. Thus, Li is the weakest reducing agent while Cs is the strongest reducing agent among alkali metals in free gaseous state.
The oxidation potential value is nothing but the tendency of an element to lose electrons in solution is measured by its oxidation potential value. As we know, alkali metals have high oxidation potential values, these are strong oxidizing agents.
Lithium being small in size has high ionization enthalpy and because of its small size it is extensively hydrated and has a very high hydration enthalpy. Thus lithium has a greater tendency to lose electrons in solution than other alkali metals. Therefore, lithium is the strongest reducing agent.
Hence, the assertion is incorrect but the reason is correct. Therefore, option C is the required answer.
Note: You should know that lithium and magnesium form monoxides when heated in air or oxygen while other alkali metals form peroxides or super-oxides.
Complete step by step answer:
As we know alkali metals are very good reducing agents because of their great tendency to lose electrons. An element which acts as a reducing agent must have low ionization energy. Alkali metals act as strong reducing agents as their ionization energy values are low. As we already know ionization decreases on moving down from Li to Cs, the reducing property increases in the same order. Thus, Li is the weakest reducing agent while Cs is the strongest reducing agent among alkali metals in free gaseous state.
The oxidation potential value is nothing but the tendency of an element to lose electrons in solution is measured by its oxidation potential value. As we know, alkali metals have high oxidation potential values, these are strong oxidizing agents.
Lithium being small in size has high ionization enthalpy and because of its small size it is extensively hydrated and has a very high hydration enthalpy. Thus lithium has a greater tendency to lose electrons in solution than other alkali metals. Therefore, lithium is the strongest reducing agent.
Hence, the assertion is incorrect but the reason is correct. Therefore, option C is the required answer.
Note: You should know that lithium and magnesium form monoxides when heated in air or oxygen while other alkali metals form peroxides or super-oxides.
Recently Updated Pages
Name the scale on which the destructive energy of an class 11 physics JEE_Main
Write an article on the need and importance of sports class 10 english JEE_Main
Choose the exact meaning of the given idiomphrase The class 9 english JEE_Main
Choose the one which best expresses the meaning of class 9 english JEE_Main
What does a hydrometer consist of A A cylindrical stem class 9 physics JEE_Main
A motorcyclist of mass m is to negotiate a curve of class 9 physics JEE_Main
Other Pages
If a wire of resistance R is stretched to double of class 12 physics JEE_Main
Formula for number of images formed by two plane mirrors class 12 physics JEE_Main
A passenger in an aeroplane shall A Never see a rainbow class 12 physics JEE_Main
Electric field due to uniformly charged sphere class 12 physics JEE_Main
Velocity of car at t 0 is u moves with a constant acceleration class 11 physics JEE_Main