
A proton is moving along the Z-axis in a magnetic field. The magnetic field is along the X axis. The proton will experience a force along
A. X-axis
B. Y-axis
C. Z-axis
D. Negative Z-axis
Answer
219.3k+ views
Hint: The force experienced by a point charge due to an electric and magnetic force due to electromagnetic forces is given by Lorentz force. It is also known as electromagnetic force.
Formula used:
The magnetic force is proportional to electric charge ‘q’ of the particle and to the magnitude of vector cross product of velocity ‘v’ and the magnetic field ‘B’.
Mathematically it is written as
\[F = q(\overrightarrow v \times \overrightarrow B )\]
Complete answer:
When a charged particle moves in a magnetic field it experiences a force. Given that the velocity of the proton is along Z-axis and magnetic field is along X-axis, therefore, the direction of force on a charged particle will be given by
\[F = \widehat v \times \widehat B\]
\[F = ( + \widehat k) \times ( + \widehat i)\]
\[F = + \widehat j\]
That means the moving proton will experience a force along the Y-axis.
Hence, Option B is the correct answer.
Note: The direction of Lorentz force acting on the charged particle is perpendicular to the magnetic field and the charge moving which can easily be explained by Lorentz Force Right Hand Rule. If the electric field, magnetic field and direction of velocity are parallel, the charge is moving in rectilinear motion. But if the direction of velocity is perpendicular to electric and magnetic fields and both fields are parallel to each other, then the charge will be moving due to the electric field and hence move in a circular motion.
Formula used:
The magnetic force is proportional to electric charge ‘q’ of the particle and to the magnitude of vector cross product of velocity ‘v’ and the magnetic field ‘B’.
Mathematically it is written as
\[F = q(\overrightarrow v \times \overrightarrow B )\]
Complete answer:
When a charged particle moves in a magnetic field it experiences a force. Given that the velocity of the proton is along Z-axis and magnetic field is along X-axis, therefore, the direction of force on a charged particle will be given by
\[F = \widehat v \times \widehat B\]
\[F = ( + \widehat k) \times ( + \widehat i)\]
\[F = + \widehat j\]
That means the moving proton will experience a force along the Y-axis.
Hence, Option B is the correct answer.
Note: The direction of Lorentz force acting on the charged particle is perpendicular to the magnetic field and the charge moving which can easily be explained by Lorentz Force Right Hand Rule. If the electric field, magnetic field and direction of velocity are parallel, the charge is moving in rectilinear motion. But if the direction of velocity is perpendicular to electric and magnetic fields and both fields are parallel to each other, then the charge will be moving due to the electric field and hence move in a circular motion.
Recently Updated Pages
Chemical Equation - Important Concepts and Tips for JEE

JEE Main 2022 (July 29th Shift 1) Chemistry Question Paper with Answer Key

Conduction Explained: Definition, Examples & Science for Students

Analytical Method of Vector Addition Explained Simply

Atomic Size - Important Concepts and Tips for JEE

JEE Main 2022 (June 29th Shift 1) Maths Question Paper with Answer Key

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Understanding Uniform Acceleration in Physics

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Understanding Atomic Structure for Beginners

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding Centrifugal Force in Physics

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Degree of Dissociation: Meaning, Formula, Calculation & Uses

