
A hydrocarbon of molecular formula ${{\rm{C}}_{\rm{5}}}{{\rm{H}}_{{\rm{10}}}}$ could be a:
This question has multiple correct options
A. Monosubstituted alkene
B. Disubstituted alkene
C. Trisubstituted alkene
D. Tetrasubstituted alkene
Answer
222.6k+ views
Hint: We know that a hydrocarbon is an organic compound in which carbon and hydrogen atoms present. Some examples of hydrocarbon are methane, ethane etc.
Complete step-by-step answer:
The molecular formula of the compound is ${{\rm{C}}_{\rm{5}}}{{\rm{H}}_{{\rm{10}}}}$. We have the identify the of substitution possible in ${{\rm{C}}_{\rm{5}}}{{\rm{H}}_{{\rm{10}}}}$. A monosubstituted alkene is the alkene in which double bonded carbon atoms bonded to only one carbon atom.
Now we draw the monosubstituted alkene of ${{\rm{C}}_{\rm{5}}}{{\rm{H}}_{{\rm{10}}}}$.

A disubstituted alkene is the alkene in which double bonded carbon atoms bond to two other carbon atoms. Now we draw the disubstituted alkene of ${{\rm{C}}_{\rm{5}}}{{\rm{H}}_{{\rm{10}}}}$.

A trisubstituted alkene is the alkene in which double bonded carbon atoms bonded to three carbon atoms. Now we draw the trisubstituted alkene of ${{\rm{C}}_{\rm{5}}}{{\rm{H}}_{{\rm{10}}}}$.

A tetrasubstituted alkene is the alkene in which double bonded carbon atoms bonded to three other carbon atoms. For ${{\rm{C}}_{\rm{5}}}{{\rm{H}}_{{\rm{10}}}}$, formation tetrasubstituted alkene is not possible because minimum six carbon atoms are required for its formation, that is, two at the C=C bond and four carbon atoms which is to be substituted. But in ${{\rm{C}}_{\rm{5}}}{{\rm{H}}_{{\rm{10}}}}$, only five carbon atoms are present.
So, we can say that, ${{\rm{C}}_{\rm{5}}}{{\rm{H}}_{{\rm{10}}}}$ forms monosubstituted, disubstituted and tetrasubstituted alkene but it cannot form tetrasubstituted alkene.
Hence, option A, B and C is correct.
Note: Isomers are compounds which possess the same molecular formula but they have different structures. Monosubstituted, disubstituted and trisubstituted alkene of ${{\rm{C}}_{\rm{5}}}{{\rm{H}}_{{\rm{10}}}}$ are isomers of each other because they have same number of hydrogen and carbon atoms but their structures are different.
Complete step-by-step answer:
The molecular formula of the compound is ${{\rm{C}}_{\rm{5}}}{{\rm{H}}_{{\rm{10}}}}$. We have the identify the of substitution possible in ${{\rm{C}}_{\rm{5}}}{{\rm{H}}_{{\rm{10}}}}$. A monosubstituted alkene is the alkene in which double bonded carbon atoms bonded to only one carbon atom.
Now we draw the monosubstituted alkene of ${{\rm{C}}_{\rm{5}}}{{\rm{H}}_{{\rm{10}}}}$.

A disubstituted alkene is the alkene in which double bonded carbon atoms bond to two other carbon atoms. Now we draw the disubstituted alkene of ${{\rm{C}}_{\rm{5}}}{{\rm{H}}_{{\rm{10}}}}$.

A trisubstituted alkene is the alkene in which double bonded carbon atoms bonded to three carbon atoms. Now we draw the trisubstituted alkene of ${{\rm{C}}_{\rm{5}}}{{\rm{H}}_{{\rm{10}}}}$.

A tetrasubstituted alkene is the alkene in which double bonded carbon atoms bonded to three other carbon atoms. For ${{\rm{C}}_{\rm{5}}}{{\rm{H}}_{{\rm{10}}}}$, formation tetrasubstituted alkene is not possible because minimum six carbon atoms are required for its formation, that is, two at the C=C bond and four carbon atoms which is to be substituted. But in ${{\rm{C}}_{\rm{5}}}{{\rm{H}}_{{\rm{10}}}}$, only five carbon atoms are present.
So, we can say that, ${{\rm{C}}_{\rm{5}}}{{\rm{H}}_{{\rm{10}}}}$ forms monosubstituted, disubstituted and tetrasubstituted alkene but it cannot form tetrasubstituted alkene.
Hence, option A, B and C is correct.
Note: Isomers are compounds which possess the same molecular formula but they have different structures. Monosubstituted, disubstituted and trisubstituted alkene of ${{\rm{C}}_{\rm{5}}}{{\rm{H}}_{{\rm{10}}}}$ are isomers of each other because they have same number of hydrogen and carbon atoms but their structures are different.
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