## Concepts of Work, Energy and Power for JEE Main Physics

This chapter will teach us about concepts like** work, energy and power**. Work, energy and power are essential concepts in physics. Work is the displacement of an object caused by a force (push or pull). Energy is defined as the ability to perform work. We also get to know about the work done formula and energy formula.

The chapter also includes the following concepts:

Kinetic Energy: It is the energy that a body possesses as a result of its motion.

Potential Energy: It is the energy possessed by a body by virtue of its position or configuration in some field.

Work Energy Theorem: This concept states that the work done by net force in displacing a body is equal to the change in kinetic energy of the body.

Principle of Conservation of Energy: According to this principle, if we account for all forms of energy, the total energy of an isolated system does not change.

Collision: It is an isolated event in which two or more colliding bodies exert relatively strong force on each other for a relatively short time.

Now, let's move onto the important concepts and formulae related to IIT JEE exams along with a few solved examples.

## JEE Main Physics Chapters 2024

### Important Topics of Work Energy and Power Chapter

Work done by variable force.

Conservative and non-conservative forces.

Power definition and relation between work and power.

Kinetic energy and linear momentum relation.

Work energy theorem.

Potential energy of a spring.

Mechanical energy and its conservation.

Collision and its types.

## What is Work?

Work happens when a force makes something move. For example, when a person climbs a mountain, work is being done because they are going against gravity to go up. So, two things matter for work:

Magnitude of force

The direction in which the body moves due to the force applied.

To calculate work, you multiply how far something moves by the force acting on it. Work is just a number, and the unit we use to measure it is called the Joule. The formula for work is: Work = Force × Distance or W = F $\times$ S

But there's a little twist: if the force isn't pushing in the exact same direction as the movement, you have to use the cosine of the angle between them in the formula: W = F $\times$ S $\times$ Cos $\theta$

It's important to note that work only happens when a force causes something to move. If you push a wall and it doesn't move, you're not doing any work on it. However, you're still using energy because your muscles are working, and you might get tired.

## What is Energy?

The capacity of a man that allows him to do work is called energy. In simple words, energy is the ability to work. It is in scalar quantity and has only magnitude and no direction. energy can neither be created nor destroyed, it can only change in its form. Energy can be found in many things, and so there are many forms of energy. The most important types of energy are kinetic energy and potential energy.

Kinetic energy refers to the energy of a body due to its movement or motion. It refers to the work that is required to accelerate a body of the given mass differentiating it from its velocity. While acceleration after the body gains energy, it maintains kinetic energy until its speed changes.

The formula of kinetic energy is –\[ \frac{1}{2}mv^{2}\]

Hence from the formula given above, we can state:

The kinetic energy of a body gets doubled whenever its mass gets doubled.

If the mass of a body is halved, then the kinetic energy is also halved.

The kinetic energy of a mass increases by four times when the velocity doubles.

## What is Power?

Power is a way to talk about how quickly work is being done. Work power or simply power is referred to as a physical concept that includes several meanings, depending on the context and the details available. Power can be defined as the rate of doing work. Power is the energy that is consumed per unit of time. It is present in scalar quantity as it does not have any direction. The SI unit of power is Joules/second and is termed as Watt. Watt refers to the power needed to do one Joule of work in a second.

### Work, Energy and Power Important Concept for JEE Main

## Types of Energy

Besides kinetic and potential energy, some other important types of energy are as follows:

Chemical energy: This refers to energy that is released by chemical substances on undergoing a chemical reaction which is further transformed into other substances.

Mechanical energy: This is referred to as the sum of potential energy and kinetic energy.

Electrical energy: This energy is derived as a result of the movement that takes place between electrically charged particles.

Magnetic energy: A magnetic field is generated by electric currents. So, the energy that is the form of electrons is known as magnetic energy.

Nuclear energy: This is the energy that is released during the process of fission or fusion, especially when it is used to generate electricity.

Heat energy: This energy is produced as a result of the movement of atoms or molecules in solids, liquids, and gasses.

### List of Important Formulas for Work Energy and Power Chapter

### What are the Differences Between Work and Energy?

Work and energy are two fundamental concepts in physics that are often used interchangeably, but they have distinct meanings and applications.

The key difference between work and energy lies in their role in physical processes. Work is the process of transferring energy from one object to another, while energy is the inherent ability of an object to do work.

To illustrate this difference, consider the following example: A person lifts a book from the floor to a shelf. The person applies force to the book, causing it to move upwards. This process involves work, as the person's force transfers energy from their muscles to the book. The book now possesses potential energy due to its elevated position. If the book were to fall off the shelf, its potential energy would be converted into kinetic energy as it falls, eventually doing work on the floor by impact.

If you want to know more differences between Work and Energy, check Vedantu’s page on the Difference Between Work and Energy.

You can also check Meaning, Differences, and FAQs on the Difference between Work, Energy, and Power on Vedantu’s page.

### Is Formula For Power Important For JEE Main?

Yes, the formula for power is important for JEE Main. Power is a fundamental concept in physics, and it is used in a variety of problems on the JEE Main exam. The formula of power is P = $\frac{W}{t}$ , where P is power, W is work, and t is time.

Here are some examples of how the Power formula in Physics is used on the JEE Main exam:

A light bulb consumes 60 watts of power. How much work does it do in 1 hour?

A car accelerates from 0 to 60 mph in 10 seconds. What is the power of the car's engine?

A pump lifts 100 liters of water to a height of 10 meters in 5 minutes. What is the power of the pump?

As you can see, the formula for power is a versatile tool that can be used to solve a variety of problems on the JEE Main exam. Therefore, it is important to understand the formula and how to use it.

### Power Formula for Electricity

In electricity, power is the rate at which electrical energy is transferred. It is measured in watts (W). The power equation is:

P = VI

where:

P is power in watts (W)

V is voltage in volts (V)

I is current in amperes (A).

This formula tells us that the power consumed by an electrical device is directly proportional to the voltage applied to it and the current flowing through it.

### Examples of Power Calculations:

Here are some examples of how to use the power formula:

A light bulb with a resistance of 10 ohms is connected to a 12-volt battery. What is the power consumed by the light bulb?

P = VI = (12V) (1A) = 1W

A motor draws 5 amperes of current from a 24-volt power supply. What is the power consumed by the motor?

P = VI = (24V) (5A) = 120W

A household appliance has a power rating of 1,000 watts. How much current does it draw from a 120-volt outlet?

I = $\frac{\text{P}}{\text{V}} = \frac{1,000 \, \text{W}}{120 \, \text{V}} = 8.33 \, \text{A}$

### Real-World Applications of Power Formula

The power formula is used in a variety of real-world applications, such as:

Designing Electrical Circuits: Engineers use the power formula to design electrical circuits that can deliver the required amount of power to various devices.

Calculating Electrical Bills: Electricity companies use the power formula to calculate the amount of electricity consumed by their customers.

Sizing Fuses and Circuit Breakers: Fuses and circuit breakers are designed to protect electrical circuits from overloading. The power formula is used to determine the appropriate size of fuse or circuit breaker for a given circuit.

## How is Work Different from Power?

You can explore further elaboration on the distinctions between work and power to gain a clearer understanding.

## How is Work Different from Energy?

To gain a better comprehension, delve deeper into the distinguish between work and power.

## How is Power Different from Energy?

You can delve into a more comprehensive explanation of distinguishing between work and power, To gain a better grasp. You can also go through the Difference Between work energy and power provided in detail along with their characteristics.

### All Formulas of Electricity Class 10 For JEE Main

In the realm of physics, understanding the fundamentals of electricity is crucial, and this holds particularly true for students preparing for competitive exams like JEE Main. This introduction serves as a gateway to comprehending all the essential electricity formulas from Class 10. From Ohm's Law to power calculations, formulas of electricity class 10 lay the foundation for solving intricate problems. As we delve into this comprehensive compilation, students will gain a holistic perspective on the principles governing electrical phenomena, providing them with the tools needed to excel in their JEE Main examinations.

Here are the essential electricity class 10 formulas for electricity for the JEE Main exam:

### Ohm's Law

Ohm's law is a fundamental principle in electricity that states that the current through a conductor is directly proportional to the voltage across it and inversely proportional to its resistance.

Formula:

I = $\frac{\text{V}}{\text{R}}$

where:

(I) is the current in amperes (A),

(V) is the voltage in volts (V),

(R) is the resistance in ohms $(\Omega)$

### Resistance

Resistance is a measure of a material's opposition to the flow of electric charge. It is measured in ohms (Omega)$ .

Formula:

R = $\frac{\rho l}{A}$

where:

(R) is the resistance in ohms $(\Omega)$ ,

$(\rho)$ is the resistivity of the material in ohm-meters $(\Omega \cdot \text{m})$ ,

(l) is the length of the conductor in meters $(\text{m})$ ,

(A) is the cross-sectional area of the conductor in square meters $(\text{m}^2)$

### Resistivity

Resistivity is a property of a material that describes its resistance to the flow of electric charge. It is measured in ohm-meters $(\Omega \cdot \text{m})$ .

Formula:

$\rho = \frac{1}{\sigma}$

where:

$(\rho)$ is the resistivity of the material in ohm-meters $(\Omega \cdot \text{m})$ ,

$(\sigma)$ is the conductivity of the material in siemens per meter (S/m).

### Current

Current is the rate of flow of electric charge through a conductor. It is measured in amperes (A).

Formula:

I = $\frac{Q}{t}$

where:

I is the current in amperes (A)

Q is the charge in coulombs (C)

t is the time in seconds (s)

### Voltage

Voltage is the electrical potential difference between two points in a circuit. It is measured in volts (V).

Formula:

V = $\frac{W}{Q}$

where:

V is the voltage in volts (V)

W is the work done in joules (J)

Q is the charge in coulombs (C)

### Power

Power is the rate at which work is done. It is measured in watts (W).

Formula:

P = $\frac{W}{t}$

where:

P is the power in watts (W)

W is the work done in joules (J)

t is the time in seconds (s)

## Kirchhoff's Laws

Kirchhoff's laws are two fundamental principles in electricity that describe the behavior of currents and voltages in electrical circuits.

### Kirchhoff's First Law (Junction Law)

The algebraic sum of the currents entering a junction is zero.

### Kirchhoff's Second Law (Loop Law)

The algebraic sum of the voltages around a closed loop is zero.

These formulas provide a solid foundation for understanding and solving problems related to electricity in JEE Main. By mastering these concepts, students can effectively analyze electrical circuits, calculate currents and voltages, and design electrical systems.

### JEE Main Work, Energy and Power Solved Examples

1. A particle travels in a straight path, with retardation proportional to displacement. Calculate the kinetic energy loss for every displacement $x$.

Sol:

It is given that retardation($a$) is proportional to displacement ($x$). So in order to solve this problem, we first write retardation in terms of velocity and after separating and integrating the quantities in the given relation, we will be able to reach the answer.

According to the question,

$-a\varpropto x$

$-a=kx$...........(1)

Here, $k$ is the proportionality constant.

Now putting $a=\dfrac{\text{d}v}{\text{d}t}$ in the eq.(1), we get:

$-a=-\dfrac{\text{d}v}{\text{d}t} = kx$

Now after multiplying and dividing on L.H.S by $\text{d}x$, we get:

$\dfrac{\text{d}v}{\text{d}t} \dfrac{\text{d}x}{\text{d}x} =-kx$

As $\dfrac{\text{d}x}{\text{d}t}=v$, therefore, $v\text{d}v=-kx\text{d}x$

$\int_{v}^{0}vdv=-k\int_{x}^{0}xdx$

$[\dfrac{v^2}{2}]^v_u=-k[\dfrac{x^2}{2}]^x_0$

$\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2=\dfrac{-kx^2m}{2}$

Thus, the loss in kinetic energy is $\Delta K=\dfrac{-kmx^2}{2}$.

Trick: Use the given condition of the question and put the retardation formula in terms of velocity then separate the similar quantities and integrate them.

2. A body falls to the earth from a height of $8,m$ and then bounces to a height of $2,m$. Calculate the ratio of the body's velocities right before and after the contact. Calculate the body's kinetic energy loss as a percentage during the contact with the ground.

Sol:

It is given that heights $h_1=8\,m$ and $h_2=2\,m$. Let $v_1$ be the velocity of the body just before collision with the ground and $v_2$ be the velocity of the body just after collision.

Now, according to the conservation of mechanical energy, we can write:

$\dfrac{1}{2}mv_1^2=mgh_1$ and $\dfrac{1}{2}mv_2^2=mgh_2$

After dividing the above equation, we get:

$\dfrac{v^2_1}{v^2_2}=\dfrac{h_1}{h_2}$

Putting the values of $h_1$ and $h_2$, we get:

$\dfrac{v^2_1}{v^2_2}=\dfrac{8}{2}=4$

$\dfrac{v_1}{v_2}=2$

Therefore, the ratio of the velocities is 2:1.

Now, the percentage loss in kinetic energy is given as:

$\% \text{ age loss in K.E}=(\dfrac{K_1-K_2}{K_1}\times 100$

$\% \text{ age loss in K.E}=\dfrac{mg(h_1-h_2)}{mgh_1}\times 100$

$\% \text{ age loss in K.E}=\dfrac{(8-2)}{8}\times 100$

$\% \text{ age loss in K.E}= 75\%$

Hence, the percentage loss in kinetic energy is 75 %.

Key point: The laws of conservation of mechanical energy is an important concept and so is the loss of kinetic energy expression.

### Previous Years’ Questions from JEE Paper

1. A block moving horizontally on a smooth surface with a speed of $40\,m/s$ splits into two equal parts. If one of the parts moves at $60\,m/s$ in the same direction, then the fractional change in the kinetic energy will be $x : 4$ where $x$ = ___________. (JEE Main 2021)

Sol:

Given:

Initial velocity of the block before splitting into two equal parts, $V=40\,m/s$

As the block is split into two equal masses, so if we consider the initial mass of the block $m$ then after splitting, it will be $\dfrac{m}{2}$. Let the velocity of 1st part be $v$ and the velocity of the second part according to the question is $v’=60\,m/s$.

Now, using the momentum conservation principle, we get:

$P_i=P_f$

$mV=\dfrac{m}{2} v+\dfrac{m}{2} v’$

$V=\dfrac{v}{2} +\dfrac{v’}{2}=\dfrac{v}{2}+\dfrac{60}{2}$

$40=\dfrac{v}{2}+30$

$v=10\times 2=20\,m/s$

Now, the initial kinetic energy ($(K.E.)_i$) is

$(K.E.)_i = \dfrac{1}{2}mV^2=\dfrac{1}{2}m(40)^2=800m$

The final kinetic energy ($(K.E.)_f$) is

$(K.E.)_f = \dfrac{1}{2}\dfrac{m}{2}(20)^2+\dfrac{1}{2}\dfrac{m}{2}(60)^2=1000m$

The change in kinetic energy ($\Delta K.E.$) is

$\lvert\Delta K.E.\rvert=\lvert 1000m-800m\rvert=200m$

The fractional change in kinetic energy is

$\text{fractional change in K.E.}=\dfrac{\Delta K.E.}{(K.E.)_i}=\dfrac{200 m}{800m}$

$\text{fractional change in K.E.}= \dfrac{1}{4}=\dfrac{x}{4}$

Hence, the value of $x$ is $1$.

Trick: Just apply the concept of conservation of momentum then fraction change in the kinetic energy.

1. A force of $F = (5y + 20) \widehat{j}\,N$ acts on a particle. The work done by this force when the particle is moved from $y = 0\,m$ to $y = 10\,m$ is ___________ J. (JEE Main 2021)

Sol:

Given:

A variable force expression, $F = (5y + 20) \widehat{j}\,N$

Moved from $y = 0\,m$ to $y = 10\,m$

The work done under the variable force is given by

$W=\int Fdy=\int_{0}^{10} Fdy$

Now, putting the value of $F$ in the above expression and integrating it, we get:

$W=\int_{0}^{10} (5y + 20)dy$

$W=(\dfrac{5y^2}{2}+2y)^{10}_0$

$W=\dfrac{5}{2}\times 100+2\times 10$

$W=250+200=450\,J$

Therefore, the value of work done is 450 J.

Key point: The expression of work done for variable forces is the important key to solve this problem.

### Practice Questions

1. A 10 kg ball and a 20 kg ball collide at velocities 20 m/s and 10 m/s, respectively. What are their post-collision velocities if the collision is completely elastic?

Ans: -20 m/s; 10 m/s

2. A spring gun has a spring constant of 80 N/cm. A ball of mass 15g compresses the spring by 12 cm. How much is the potential energy of the spring? What is the velocity of the ball if the trigger is pulled?

Ans: 57.6 J; 87.6 m/s

## JEE Main Physics Work, Energy and Power Study Materials

Here, you'll find a comprehensive collection of study resources for Work, Energy and Power designed to help you excel in your JEE Main preparation. These materials cover various topics, providing you with a range of valuable content to support your studies. Simply click on the links below to access the study materials of Work, Energy and Power and enhance your preparation for this challenging exam.

## JEE Main Physics Study and Practice Materials

Explore an array of resources in the JEE Main Physics Study and Practice Materials section. Our practice materials offer a wide variety of questions, comprehensive solutions, and a realistic test experience to elevate your preparation for the JEE Main exam. These tools are indispensable for self-assessment, boosting confidence, and refining problem-solving abilities, guaranteeing your readiness for the test. Explore the links below to enrich your Physics preparation.

### Conclusion

The "**Work, Energy, and Power**" chapter in the JEE Main syllabus is a cornerstone of physics that unveils the principles governing motion, transformation of energy, and the concept of power. It equips aspiring engineers and scientists with the tools to understand and solve intricate problems related to kinetic and potential energy, work done by forces, and the rate at which work is performed. Beyond exam success, the knowledge gained here is instrumental in comprehending real-world phenomena, from machinery to the cosmos. It empowers students to analyze and optimize systems, making it an indispensable component of their scientific journey.

## FAQs on Work, Energy and Power Chapter - Physics JEE Main

**1. What is the weightage of the Work Energy and Power chapter in JEE?**

From this chapter, approximately two questions are asked every year which leads to a weightage of about 2-3% in the exam.

**2. What is the level of difficulty of the questions from the Work Energy and Power chapter?**

As this chapter deals with daily life applications, the questions asked in this chapter are from easy to moderate levels of difficulty. Thus, it is essential to study this chapter as the level of difficulty is not that hard. Studying this chapter can help you in improving your rank along with a good score.

**3. Is it truly beneficial to review Work Energy and Power chapter questions from previous years for this exam?**

We must practice previous years’ questions in order to score well and become familiar with the exam's difficulty level. It improves our self-esteem while also pointing us to areas where we may improve. Solving previous ten to fifteen years’ question papers will help you better comprehend a concept and also show you how many times a concept or topic has been repeated in the test. It is advisable to practice previous years’ questions in order to prepare for the work power energy notes.

4. Define work power and energy for JEE Main?

Work, power, and energy are fundamental concepts in physics that are crucial for understanding various phenomena and solving problems in the JEE Main exam. Here's a concise explanation of these concepts:

Work: Work is defined as the transfer of energy from one object to another. It occurs when a force acts on an object, causing it to move in the direction of the force. The work done is calculated as the product of the force applied and the displacement of the object in the direction of the force. The SI unit of work is the joule (J).

Power: Power is the rate at which work is done. It is defined as the work done per unit time. The SI unit of power is the watt (W), which is equivalent to one joule per second (J/s).

Energy: Energy is the capacity to do work. It is the ability of a system to perform work or produce heat. Energy exists in various forms, including kinetic energy, potential energy, thermal energy, and electromagnetic energy. The SI unit of energy is also the joule (J).

5. What is the Relationship between Work, Energy, Power?

Work, power, and energy are interconnected concepts. The relationship between them can be expressed as:

\text{Power} = \frac{\text{Work}}{\text{Time}} \quad (\text{W} = \text{J/s})

\text{Work} = \text{Power} \times \text{Time} \quad (\text{J} = \text{W} \times \text{s})

These equations emphasize that power is a measure of the rate at which work is done, and work is the total amount of energy transferred over a specific time interval.

6. What are the applications of power, work and energy in JEE Main?

Work, power, and energy play a significant role in solving various JEE Main problems, particularly in mechanics and thermodynamics. Some common applications include:

Calculating the work done by a force

Determining the power of a machine or engine

Analyzing the energy transformations in different processes

Understanding the concepts of kinetic energy and potential energy

7. Explain Work vs power.

Work is the energy transferred from one object to another due to the application of a force. It is a measure of the amount of energy transferred, and it is measured in joules (J) in the SI system. The formula for work is:

W = F \cdot d

where:

W is work (J)

F is force (N)

d is displacement (m)

Power is the rate at which work is done. It is defined as the work done per unit time, and it is measured in watts (W) in the SI system. The formula for power is:

P = \frac{W}{t}

where:

P is power (W)

W is work (J)

t is time (s)

In simpler terms, power tells us how quickly work is being done. A higher power indicates that work is being done at a faster rate.

8. What are the Real-World Applications of Work and Power?

Work is used in engineering to calculate the amount of energy required to perform a task, such as lifting a load or moving an object.

Power is used in engineering to design machines and devices that operate at the desired speed and efficiency.

9. Are all formulas of electricity class 10 essential for JEE Main exam?

Absolutely! While the JEE Main primarily focuses on the syllabus of Class 11 and 12, having a solid understanding of Class 10 Electricity formulas can be beneficial for foundation course students. A strong foundation in fundamental concepts enhances overall comprehension and problem-solving skills, providing an advantageous edge for tackling more advanced topics in Physics. It's always advantageous to build a comprehensive understanding of the subject from the ground up, ensuring a well-rounded preparation for the JEE Main exam and beyond.

10. How derivation of electricity class 10 helps in the JEE Main exam?

The derivation of electricity concepts in Class 10 lays the groundwork for a deeper understanding of electrical principles. While Class 10 derivations might not be directly tested in JEE Main, they contribute significantly to the foundational knowledge needed for advanced topics in Class 11 and 12 Physics.

Understanding derivations helps in developing problem-solving skills, critical for JEE Main. It fosters a logical thought process, making it easier to comprehend complex electrical concepts. Furthermore, it establishes a strong base, enabling students to approach JEE Main questions with confidence, as they can connect higher-level ideas to their foundational understanding. In essence, Class 10 derivations provide a stepping stone for success in JEE Main and subsequent Physics studies.