
A radioactive nucleus emits a beta particle. The parent and daughter nuclei are
A. Isotopes
B. Isotones
C. Isomers
D. Isobars
Answer
162.3k+ views
Hint:In the given question, we need to find the parent and daughter nuclei of a beta particle. For this, we will give an example of emission of a beta particle.
Complete step by step solution:
We know that \[\beta = {}_{ - 1}{e^0}\].
Also, the atomic mass of any nucleus that produces a beta particle remains constant, however the atomic number increases by one.
Mathematically, it can be expressed as
\[{}_Z{P^A} \to {}_{Z+1}{D^A} + {\beta ^ - }\]
Here, in the above situation, we observed that the daughter's atomic number is boosted by one, although those of her parent and daughter nuclei have equal mass number. As a result, the parent and daughter nuclei are isobars.
Therefore, the correct option is D.
Additional Information: Isobars are atoms (nuclides) of various chemical elements that have varying chemical characteristics but have the same physical characteristics. So, we can define isobars as elements with the same mass number but just a different atomic number. Additionally because of the variation in electron counts, they have different chemical properties. Because more neutrons make up for more nucleons, an isobar has a different atomic number but has the same atomic mass. Also, in addition to that, we can say that for cancer treatment, isobars of cobalt can be used.
Note: Many students may write only the explanation regarding isobars but by giving an example we can get a clear idea about the solution. Thus, it is necessary to give an example of beta emission. Moreover, the elements with a different atomic number but the same mass number are referred to as isobars. Isotopes, on the other hand, are elements with the same atomic number but varying masses.
Complete step by step solution:
We know that \[\beta = {}_{ - 1}{e^0}\].
Also, the atomic mass of any nucleus that produces a beta particle remains constant, however the atomic number increases by one.
Mathematically, it can be expressed as
\[{}_Z{P^A} \to {}_{Z+1}{D^A} + {\beta ^ - }\]
Here, in the above situation, we observed that the daughter's atomic number is boosted by one, although those of her parent and daughter nuclei have equal mass number. As a result, the parent and daughter nuclei are isobars.
Therefore, the correct option is D.
Additional Information: Isobars are atoms (nuclides) of various chemical elements that have varying chemical characteristics but have the same physical characteristics. So, we can define isobars as elements with the same mass number but just a different atomic number. Additionally because of the variation in electron counts, they have different chemical properties. Because more neutrons make up for more nucleons, an isobar has a different atomic number but has the same atomic mass. Also, in addition to that, we can say that for cancer treatment, isobars of cobalt can be used.
Note: Many students may write only the explanation regarding isobars but by giving an example we can get a clear idea about the solution. Thus, it is necessary to give an example of beta emission. Moreover, the elements with a different atomic number but the same mass number are referred to as isobars. Isotopes, on the other hand, are elements with the same atomic number but varying masses.
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