
A lump of clay of mass 10g travelling with a velocity 10cm/sec, towards east collides head on with another lump of clay of mass 10g travelling with velocity of 20 cm/sec towards west. If the two lumps coalesce after collision, what is its velocity if no external force acts on the system?
1) 15 cm/ sec towards west
2) 15 cm/sec towards east
3) 5 cm/sec towards west.
4) 5 cm/sec towards east.
Answer
162.6k+ views
Hint: For this question, one should be thorough with the concepts of collision. When two bodies collides under isolated conditions, their momentum is conserved unless some external force is applied.
Complete answer:
In physics, collision, which is also known as impact, is the abrupt, powerful coming together in close proximity of two bodies, such as two pool cues, a golf club and a ball, a hammer and a nail, two railroad cars when linked, or a falling object and a floor. Two factors—the force and the amount of time the items are in contact—affect the outcome of impact in addition to the characteristics of the two objects' materials To solve the given question we are have
Given data:-
Mass of first body(\[{m_1}\])= 10g ; Mass of second body(\[{m_2}\])= 10g
Velocity of first body(\[{v_1}\]) = 10cm/sec ; Velocity of second body(\[{v_2}\]) = -20cm/sec
To find:- Velocity after collision(\[v\])
Complete answer:
In physics, collision, which is also known as impact, is the abrupt, powerful coming together in close proximity of two bodies, such as two pool cues, a golf club and a ball, a hammer and a nail, two railroad cars when linked, or a falling object and a floor. Two factors—the force and the amount of time the items are in contact—affect the outcome of impact in addition to the characteristics of the two objects' materials To solve the given question we are have
Given data:-
Mass of first body(\[{m_1}\])= 10g ; Mass of second body(\[{m_2}\])= 10g
Velocity of first body(\[{v_1}\]) = 10cm/sec ; Velocity of second body(\[{v_2}\]) = -20cm/sec
To find:- Velocity after collision(\[v\])
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