
A piece of copper and another of germanium are cooled from room temperature to $100K$. What will happen to their conductivities? Explain.
Answer
214.2k+ views
Hint: The behavior of conductor and semiconductor varies to the change in temperature. Here copper is a conductor and germanium is a semiconductor. To know about the conductivity, we want to know how the resistance changes according to temperature.
Complete solution:
We are given a piece of copper which is a conductor and a piece of germanium which is a semiconductor. These two pieces are cooled to $100K$ from the room temperature. The temperature decreases.
The resistance of the conductor is proportional to the temperature.
$R \propto T$
When the temperature decreases the resistance also decreases. This leads to the conductivity to increase. So, the rise in temperature can decrease the electrical conductivity of the conductor. When the temperature is raised this will cause the electrons in the conduction band to collide each other. This will gradually decrease the conductivity.
In the case of a semiconductor, the resistance is inversely proportional to the temperature.
$R \propto \dfrac{1}{T}$
Therefore, when the temperature decreases the resistance of the semiconductor will increase. And this leads to conductivity to decrease. So, the rise in temperature can increase the electrical conductivity of the semiconductor. When the temperature is raised in the semiconductor more electrons will occupy the conduction band thus increasing the conductivity.
Thus, when the temperature is decreased to $100K$ from temperature the conductivity of copper increases and conductivity of germanium decreases.
Note: We have to note that the resistance and the conductivity are inversely proportional. The metal has resistance means it resists the movement of electrons. This will decrease the conductivity hence the conductance is through electrons.
Complete solution:
We are given a piece of copper which is a conductor and a piece of germanium which is a semiconductor. These two pieces are cooled to $100K$ from the room temperature. The temperature decreases.
The resistance of the conductor is proportional to the temperature.
$R \propto T$
When the temperature decreases the resistance also decreases. This leads to the conductivity to increase. So, the rise in temperature can decrease the electrical conductivity of the conductor. When the temperature is raised this will cause the electrons in the conduction band to collide each other. This will gradually decrease the conductivity.
In the case of a semiconductor, the resistance is inversely proportional to the temperature.
$R \propto \dfrac{1}{T}$
Therefore, when the temperature decreases the resistance of the semiconductor will increase. And this leads to conductivity to decrease. So, the rise in temperature can increase the electrical conductivity of the semiconductor. When the temperature is raised in the semiconductor more electrons will occupy the conduction band thus increasing the conductivity.
Thus, when the temperature is decreased to $100K$ from temperature the conductivity of copper increases and conductivity of germanium decreases.
Note: We have to note that the resistance and the conductivity are inversely proportional. The metal has resistance means it resists the movement of electrons. This will decrease the conductivity hence the conductance is through electrons.
Recently Updated Pages
Chemical Equation - Important Concepts and Tips for JEE

JEE Main 2022 (July 29th Shift 1) Chemistry Question Paper with Answer Key

Conduction, Transfer of Energy Important Concepts and Tips for JEE

JEE Analytical Method of Vector Addition Important Concepts and Tips

Atomic Size - Important Concepts and Tips for JEE

JEE Main 2022 (June 29th Shift 1) Maths Question Paper with Answer Key

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

JEE Main Correction Window 2026 Session 1 Dates Announced - Edit Form Details, Dates and Link

Equation of Trajectory in Projectile Motion: Derivation & Proof

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Hybridisation in Chemistry – Concept, Types & Applications

Angle of Deviation in a Prism – Formula, Diagram & Applications

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Collision: Meaning, Types & Examples in Physics

Atomic Structure: Definition, Models, and Examples

Degree of Dissociation: Meaning, Formula, Calculation & Uses

How to Convert a Galvanometer into an Ammeter or Voltmeter

Average and RMS Value in Physics: Formula, Comparison & Application

