Answer
64.8k+ views
Hint: The concept of the Left-hand rule can be used to solve this problem. When a current-carrying conductor/wire is placed in a magnetic field, a force is exerted on the wire.
Hence Fleming gave a simple rule to determine the direction of force acting on a current-carrying conductor/wire placed in a magnetic field. This can be used to calculate the force of nature.
Complete step by step answer:
If the direction of electric currents flowing in two parallel straight conductors is the same then they will attract each other.
If the direction of electric currents flowing two parallel straight conductors are opposite then they repel each other.
In this question, current $({I_1})$ produces a magnetic field around it which at any point on current $({I_2})$carrying wire is,
${B_1} = \dfrac{{{\mu _0}{I_1}}}{{2\pi a}}$ Directed inwards perpendicular to planes or wires
So current $({I_2})$ carrying wire then experiences a force due to its magnetic field which on its length $l$ given by,
$\Rightarrow F = {I_2}l{B_1}\sin {90^ \circ }$
$\Rightarrow F = {I_2}l \times \dfrac{{{\mu _0}{I_1}{I_2}}}{{2\pi a}}$
Or,\[\] $F = \dfrac{{{\mu _0}{I_1}{I_2}}}{{2\pi a}}l$
So force per unit length than the two wires exert on each other is,
$\Rightarrow f = \dfrac{F}{L}$
Hence \[f = \dfrac{{{\mu _0}{I_1}{I_2}}}{{2\pi a}}\]
The answer will be $\left( A \right),$ thus nullifying other options.
Note: The strong force of nature is considered as the most powerful force. The electric, weak, and gravitational forces are followed in decreasing order.
Despite its strength, because of its exceedingly small range, the strong force does not manifest itself in the macroscopic universe.
When a current-carrying wire is placed in a magnetic field of another current-carrying wire, it experiences a magnetic force.
The direction of the force depends on the direction of the magnetic field as well as the current and is perpendicular to it.
Hence Fleming gave a simple rule to determine the direction of force acting on a current-carrying conductor/wire placed in a magnetic field. This can be used to calculate the force of nature.
Complete step by step answer:
If the direction of electric currents flowing in two parallel straight conductors is the same then they will attract each other.
If the direction of electric currents flowing two parallel straight conductors are opposite then they repel each other.
In this question, current $({I_1})$ produces a magnetic field around it which at any point on current $({I_2})$carrying wire is,
${B_1} = \dfrac{{{\mu _0}{I_1}}}{{2\pi a}}$ Directed inwards perpendicular to planes or wires
So current $({I_2})$ carrying wire then experiences a force due to its magnetic field which on its length $l$ given by,
$\Rightarrow F = {I_2}l{B_1}\sin {90^ \circ }$
$\Rightarrow F = {I_2}l \times \dfrac{{{\mu _0}{I_1}{I_2}}}{{2\pi a}}$
Or,\[\] $F = \dfrac{{{\mu _0}{I_1}{I_2}}}{{2\pi a}}l$
So force per unit length than the two wires exert on each other is,
$\Rightarrow f = \dfrac{F}{L}$
Hence \[f = \dfrac{{{\mu _0}{I_1}{I_2}}}{{2\pi a}}\]
The answer will be $\left( A \right),$ thus nullifying other options.
Note: The strong force of nature is considered as the most powerful force. The electric, weak, and gravitational forces are followed in decreasing order.
Despite its strength, because of its exceedingly small range, the strong force does not manifest itself in the macroscopic universe.
When a current-carrying wire is placed in a magnetic field of another current-carrying wire, it experiences a magnetic force.
The direction of the force depends on the direction of the magnetic field as well as the current and is perpendicular to it.
Recently Updated Pages
Write a composition in approximately 450 500 words class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Arrange the sentences P Q R between S1 and S5 such class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What is the common property of the oxides CONO and class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What happens when dilute hydrochloric acid is added class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
If four points A63B 35C4 2 and Dx3x are given in such class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The area of square inscribed in a circle of diameter class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Other Pages
A boat takes 2 hours to go 8 km and come back to a class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Electric field due to uniformly charged sphere class 12 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
In the ground state an element has 13 electrons in class 11 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
According to classical free electron theory A There class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Differentiate between homogeneous and heterogeneous class 12 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Excluding stoppages the speed of a bus is 54 kmph and class 11 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)