Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store

A square loop of a side ‘a’ is placed at ‘a’ distance away from a long wire carrying a current ${I_1}$. If the loop carries as current ${I_2}$ as shown in figure. Then the nature of the force and its amount is:

$\left( A \right)$ \[\dfrac{{{\mu _0}{I_1}{I_2}}}{{2\pi a}}\], attractive
$\left( B \right)$ \[\dfrac{{{\mu _0}{I_1}{I_2}}}{{4\pi }}\], attractive
$\left( C \right)$ \[\dfrac{{{\mu _0}{I_1}{I_2}}}{{4\pi }}\], repulsive
$\left( D \right)$ \[\dfrac{{{\mu _0}{I_1}{I_2}}}{{4\pi a}}\], repulsive

seo-qna
Last updated date: 17th Jun 2024
Total views: 53.1k
Views today: 0.53k
Answer
VerifiedVerified
53.1k+ views
Hint: The concept of the Left-hand rule can be used to solve this problem. When a current-carrying conductor/wire is placed in a magnetic field, a force is exerted on the wire.
Hence Fleming gave a simple rule to determine the direction of force acting on a current-carrying conductor/wire placed in a magnetic field. This can be used to calculate the force of nature.

Complete step by step answer:
If the direction of electric currents flowing in two parallel straight conductors is the same then they will attract each other.
If the direction of electric currents flowing two parallel straight conductors are opposite then they repel each other.
In this question, current $({I_1})$ produces a magnetic field around it which at any point on current $({I_2})$carrying wire is,
${B_1} = \dfrac{{{\mu _0}{I_1}}}{{2\pi a}}$ Directed inwards perpendicular to planes or wires
So current $({I_2})$ carrying wire then experiences a force due to its magnetic field which on its length $l$ given by,
$\Rightarrow F = {I_2}l{B_1}\sin {90^ \circ }$
$\Rightarrow F = {I_2}l \times \dfrac{{{\mu _0}{I_1}{I_2}}}{{2\pi a}}$
Or,\[\] $F = \dfrac{{{\mu _0}{I_1}{I_2}}}{{2\pi a}}l$
So force per unit length than the two wires exert on each other is,
$\Rightarrow f = \dfrac{F}{L}$
Hence \[f = \dfrac{{{\mu _0}{I_1}{I_2}}}{{2\pi a}}\]

The answer will be $\left( A \right),$ thus nullifying other options.

Note: The strong force of nature is considered as the most powerful force. The electric, weak, and gravitational forces are followed in decreasing order.
Despite its strength, because of its exceedingly small range, the strong force does not manifest itself in the macroscopic universe.
When a current-carrying wire is placed in a magnetic field of another current-carrying wire, it experiences a magnetic force.
The direction of the force depends on the direction of the magnetic field as well as the current and is perpendicular to it.