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# An example of perfect diamagnetic is a superconductor. This implies that when a superconductor is put in magnetic field of intensity $B$, the magnetic field ${B_S}$ inside the superconductor will be such that:A) ${B_S} = - B$B) ${B_S} = 0$C) ${B_S} = B$D) ${B_S} < B$ but ${B_S} \ne 0$

Last updated date: 11th Aug 2024
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Hint: Just keep in mind that a superconductor is said to be in the Meissner effect when there is no magnetic field inside it. Also. Meissner effect is originated when the current is induced in the superconductor to reject the magnetic field lines.

Complete step by step solution:
Firstly, A superconductor is a conductor that does not allow the magnetic field lines to pass through it. This effect of not allowing magnetic field lines to pass is known as Meissner’s effect. This effect happens because an induced current is set up inside the semiconductor so that on the application of an external magnetic field the superconductor faces zero resistance and the field produced by the induced current cancels the applied field.

Now, as we know, a diamagnetic substance tends to repel the magnetic field lines passing through it. Therefore, for the perfect semiconductor or superconductor, the field would not enter the superconductor. Hence, magnetic field lines inside the superconductor will be zero. Hence, we can say that the magnetic field inside the superconductor is ${B_S} = 0$ .

Hence, option (B) is the correct option.

${\Delta ^2}H = {\lambda ^{ - 2}}H$
Here, $H$ is the magnetic field and $\lambda$ is the penetration depth. This equation shows that the magnetic field in a superconductor decays exponentially. This process of exclusion of the magnetic field is the demonstration of the super demagnetisation.