
A meter gauge train is heading north with speed $54km{h^{ - 1}}$ in earth’s magnetic field $3 \times {10^{ - 4}}T$. The $emf$ induced across the axle joining the wheels is
(A) $0.45mV$
(B) $4.5mV$
(C) $45mV$
(D) $450mV$
Answer
233.1k+ views
Hint We are given here with the length of the gauge of the train, the direction and speed of the train and the magnetic field of the earth and are asked to calculate the $emf$ induced across the axle rod joining the wheels. Thus, we will use the formula of emotional $emf$ as this case clearly is assisted by this concept.
Formulae Used
$\varepsilon = BLv$
Where, $\varepsilon $ is the induced$emf$, $B$ is the magnetic field, $L$ is the length of the moving pivot and $v$ is its velocity.
Complete Step by Step Solution
Here,
We can safely assume that the length of the axle is approximately equal to the gauge measurement of the train.
Thus,
$L = 1m$
Now,
Velocity of the axle would be the same as the velocity of the train.
Thus,
$v = 54km{h^{ - 1}}$ due north.
Converting this value into the standard unit, we get
$v = 15m{s^{ - 1}}$
And the magnetic field of the earth is given to be
$B = 3 \times {10^{ - 4}}T$
Thus,
The induced $emf$ will be,
$\varepsilon = (3 \times {10^{ - 4}})(1)(15)$
Which turns out to be,
$\varepsilon = 45 \times {10^{ - 4}}V$
Converting into$mV$, we get
$\varepsilon = 4.5mV$
Hence, the correct option is (B).
Additional information
The concept of emotional $emf$ is just an extension of Faraday's law of electromagnetic induction. It is just the collaboration of the former law with Lenz's law.
The Lenz’s law can be simply put as a conducting material opposes the change in magnetic field attached to it. In other words, if the magnetic field around it is increasing, it tries to decrease the same and vice versa.
Note
Before putting in the values of magnetic field, length and the velocity of the object, we need to make sure that all the three parameters are mutually perpendicular to each other. If any of them are at some other angles to the remaining parameters, then the calculation procedure and the substitution of the formula will be different.
Formulae Used
$\varepsilon = BLv$
Where, $\varepsilon $ is the induced$emf$, $B$ is the magnetic field, $L$ is the length of the moving pivot and $v$ is its velocity.
Complete Step by Step Solution
Here,
We can safely assume that the length of the axle is approximately equal to the gauge measurement of the train.
Thus,
$L = 1m$
Now,
Velocity of the axle would be the same as the velocity of the train.
Thus,
$v = 54km{h^{ - 1}}$ due north.
Converting this value into the standard unit, we get
$v = 15m{s^{ - 1}}$
And the magnetic field of the earth is given to be
$B = 3 \times {10^{ - 4}}T$
Thus,
The induced $emf$ will be,
$\varepsilon = (3 \times {10^{ - 4}})(1)(15)$
Which turns out to be,
$\varepsilon = 45 \times {10^{ - 4}}V$
Converting into$mV$, we get
$\varepsilon = 4.5mV$
Hence, the correct option is (B).
Additional information
The concept of emotional $emf$ is just an extension of Faraday's law of electromagnetic induction. It is just the collaboration of the former law with Lenz's law.
The Lenz’s law can be simply put as a conducting material opposes the change in magnetic field attached to it. In other words, if the magnetic field around it is increasing, it tries to decrease the same and vice versa.
Note
Before putting in the values of magnetic field, length and the velocity of the object, we need to make sure that all the three parameters are mutually perpendicular to each other. If any of them are at some other angles to the remaining parameters, then the calculation procedure and the substitution of the formula will be different.
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Understanding Uniform Acceleration in Physics

Dual Nature of Radiation and Matter Class 12 Physics Chapter 11 CBSE Notes - 2025-26

Understanding Electromagnetic Waves and Their Importance

Understanding the Electric Field of a Uniformly Charged Ring

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

