
A toy balloon can occupy 500ml at 27 \[^\circ C\]. The maximum stretching capacity of the balloon is three times the volume at 27 \[^\circ C\]. The temperature above which the balloon which the balloon will burst, if pressure of the balloon does not change
A. 300 K
B. 900 K
C. 625 \[^\circ C\]
D. 225 \[^\circ C\]
Answer
137.7k+ views
Hint: For solving this question, we must follow the following steps: first find a relation between the temperature and volume of the gas. Remember, the condition given to us is that the pressure is constant. So we won’t be needing pressure in this relationship. Then we must simply substitute the values and obtain the value for \[T{}_2\]
Formula used: \[\dfrac{{T{}_1}}{{T{}_2}}\,\alpha \,\dfrac{{V{}_1}}{{V{}_2}}\]
Complete Step-by-Step Answer:
For solving this question, we must know the following relation: for any given gas, the volume of the gas is directly proportional to the temperature of the gas. To put this in simpler words, we can say that if the value of the temperature of the gas is increasing, then the value of the volume of the gas will also increase in a linear manner. This relation can be represented as:
\[T\,\alpha \,V\]
When considering two sets of values for the temperature and pressure of the gas, this relation can be represented as:
\[\dfrac{{T{}_1}}{{T{}_2}}\,\alpha \,\dfrac{{V{}_1}}{{V{}_2}}\]
In the given problem, the values of these quantities are given as:
\[T{}_1\] = 27 \[^\circ C\]= 300 K
\[V{}_1\] = 500 ml
\[V{}_2\] = maximum volume of the balloon = \[3{\text{ }}\left( {500} \right){\text{ }} = {\text{ }}1500\] ml
\[T{}_2\] = ?
Hence, the value of \[T{}_2\] can be found as:
\[\dfrac{{300}}{{T{}_2}}\, = \,\dfrac{{500}}{{1500}}\]
\[T{}_2\] = 900 K
Hence, Option B is the correct option.
Note: The ideal gas law, also called the general gas equation, is the equation of state of a hypothetical ideal gas. It is a good approximation of the behaviour of many gases under many conditions, although it has several limitations. The equation for the ideal gas law can be given as:
PV = nRT
This helps us find the relations between the different physical parameters of the given gas.
Formula used: \[\dfrac{{T{}_1}}{{T{}_2}}\,\alpha \,\dfrac{{V{}_1}}{{V{}_2}}\]
Complete Step-by-Step Answer:
For solving this question, we must know the following relation: for any given gas, the volume of the gas is directly proportional to the temperature of the gas. To put this in simpler words, we can say that if the value of the temperature of the gas is increasing, then the value of the volume of the gas will also increase in a linear manner. This relation can be represented as:
\[T\,\alpha \,V\]
When considering two sets of values for the temperature and pressure of the gas, this relation can be represented as:
\[\dfrac{{T{}_1}}{{T{}_2}}\,\alpha \,\dfrac{{V{}_1}}{{V{}_2}}\]
In the given problem, the values of these quantities are given as:
\[T{}_1\] = 27 \[^\circ C\]= 300 K
\[V{}_1\] = 500 ml
\[V{}_2\] = maximum volume of the balloon = \[3{\text{ }}\left( {500} \right){\text{ }} = {\text{ }}1500\] ml
\[T{}_2\] = ?
Hence, the value of \[T{}_2\] can be found as:
\[\dfrac{{300}}{{T{}_2}}\, = \,\dfrac{{500}}{{1500}}\]
\[T{}_2\] = 900 K
Hence, Option B is the correct option.
Note: The ideal gas law, also called the general gas equation, is the equation of state of a hypothetical ideal gas. It is a good approximation of the behaviour of many gases under many conditions, although it has several limitations. The equation for the ideal gas law can be given as:
PV = nRT
This helps us find the relations between the different physical parameters of the given gas.
Recently Updated Pages
How to find Oxidation Number - Important Concepts for JEE

How Electromagnetic Waves are Formed - Important Concepts for JEE

Electrical Resistance - Important Concepts and Tips for JEE

Average Atomic Mass - Important Concepts and Tips for JEE

Chemical Equation - Important Concepts and Tips for JEE

Concept of CP and CV of Gas - Important Concepts and Tips for JEE

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

Electromagnetic radiation with maximum wavelength is class 11 chemistry JEE_Main

JEE Main 2025: Derivation of Equation of Trajectory in Physics

The correct order of electron affinity is A F Cl Br class 11 chemistry JEE_Main

Learn About Angle Of Deviation In Prism: JEE Main Physics 2025

Number of sigma and pi bonds in C2 molecule isare A class 11 chemistry JEE_Main

Other Pages
NCERT Solutions for Class 11 Chemistry Chapter 9 Hydrocarbons

NCERT Solutions for Class 11 Chemistry Chapter 7 Redox Reaction

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 11 Chemistry Chapter 5 Thermodynamics

Hydrocarbons Class 11 Notes: CBSE Chemistry Chapter 9

NCERT Solutions for Class 11 Chemistry In Hindi Chapter 1 Some Basic Concepts of Chemistry
