Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store

What Are Elastic Collisions in One Dimension?

ffImage
hightlight icon
highlight icon
highlight icon
share icon
copy icon
SearchIcon
widget title icon
Latest Updates

widget icon
Start Your JEE Practice Here :
JEE Test Series 2026

How to Solve One-Dimensional Elastic Collision Problems

Elastic collision in one dimension is a key concept in mechanics, where two objects collide along a straight line and both kinetic energy and linear momentum are conserved throughout the process. This analysis plays an important role in understanding foundational physics at the JEE and Class 11 level.


Fundamental Laws Governing Elastic Collisions in One Dimension

The behavior of objects in a one-dimensional elastic collision is determined by two conservation principles: conservation of linear momentum and conservation of kinetic energy. Application of these principles allows prediction of post-collision velocities.


Linear momentum $\left(p\right)$ for an object is expressed as $p = m v$, where $m$ is mass and $v$ is velocity. The total momentum before collision equals total momentum after collision in an isolated system. For more details, refer to Understanding Momentum.


Kinetic energy for a moving object is given by $KE = \dfrac{1}{2}m v^2$. In one-dimensional elastic collisions, total kinetic energy remains unchanged during the event. This criteria differentiates elastic collisions from inelastic collisions, where kinetic energy is not conserved.


Mathematical Equations of Elastic Collision in One Dimension

Consider two bodies of masses $m_1$ and $m_2$ moving along a straight line with initial velocities $u_1$ and $u_2$, and final velocities $v_1$ and $v_2$ after collision. The following equations represent conservation principles:


Conservation of linear momentum: $$ m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2 $$


Conservation of kinetic energy: $$ \dfrac{1}{2} m_1 u_1^2 + \dfrac{1}{2} m_2 u_2^2 = \dfrac{1}{2} m_1 v_1^2 + \dfrac{1}{2} m_2 v_2^2 $$


Solving these equations simultaneously provides the final velocities for both bodies after the collision in terms of their masses and initial velocities. A detailed overview is available at Elastic Collisions Overview.


Derivation of Final Velocities: Stepwise Analysis

To derive the equations for $v_1$ and $v_2$, first manipulate both conservation equations to eliminate one variable. The standard form of solutions is:


$$ v_1 = \dfrac{(m_1 - m_2) u_1 + 2 m_2 u_2}{m_1 + m_2} $$


$$ v_2 = \dfrac{(m_2 - m_1) u_2 + 2 m_1 u_1}{m_1 + m_2} $$


When both bodies have equal mass $(m_1 = m_2)$, the above results reduce to $v_1 = u_2$ and $v_2 = u_1$. The objects exchange their velocities after the collision, which is a direct consequence of conservation laws in this scenario.


Solved Example: Elastic Collision in One Dimension

Let $m_1 = 2$ kg, $u_1 = 3$ m/s, $m_2 = 3$ kg, and $u_2 = 0$ m/s. Substituting values into the derived formulas yields:


$$ v_1 = \dfrac{(2 - 3) \times 3 + 2 \times 3 \times 0}{2 + 3} = \dfrac{(-3)}{5} = -0.6 \ \mathrm{m/s} $$


$$ v_2 = \dfrac{(3 - 2) \times 0 + 2 \times 2 \times 3}{2 + 3} = \dfrac{12}{5} = 2.4 \ \mathrm{m/s} $$


The negative sign for $v_1$ indicates the first mass reverses its direction after the collision. The second mass gains velocity in the original direction of the first mass.


Comparison: One-Dimensional vs Two-Dimensional Elastic Collisions

Aspect One Dimension
Collision DirectionSingle line
Equations RequiredTwo (momentum, energy)
Complexity LevelSimpler
Typical ExampleTrack or head-on

Aspect Two Dimension
Collision DirectionMultiple axes
Equations RequiredThree or more
Complexity LevelHigher
Typical ExampleBilliards

Collisions in two dimensions demand separate conservation for each axis, increasing algebraic complexity. Further clarification is given in Types of Collisions.


Key Characteristics and Identification of Elastic Collisions

  • Both kinetic energy and momentum are conserved
  • No loss of total energy as heat or deformation
  • Strict sign convention is essential for directions
  • True ideal elastic collisions are rare in reality
  • Most common in theoretical and microscopic cases

Elastic collision analysis is frequently used in problems on molecular motion and ideal gases. See the Kinetic Theory of Gases for applications at the microscopic scale.


Common Pitfalls and Practical Tips for Solving Problems

  • Failing to apply both conservation equations
  • Mixing up initial and final velocities
  • Skipping sign conventions for directions
  • Not recognizing velocity exchange in equal masses case
  • Assuming all collisions are perfectly elastic

To avoid calculation errors, always write both conservation equations explicitly and check for conservation of kinetic energy to confirm elasticity.


Applications and Further Concepts Linked to Elastic Collisions

Analysis of elastic collisions in one dimension is foundational for topics such as work, energy, and momentum problems in Class 11 and for JEE. This knowledge is also directly applicable in the study of Work, Energy, and Power.


Problems involving impulse and momentum theorem, as covered in Elastic Collisions Overview, often use similar logic and derivation steps.


Concepts related to energy transfer in collisions also appear in oscillatory motion and advanced mechanics. For such contexts, see Energy in Simple Harmonic Motion.


Competitive Exams after 12th Science
tp-imag
bottom-arrow
tp-imag
bottom-arrow
tp-imag
bottom-arrow
tp-imag
bottom-arrow
tp-imag
bottom-arrow
tp-imag
bottom-arrow

FAQs on What Are Elastic Collisions in One Dimension?

1. What is an elastic collision in one dimension?

An elastic collision in one dimension is a type of collision where both momentum and kinetic energy are conserved. In such collisions:

  • Colliding bodies move along a straight line (one-dimensional).
  • Total kinetic energy before and after collision remains unchanged.
  • Total linear momentum is also unchanged.
  • Examples include collisions between ideal gas molecules and perfectly hard spheres.

2. What are the main differences between elastic and inelastic collisions?

The primary difference is that in elastic collisions, both kinetic energy and momentum are conserved, whereas, in inelastic collisions, only momentum is conserved. Other key differences include:

  • Elastic collisions maintain both momentum and kinetic energy.
  • Inelastic collisions lose kinetic energy to heat, sound, or deformation.
  • Elastic collisions often occur with hard, non-deformable objects like atomic particles.

3. What are the velocity formulas after a one-dimensional elastic collision?

For two objects (m₁ and m₂) with initial velocities u₁ and u₂, the final velocities (v₁ and v₂) after an elastic collision are:

  • v₁ = [(m₁ - m₂)/(m₁ + m₂)]u₁ + [2m₂/(m₁ + m₂)]u₂
  • v₂ = [2m₁/(m₁ + m₂)]u₁ + [(m₂ - m₁)/(m₁ + m₂)]u₂
  • These equations follow from momentum and kinetic energy conservation.

4. How is momentum conserved in a one-dimensional elastic collision?

Momentum is conserved in a one-dimensional elastic collision, meaning the total momentum before and after collision remains the same.

  • Before collision: m₁u₁ + m₂u₂
  • After collision: m₁v₁ + m₂v₂
  • The sum is equal in both cases, following Newton's Third Law.

5. Can you give an example of an elastic collision in one dimension?

A classic example is the collision of two identical billiard balls moving in a straight line on a frictionless table. Key features include:

  • Balls have the same mass.
  • They exchange velocities after a head-on, perfectly elastic collision.
  • Total kinetic energy and momentum are conserved.

6. What are the conditions required for a collision to be perfectly elastic?

The conditions for a perfectly elastic collision are:

  • No loss of kinetic energy during the collision.
  • No deformation of the objects.
  • No generation of heat, sound, or other energy forms.
  • Applies to microscopic particles (like atoms) more often than ordinary objects.

7. How do you calculate the final velocities using the conservation laws in elastic collisions?

You calculate the final velocities by applying both conservation of momentum and conservation of kinetic energy.

  • Set up two equations: one for momentum, one for kinetic energy.
  • Solve for the unknown velocities (v₁ and v₂).
  • Use formulas:
    • v₁ = [(m₁ - m₂)/(m₁ + m₂)]u₁ + [2m₂/(m₁ + m₂)]u₂
    • v₂ = [2m₁/(m₁ + m₂)]u₁ + [(m₂ - m₁)/(m₁ + m₂)]u₂

8. Why is kinetic energy conserved in an elastic collision?

Kinetic energy is conserved in an elastic collision because there is no transformation of kinetic energy into heat, sound, or deformation.

  • Interacting bodies are perfectly rigid.
  • All the energy remains as mechanical kinetic energy.
  • Atoms, electrons, and hard spheres display this property under ideal conditions.

9. What is the importance of studying elastic collisions in physics?

Studying elastic collisions helps in understanding fundamental physics concepts and practical systems in nature. Importance includes:

  • Explains behavior of gas molecules and ideal gases (kinetic theory).
  • Forms the basis of Newton's laws and energy conservation.
  • Useful for solving numerical and conceptual problems in CBSE exams.

10. Are all collisions in nature perfectly elastic?

No, most collisions in everyday life are not perfectly elastic as some energy is usually lost to heat, sound, or deformation.

  • Only specific cases (like collisions between fundamental particles or gas molecules) approach perfect elasticity.
  • Bouncing balls, car crashes, and similar events are mostly inelastic.