Answer
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Hint: When no current flows through the coil or, the potential difference across the galvanometer is zero the bridge is said to be in a balanced condition.
Complete answer:
The Meter bridge is the modification of Wheatstone’s network used to determine the value of unknown resistance.
The meter bridge consists of a thin, uniform, and homogenous conducting wire AC, rectangular wooden board between two thick L shaped metal strips C1 and C2 as shown in the diagram.
In the diagram AC- conducting wire
C1, C2, and C3- metal strips
E- cell
X- unknown resistance
R- resistance box
D- null point
K’- jockey
G- galvanometer
Rh- rheostat
To determine the unknown resistance, the circuit is connected as shown in the diagram. The unknown resistance X is connected in one gap (left gap) and a resistance box (known variable resistor) is connected in another gap (right gap).
A cell of emf E, key K, and rheostat Rh are connected to junction B of X and R also other terminal connected to the jockey.
The jockey is placed at points A and C and the deflection is checked in the galvanometer. This deflection must be on opposite sides otherwise rheostat and the value of resistance from the resistance box should be adjusted.
A suitable value of resistance R is taken in the resistance box and by touching the jockey at different points of the wire AC, a point D is obtained for which the galvanometer shows zero deflection, point D is called the null point.
Let $l_x$ and $l_y$ be the distances of the null point D (balancing lengths) measured in centimeters from end A and C of the wire AC respectively and σ be the resistance per unit length of wire AC.
Here X, R, and resistances of wire AD and wire CD from arms of Wheatstone’s network.
Therefore from balancing condition,
\[ \Rightarrow \dfrac{{\text{X}}}{{\text{R}}} = \dfrac{{{\text{Resistance of wire AD}}}}{{{\text{Resistance of wire CD}}}}\]
\[\Rightarrow \dfrac{{\text{X}}}{{\text{R}}} = \dfrac{{\sigma {l_X}}}{{\sigma {l_y}}} = \dfrac{{{l_X}}}{{{l_y}}}\]
\[ \Rightarrow {\text{X = R}}\left( {\dfrac{{{l_X}}}{{{l_y}}}} \right)\]
\[ \Rightarrow {\text{X = R}}\left( {\dfrac{{{l_X}}}{{100 - {l_x}}}} \right)\]
$\therefore$ Hence the unknown resistance X can be determined by using the formula \[{\text{X = R}}\left( {\dfrac{{{l_X}}}{{100 - {l_x}}}} \right)\].
Note:
Slide wire is known as a meter bridge. The meter bridge is an instrument that works on the principle of the Wheatstone bridge. A meter bridge is also a simple type of the potentiometer that is used to measure the resistance and it is being used in the school laboratories.
Complete answer:
The Meter bridge is the modification of Wheatstone’s network used to determine the value of unknown resistance.
The meter bridge consists of a thin, uniform, and homogenous conducting wire AC, rectangular wooden board between two thick L shaped metal strips C1 and C2 as shown in the diagram.
![seo images](https://www.vedantu.com/question-sets/09b5a115-9c0b-4038-b470-b1e428f88be87913504674299048097.png)
In the diagram AC- conducting wire
C1, C2, and C3- metal strips
E- cell
X- unknown resistance
R- resistance box
D- null point
K’- jockey
G- galvanometer
Rh- rheostat
To determine the unknown resistance, the circuit is connected as shown in the diagram. The unknown resistance X is connected in one gap (left gap) and a resistance box (known variable resistor) is connected in another gap (right gap).
A cell of emf E, key K, and rheostat Rh are connected to junction B of X and R also other terminal connected to the jockey.
The jockey is placed at points A and C and the deflection is checked in the galvanometer. This deflection must be on opposite sides otherwise rheostat and the value of resistance from the resistance box should be adjusted.
A suitable value of resistance R is taken in the resistance box and by touching the jockey at different points of the wire AC, a point D is obtained for which the galvanometer shows zero deflection, point D is called the null point.
Let $l_x$ and $l_y$ be the distances of the null point D (balancing lengths) measured in centimeters from end A and C of the wire AC respectively and σ be the resistance per unit length of wire AC.
Here X, R, and resistances of wire AD and wire CD from arms of Wheatstone’s network.
Therefore from balancing condition,
\[ \Rightarrow \dfrac{{\text{X}}}{{\text{R}}} = \dfrac{{{\text{Resistance of wire AD}}}}{{{\text{Resistance of wire CD}}}}\]
\[\Rightarrow \dfrac{{\text{X}}}{{\text{R}}} = \dfrac{{\sigma {l_X}}}{{\sigma {l_y}}} = \dfrac{{{l_X}}}{{{l_y}}}\]
\[ \Rightarrow {\text{X = R}}\left( {\dfrac{{{l_X}}}{{{l_y}}}} \right)\]
\[ \Rightarrow {\text{X = R}}\left( {\dfrac{{{l_X}}}{{100 - {l_x}}}} \right)\]
$\therefore$ Hence the unknown resistance X can be determined by using the formula \[{\text{X = R}}\left( {\dfrac{{{l_X}}}{{100 - {l_x}}}} \right)\].
Note:
Slide wire is known as a meter bridge. The meter bridge is an instrument that works on the principle of the Wheatstone bridge. A meter bridge is also a simple type of the potentiometer that is used to measure the resistance and it is being used in the school laboratories.
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