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KCET 2013 Previous Year Question Paper for Maths, Physics, Chemistry & Biology

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Last updated date: 22nd Mar 2024
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MVSAT 2024

Karnataka CET Question Paper - Year 2013

All About the KCET Exam

  • KCET exam is held for students who aspire to pursue courses like engineering, pharmacy, architecture, etc. from the government or private institutions of Karnataka. There are over 200 colleges that accept the KCET scores.

  • The question paper for each subject in PCB/PCM is in 16 different versions from A to H, where each MCQ has four alternatives. One mark is rewarded for a correct response and zero for wrong/multiple responses.

  • As per the KCET 2020 analysis, the difficulty level of the paper was easy to moderate. The percentage of 2nd PUC topics were more in the KCET 2020 exam. It cannot be predicted what may come in the upcoming exam.

  • At Vedantu, we promise you to provide an excellent platform for KCET preparation. Your aim for scoring high in the KCET exam is ours now. So, leave your worries aside and kickstart your KCET preparation with our highly qualified subject matter experts.

On-the-Go KCET Preparation with Vedantu

  • For your ease, our experts have provided solutions to all the KCET 2013 Question Papers.

  • Our subject matter experts have been mentoring millions of candidates in various entrance exams. Adjusting their teaching style according to the understanding of the students, they have prepared concise solutions to KCET Question Papers 2013. Please go through them.

KCET 2013 Maths Question Paper

A solved Sample of KCET 2013 Maths Paper is provided below.


Q1: What will be the remainder when 1010 . (1010+1) . (1010+2) is divided by 6?

Options: 

  1. 2

  2. 4

  3. 6

  4. 0

Objective Answer: (d)


Solution: Starting with 1010

Rem \[(\frac{10^{10}}{6}) = 4^{10}\]

\[\Rightarrow Rem  \frac{10^{10} . (10^{10} + 1) . (10^{10} + 2)}{6} = Rem (\frac{4^{10} \times (4^{10} + 1) \times (4^{10} + 2)}{6})\]

Now, looking at the cyclicity of \[\frac{4^{n}}{6}\]:

Rem \[(\frac{4^{1}}{6})\] = Rem \[(\frac{4^{2}}{6})\] =.....= Rem \[(\frac{4^{n}}{6})\] = 1

So, \[Rem (\frac{4^{10} \times (4^{10} + 1) \times (4^{10} + 2)}{6}) = Rem (\frac{1 \times (1 + 1) \times (1 + 2)}{6}) = Rem (\frac{6}{6}) = 0\]


Q2: A regular graph has 15 vertices, and the sum of their degree is 60. Find the degree of each vertex.

  1. 5

  2. 4

  3. 2

  4. 3

Objective Answer: (b)


Solution: We are given with no of vertices, V = 15, and Sum (S) = 60

Let the degree of each vertex = x

So, V *  x = S 15 * x = 60

Or, x = 4


KCET 2013 Physics Question Paper

Sample Solved KCET 2013 Physics Paper is provided below.


Q1: If radii of curvature of a converging lens are in the ratio of 1: 2, and its focal length is 6 cm, and the refractive index is 1.5, then find the radii of curvature.

  1. 9 and 18 cm

  2. 6 and 12 cm

  3. 3 and 6 cm

  4. 4.5 and 9 cm

Objective Answer: (d)


Q2: Which among the following is made by quarks? 

  1. Neutron

  2. Positron

  3. Proton

  4. n-meson

Objective Answer: (b)


KCET 2013 Chemistry Question Paper

Sample Solved KCET 2013 Chemistry Paper is provided below.


Q1: Which reagent used to distinguish between aldehyde and benzaldehyde?

  1. Tollen’s reagent

  2. Semicarbazide

  3. Fehling’s Solution

  4. 2,4-dinitrophenyl hydrazine

Objective Answer: (d): 2,4-dinitrophenyl hydrazine


Q2: What is the number of antibonding electrons present in O2- molecular ions?

  1. 8

  2. 5

  3. 4

  4. 6

Objective Answer: (b)


KCET 2013 Biology Question Paper

Sample Solved KCET 2013 Biology Paper is provided below.


Q1: What taxonomic term can be suggested for any rank in the classification?

  1. Class

  2. Order

  3. Species

  4. Taxon

Objective Answer: (d)


Q2: What is Tikka?

  1. A Fungal Disease

  2. A Protozoan Disease

  3. A Viral Disease

  4. A Bacterial Disease

Objective Answer: (a)


Salient Features of Vedantu’s Solved KCET PYQP

Key features are as follows:

  • Solutions to all papers, i.e. Physics, Chemistry, Maths and Biology are available in a single window.

  • Solutions to all papers are explained in a simple and logical manner and are available 24/7 for free.

  • Model Papers are available for each topic. Solving them will help you brush your concepts.

  • Repetitive questions are highlighted so that candidates become familiar with the type of questions asked in the past years.

  • Candidates can consult our doubt experts for their queries.

  • Mocks are available for helping a candidate track the time they take on each attempt. 

  • They can also view the solution to each question after submitting the mock test. After the submission, they will be able to see the strengths and weaknesses of particular topics.

  • Candidates can also watch video tutorials for free and clear all their doubts from our master teachers.

FAQs on KCET 2013 Previous Year Question Paper for Maths, Physics, Chemistry & Biology

Q1: Which among the following is the most unstable RNA?

  1. Messenger RNA

  2. Heterogeneous Nuclear RNA

  3. Ribosomal RNA

  4. Soluble RNA

Answer: OA: (a) Messenger RNA is the most soluble RNA.

Q2: Determine at which combination of working temperatures of the source and sink, the efficiency of Carnot’s engine is maximum.

  1. 600 K, 500 K

  2. 300 K, 100 K

  3. 500 K, 300 K

  4. 400 K, 200 K

Answer: OA: (b) At the combination of 300 K, 100 K,  the efficiency of Carnot’s engine is maximum.

Q3: Is KCET Applicable for Pursuing MBBS?

Answer: KCET or Karnataka CET Medical exam is the common entrance examination that opens the doors for taking admission into the government/private medical and dental colleges of Karnataka.

Q4: How Can I Score 170+ in the KCET Exam?

Answer: Following are the tips for scoring 170+ in the KCET Exam:

  1. Go through the updated KCET syllabus.

  2. Search for the topics with high weightage and mark them as important.

  3. Build your concepts, and then start practising the numerical based on the same.

  4. Devote equal time to each subject and on the language-based test preparation as well.

  5. Practice sample papers for keeping yourself updated with the difficulty level of questions.

  6. Revise all the topics before exams.