
A mixture of benzene and aniline can be separated by:
A. Hot water
B. Dil. HCl
C. Dil. NaOH
D. Alcohol
Answer
225k+ views
Hint: Benzene is the cyclic compound of the formula \[{{\rm{C}}_{\rm{6}}}{{\rm{H}}_{\rm{6}}}\] . Aniline is also a substituted benzene compound, where, one hydrogen atom of benzene ring is replaced by the amine group, that is, \[{\rm{N}}{{\rm{H}}_{\rm{2}}}\] group. So, the formula of aniline is \[{{\rm{C}}_{\rm{6}}}{{\rm{H}}_5}{\rm{N}}{{\rm{H}}_{\rm{2}}}\].
Complete Step by Step Solution:
Let’s understand which reagent can separate a mixture of benzene and aniline.
The compound aniline possesses the character of weak base. When it is added to dilute hydrochloric acid (HCl), the formation of aniline hydrochloride occurs. The formed product aniline hydrochloride is a precipitate of black colour.
The chemical reaction is as follows:
\[{{\rm{C}}_{\rm{6}}}{{\rm{H}}_{\rm{5}}}{\rm{N}}{{\rm{H}}_{\rm{2}}} + {\rm{Dil}}{\rm{.}}\,{\rm{HCl}} \to {{\rm{C}}_{\rm{6}}}{{\rm{H}}_{\rm{5}}}{\rm{N}}{{\rm{H}}_{\rm{2}}} \cdot {\rm{HCl(Black}}\,{\rm{ppt}}{\rm{.)}}\]
But, Benzene does not undergo any reaction with dilute HCl. Therefore, both the compounds such as benzene and aniline are separated by reacting them with dilute hydrochloric acid.
Hence, the correct answer is option B, i.e., Dil. HCl.
Additional Information: Benzene is a chemical of no colour. It possesses light-yellow colour at room temperature. Primarily, It is used in the form of solvent in the chemical industries. In pharmaceutical industries, it is useful in the form of a starting material. The production of benzene is both manmade and natural.
Note: When a mixture of benzene and aniline is mixed with dilute HCl in a separating funnel, the separation of two layers takes place. When the non-aqueous layer undergoes distillation at 208 degrees results in the formation of benzene. The evaporation of the aqueous layer to dryness and then distilled with KOH gives pure aniline at a distillate.
Complete Step by Step Solution:
Let’s understand which reagent can separate a mixture of benzene and aniline.
The compound aniline possesses the character of weak base. When it is added to dilute hydrochloric acid (HCl), the formation of aniline hydrochloride occurs. The formed product aniline hydrochloride is a precipitate of black colour.
The chemical reaction is as follows:
\[{{\rm{C}}_{\rm{6}}}{{\rm{H}}_{\rm{5}}}{\rm{N}}{{\rm{H}}_{\rm{2}}} + {\rm{Dil}}{\rm{.}}\,{\rm{HCl}} \to {{\rm{C}}_{\rm{6}}}{{\rm{H}}_{\rm{5}}}{\rm{N}}{{\rm{H}}_{\rm{2}}} \cdot {\rm{HCl(Black}}\,{\rm{ppt}}{\rm{.)}}\]
But, Benzene does not undergo any reaction with dilute HCl. Therefore, both the compounds such as benzene and aniline are separated by reacting them with dilute hydrochloric acid.
Hence, the correct answer is option B, i.e., Dil. HCl.
Additional Information: Benzene is a chemical of no colour. It possesses light-yellow colour at room temperature. Primarily, It is used in the form of solvent in the chemical industries. In pharmaceutical industries, it is useful in the form of a starting material. The production of benzene is both manmade and natural.
Note: When a mixture of benzene and aniline is mixed with dilute HCl in a separating funnel, the separation of two layers takes place. When the non-aqueous layer undergoes distillation at 208 degrees results in the formation of benzene. The evaporation of the aqueous layer to dryness and then distilled with KOH gives pure aniline at a distillate.
Recently Updated Pages
JEE Main 2025-26 Mock Test: Organic Compounds Containing Nitrogen

JEE Main 2025-26 Organic Compounds Containing Nitrogen Mock Test

JEE Main Chemical Kinetics Mock Test 2025-26: Free Practice Online

JEE Main 2025-26 Organic Compounds Containing Oxygen Mock Test

JEE Main 2025-26 Organic Compounds Containing Halogens Mock Test

Sodium acetate on heating with soda lime produce A class 12 chemistry JEE_Main

Trending doubts
JEE Main 2026: City Intimation Slip and Exam Dates Released, Application Form Closed, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

Other Pages
NCERT Solutions For Class 12 Chemistry Chapter 1 Solutions - 2025-26

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Solutions Class 12 Chemistry Chapter 1 CBSE Notes - 2025-26

NCERT Solutions ForClass 12 Chemistry Chapter Chapter 4 The D and F Block Elements

Biomolecules Class 12 Chemistry Chapter 10 CBSE Notes - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 10 Biomolecules - 2025-26

