
A short magnetic needle is pivoted in a uniform magnetic field of induction 1T. Now, simultaneoulsy another magnetic field of induction $\sqrt 3 T$ is applied at right angles to the first field; the needle deflects through an angle $\theta $ where its value is
A. ${30^ \circ }$
B. ${45^ \circ }$
C. ${90^ \circ }$
D. ${60^ \circ }$
Answer
221.1k+ views
Hint: For solving these types of questions, we need to know about the angle of dip. Since the dip circle is positioned on a horizontal surface, a change in the dip needle will affect the horizontal component. Due to these fields that are applied to the needle, the magnet acquires an equilibrium state.
Formula used:
${B_1} = B\tan \theta $
where $\theta $ defines the angle through which the needle deflects.
Complete step by step solution:
We are aware that the portion of a material's magnetic field that results from an external current and is not intrinsic to the material itself is known as magnetic field strength, also known as magnetic intensity or magnetic field intensity. It is measured in amperes per metre and represented as the vector H.
We can also draw the conclusion that an angle is a measurement of how far an object is moving from its intended course. Measured between the line of sight to the target and the line of sight to the aiming point, the angle of a deflection shot in gunnery. From the given,
$B = 1T$ and ${B_1} = \sqrt 3 T$
We know that,
${B_1} = B\tan \theta $
where $\theta $ defines the angle through which the needle deflects.
Substituting the values we get
$\sqrt 3 = 1\tan \theta $
$ \therefore \theta = {60^ \circ }$
Hence, option D is the correct answer.
Note: It is important to keep in mind the following facts about the magnetic field:
- There are two different types of magnetic fields: the B-field and the H-field.
- Teslas are used to measure B-field (T). A/m units are used to express the H-field.
- The earth's magnetic field is oriented so that it extends from its magnetic north pole to its magnetic south pole. The inclined bar magnet is merely a fictitious magnet; it does not exist.
Formula used:
${B_1} = B\tan \theta $
where $\theta $ defines the angle through which the needle deflects.
Complete step by step solution:
We are aware that the portion of a material's magnetic field that results from an external current and is not intrinsic to the material itself is known as magnetic field strength, also known as magnetic intensity or magnetic field intensity. It is measured in amperes per metre and represented as the vector H.
We can also draw the conclusion that an angle is a measurement of how far an object is moving from its intended course. Measured between the line of sight to the target and the line of sight to the aiming point, the angle of a deflection shot in gunnery. From the given,
$B = 1T$ and ${B_1} = \sqrt 3 T$
We know that,
${B_1} = B\tan \theta $
where $\theta $ defines the angle through which the needle deflects.
Substituting the values we get
$\sqrt 3 = 1\tan \theta $
$ \therefore \theta = {60^ \circ }$
Hence, option D is the correct answer.
Note: It is important to keep in mind the following facts about the magnetic field:
- There are two different types of magnetic fields: the B-field and the H-field.
- Teslas are used to measure B-field (T). A/m units are used to express the H-field.
- The earth's magnetic field is oriented so that it extends from its magnetic north pole to its magnetic south pole. The inclined bar magnet is merely a fictitious magnet; it does not exist.
Recently Updated Pages
[Awaiting input: Please provide the content from "Ask AI Response," "Competitor 1," and "Competitor 2," so I can perform the analysis and synthesize the requested metadata and headings.]

Young’s Double Slit Experiment Derivation Explained

A square frame of side 10 cm and a long straight wire class 12 physics JEE_Main

The work done in slowly moving an electron of charge class 12 physics JEE_Main

Two identical charged spheres suspended from a common class 12 physics JEE_Main

According to Bohrs theory the timeaveraged magnetic class 12 physics JEE_Main

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Understanding Uniform Acceleration in Physics

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Dual Nature of Radiation and Matter Class 12 Physics Chapter 11 CBSE Notes - 2025-26

Degree of Dissociation: Meaning, Formula, Calculation & Uses

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

Understanding the Electric Field of a Uniformly Charged Ring

Understanding Electromagnetic Waves and Their Importance

