
Among the following, the molecule with the lowest dipole moment is
A \[\text{CHC}{{\text{l}}_{\text{3}}}\]
B \[\text{C}{{\text{H}}_{3}}\text{Cl}\]
C \[\text{C}{{\text{H}}_{2}}\text{C}{{\text{l}}_{2}}\]
D \[\text{CC}{{\text{l}}_{\text{4}}}\]
Answer
221.1k+ views
Hint: In any system where there is a charge separation, a dipole moment develops. Therefore, they can occur in both covalent and ionic bonds. The difference in electronegativity between two atoms that are chemically linked causes dipole moments.
Complete step-by-step answer:The polarity of a chemical bond between two atoms in a molecule is gauged by the bond dipole moment. It involves the idea of an electric dipole moment, which is a gauge of how far apart a system's positive and negative charges are from one another. Since the bond dipole moment has both a magnitude and a direction, it is a vector quantity. Note that the two electric charges that form in a molecule and have equal magnitudes but opposite signs are denoted by the letters ${{\delta }^{+}}$ and ${{\delta }^{-}}$. They are separated by a predetermined distance, often represented by the letter "d."
The bond dipole moment, which is distinct from the molecule's overall dipole moment, is the dipole moment of a single bond in a polyatomic molecule.
It is a vector quantity, meaning it has a specific magnitude and direction.
Being a vector quantity, it is also possible for it to equal zero because the two bond dipoles can cancel one another out.
A little arrow with its head on the positive centre and tail on the negative centre is typically used to represent it.
The dipole moment in chemistry is denoted by a modest modification of the arrow sign. On the positive centre and the negative centre, there is a cross to indicate it.
The lowest (zero) dipole moment is in \[\text{CC}{{\text{l}}_{\text{4}}}\]. Its symmetrical tetrahedral structure is the reason for this. Due to this, the opposite dipole moment of the other three bonds cancels out the dipole moment of one bond.
Option ‘D’ is correct
Note: Another vector quantity with a direction parallel to the bond axis is the bond dipole moment ($\mu $). The arrows used to depict dipole moments in chemistry start at the positive charge and stop at the negative charge.
The electrons usually shift from their initial positions to get closer to the more electronegative atom when two atoms with different electronegativities contact. The bond dipole moment can be used to visualise this electron motion.
Complete step-by-step answer:The polarity of a chemical bond between two atoms in a molecule is gauged by the bond dipole moment. It involves the idea of an electric dipole moment, which is a gauge of how far apart a system's positive and negative charges are from one another. Since the bond dipole moment has both a magnitude and a direction, it is a vector quantity. Note that the two electric charges that form in a molecule and have equal magnitudes but opposite signs are denoted by the letters ${{\delta }^{+}}$ and ${{\delta }^{-}}$. They are separated by a predetermined distance, often represented by the letter "d."
The bond dipole moment, which is distinct from the molecule's overall dipole moment, is the dipole moment of a single bond in a polyatomic molecule.
It is a vector quantity, meaning it has a specific magnitude and direction.
Being a vector quantity, it is also possible for it to equal zero because the two bond dipoles can cancel one another out.
A little arrow with its head on the positive centre and tail on the negative centre is typically used to represent it.
The dipole moment in chemistry is denoted by a modest modification of the arrow sign. On the positive centre and the negative centre, there is a cross to indicate it.
The lowest (zero) dipole moment is in \[\text{CC}{{\text{l}}_{\text{4}}}\]. Its symmetrical tetrahedral structure is the reason for this. Due to this, the opposite dipole moment of the other three bonds cancels out the dipole moment of one bond.
Option ‘D’ is correct
Note: Another vector quantity with a direction parallel to the bond axis is the bond dipole moment ($\mu $). The arrows used to depict dipole moments in chemistry start at the positive charge and stop at the negative charge.
The electrons usually shift from their initial positions to get closer to the more electronegative atom when two atoms with different electronegativities contact. The bond dipole moment can be used to visualise this electron motion.
Recently Updated Pages
Difference Between Alcohol and Phenol: Structure, Tests & Uses

Classification of Drugs in Chemistry: Types, Examples & Exam Guide

Class 12 Chemistry Mock Test Series for JEE Main – Free Online Practice

Is PPh3 a strong ligand class 12 chemistry JEE_Main

Full name of DDT is A 111trichloro22bispchlorophenyl class 12 chemistry JEE_Main

Sodium acetate on heating with soda lime produce A class 12 chemistry JEE_Main

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

How to Convert a Galvanometer into an Ammeter or Voltmeter

Degree of Dissociation: Meaning, Formula, Calculation & Uses

Other Pages
Solutions Class 12 Chemistry Chapter 1 CBSE Notes - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 1 Solutions - 2025-26

The D and F Block Elements Class 12 Chemistry Chapter 4 CBSE Notes - 2025-26

NCERT Solutions for Class 12 Chemistry Chapter Chapter 7 Alcohol Phenol and Ether

NCERT Solutions ForClass 12 Chemistry Chapter Chapter 8 Aldehydes Ketones And Carboxylic Acids

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

