
A capacitor of capacitance $C$ which is initially charged up to a potential difference $\varepsilon $ is connected with a battery of $\varepsilon $ such that the positive terminal of the battery is connected with the positive plate of the capacitor. Find the heat loss in the circuit and the process of charging.
Answer
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Hint: Charge (or additionally, electric charge) is that the fundamental measure of electricity. Electricity is all regarding the charge. No one will tell you what the charge is. They’ll solely tell you the way charges act.
Formula used:
When the capacitor is fully charged then this formula will come,
$ \Rightarrow q = C\varepsilon $
Where ‘$q$’ will be the amount of charge which gets stored in the capacitor
‘$C$’ will be the capacitance and ‘$\varepsilon $’ will be the electromotive force which is being used for charging the capacitor.
Complete step by step solution:
Since it is given that the capacitor is initially charged up to the potential difference and it is connected in such a way that the positive terminal of the battery gets connected with the positive plate and we have to find the heat loss during the process.
So for this, we will check the initial and final charge stored on the capacitor.
So by using the formula
$ \Rightarrow q = C\varepsilon $
Suppose a battery is connected with the positive terminal of the capacitor and then the charge developed on the capacitor will be
$ \Rightarrow {q_f} = C\varepsilon $
We name this final charge.
Now let’s see the initial charge,
$ \Rightarrow {q_i} = C\varepsilon $
Since the initial charge and the final charge both are the same, that is
$ \Rightarrow {q_f} = {q_i}$
By the above it is understood since there is no difference in the charge, therefore the heat loss will be zero.
Therefore, there is zero loss of heat during this.
Note: The term neutral doesn't refer to the third kind of charge, however to the presence in a very region of positive and negative charges in equal quantity. The total of identical positive and negative quantities is zero. This is often what it suggests that to be electrically neutral. The assumed charge of all gross objects is neutral unless otherwise indicated. Although regions of the house may be delineated as being "positive" or "negative" the universe as an entire is electrically neutral.
Formula used:
When the capacitor is fully charged then this formula will come,
$ \Rightarrow q = C\varepsilon $
Where ‘$q$’ will be the amount of charge which gets stored in the capacitor
‘$C$’ will be the capacitance and ‘$\varepsilon $’ will be the electromotive force which is being used for charging the capacitor.
Complete step by step solution:
Since it is given that the capacitor is initially charged up to the potential difference and it is connected in such a way that the positive terminal of the battery gets connected with the positive plate and we have to find the heat loss during the process.
So for this, we will check the initial and final charge stored on the capacitor.
So by using the formula
$ \Rightarrow q = C\varepsilon $
Suppose a battery is connected with the positive terminal of the capacitor and then the charge developed on the capacitor will be
$ \Rightarrow {q_f} = C\varepsilon $
We name this final charge.
Now let’s see the initial charge,
$ \Rightarrow {q_i} = C\varepsilon $
Since the initial charge and the final charge both are the same, that is
$ \Rightarrow {q_f} = {q_i}$
By the above it is understood since there is no difference in the charge, therefore the heat loss will be zero.
Therefore, there is zero loss of heat during this.
Note: The term neutral doesn't refer to the third kind of charge, however to the presence in a very region of positive and negative charges in equal quantity. The total of identical positive and negative quantities is zero. This is often what it suggests that to be electrically neutral. The assumed charge of all gross objects is neutral unless otherwise indicated. Although regions of the house may be delineated as being "positive" or "negative" the universe as an entire is electrically neutral.
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