A conductor carries a current $50\mu A$. If the area of cross-section of the conductor is $50m{m^2}$, then value of the current density in $A{m^{ - 2}}$ is
A) 0.5
B) 1
C) ${10^{ - 3}}$
D) ${10^{ - 6}}$
Answer
253.5k+ views
Hint:The question is from electricity. Substitute the value of current (I) and cross-section area (A) in the current density equation and find the value of current density (J).
Formula Used:
\[J = \dfrac{I}{A}\]
Where,
J = Current density
I = Current
A = Cross-section area
Complete answer:
Current density is defined as the total amount of current passing through a unit cross-sectional conductor in unit time. The equation for current density is given below.
\[J = \dfrac{I}{A}\]
Where,
J = Current density
I = Current
A = Cross-section area
The value of current and cross-section area is given. \[I = 50\mu A = 50 \times {10^{ - 6}}A\] and \[A = 50m{m^2} = 50 \times {10^{ - 6}}{m^2}\].
\[J = \dfrac{I}{A} = \dfrac{{50 \times {{10}^{ - 6}}}}{{50 \times {{10}^{ - 6}}}} = 1A{m^{ - 2}}\]
Hence, the correct option is Option B) 1.
Additional Information:
Drift velocity is the average velocity attained by charged particles, (electrons) in a material due to an electric field (\[\overrightarrow E \]). The SI unit of drift velocity is the same as velocity which is m/s. The drift velocity and current flowing through the conductor both increase as the intensity of the electric field increases. Drift velocity is directly proportional to current.
The relation between drift velocity and current is given below.
\[{v_d} = \dfrac{I}{{neA}}\]
\[{v_d}\]= drift velocity
I = current flow
n = free electron density
e = charge of an electron
A = cross sectional area
Mobility (\[\mu \]) of an electron is the drift velocity of an electron for a unit electric field (\[E\]). The equation for mobility is given below.
\[\mu = \dfrac{{{v_d}}}{E}\]
Note: The relation between drift velocity and Current Density is \[J = n{v_d}e\]. Where, n = free electron density, e = charge of an electron, \[{v_d}\]= drift velocity and J = current density.
Formula Used:
\[J = \dfrac{I}{A}\]
Where,
J = Current density
I = Current
A = Cross-section area
Complete answer:
Current density is defined as the total amount of current passing through a unit cross-sectional conductor in unit time. The equation for current density is given below.
\[J = \dfrac{I}{A}\]
Where,
J = Current density
I = Current
A = Cross-section area
The value of current and cross-section area is given. \[I = 50\mu A = 50 \times {10^{ - 6}}A\] and \[A = 50m{m^2} = 50 \times {10^{ - 6}}{m^2}\].
\[J = \dfrac{I}{A} = \dfrac{{50 \times {{10}^{ - 6}}}}{{50 \times {{10}^{ - 6}}}} = 1A{m^{ - 2}}\]
Hence, the correct option is Option B) 1.
Additional Information:
Drift velocity is the average velocity attained by charged particles, (electrons) in a material due to an electric field (\[\overrightarrow E \]). The SI unit of drift velocity is the same as velocity which is m/s. The drift velocity and current flowing through the conductor both increase as the intensity of the electric field increases. Drift velocity is directly proportional to current.
The relation between drift velocity and current is given below.
\[{v_d} = \dfrac{I}{{neA}}\]
\[{v_d}\]= drift velocity
I = current flow
n = free electron density
e = charge of an electron
A = cross sectional area
Mobility (\[\mu \]) of an electron is the drift velocity of an electron for a unit electric field (\[E\]). The equation for mobility is given below.
\[\mu = \dfrac{{{v_d}}}{E}\]
Note: The relation between drift velocity and Current Density is \[J = n{v_d}e\]. Where, n = free electron density, e = charge of an electron, \[{v_d}\]= drift velocity and J = current density.
Recently Updated Pages
States of Matter Chapter For JEE Main Chemistry

Young’s Double Slit Experiment Derivation Explained

JEE Main Participating Colleges 2026 - A Complete List of Top Colleges

Wheatstone Bridge – Principle, Formula, Diagram & Applications

Circuit Switching vs Packet Switching: Key Differences Explained

Mass vs Weight: Key Differences Explained for Students

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Electric Field of a Uniformly Charged Ring

Derivation of Equation of Trajectory Explained for Students

Other Pages
CBSE Class 12 Physics Question Paper 2026: Download SET-wise PDF with Answer Key & Analysis

JEE Advanced 2026 - Exam Date (Released), Syllabus, Registration, Eligibility, Preparation, and More

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

JEE Advanced Marks vs Rank 2025 - Predict Your IIT Rank Based on Score

