Question

A wire of resistance 12 ohms per meter is bent to form a square of total length 10 cm. The resistance between its two farthest points is
A) $1.2\Omega $
B) $6\Omega $
C) $1.5\Omega $
D) $2.8\Omega $

Answer 1

Hint:The problem is from the current electricity part of physics. This is a direct question and we can apply the concept of resistance here. Use the relationship between resistance and length of the wire to solve the problem.




Complete answer:
Here, the resistance of the wire is 12 ohms per meter.
That means 1 m length of wire is having 12 ohm resistance.

That implies 10 cm = 0.1 m length wire will have
$R = 12 \times 0.1 = 1.2\Omega {m^{ - 1}}$

Hence, the correct option is Option (A).




Note: When electrons move through a conductor, such as a metal wire, an electric current occurs. Electrons in motion can clash with ions in the metal. This makes the current flow more complex and generates resistance. While solving this question pay close attention to circuits and terminals in which these resistances are connected and apply the concepts of parallel combination and series combination of resistance accordingly.